简单快捷的解决方案。

我只要滚动到右边的单元格

    - (void)scrollViewDidScroll:(UIScrollView *)scrollView 

假设我知道表现在处于这个模式_keepMyCellOnTop &我知道选定单元格“_selectedCellIndex”或滚动到选定单元格

- (void)scrollViewDidScroll:(UIScrollView *)scrollView 
{

    if (_keepMyCellOnTop)
    {
        [self.tableView scrollToRowAtIndexPath:_selectedCellIndex atScrollPosition:UITableViewScrollPositionTop animated:NO];
    }
}

这将防止滚动。

将代码放在-(void) scrollViewDidEndScrollingAnimation:(UIScrollView *)scrollView中 结果是上下滚动吗

我认为没有“正确”的方法来做这件事。您必须为您的用例选择最合适的解决方案。 在我的iPad App中，我有一个UIViewController，它以UIModalPresentationFormSheet的形式呈现，由一个UITableView组成。这个表格每个单元格包含两个UITextFields。 只是调用scrollToRowAtIndexPath:atScrollPosition:animated:在textFieldDidBeginEditing:方法不为我工作。因此，我创建了一个tableFooterView:

- (void)viewDidLoad
{
    [super viewDidLoad];

    m_footerView = [[UIView alloc] initWithFrame:CGRectMake(0.0f, 0.0f, m_tableView.frame.size.width, 300.0f)];
    [m_footerView setBackgroundColor:[UIColor clearColor]];
    [m_tableView setTableFooterView:m_footerView];
    [m_footerView release];
}

这个想法是键盘隐藏tableFooterView而不是UITextFields。tableFooterView必须足够高。之后，你可以在textFieldDidBeginEditing:方法中使用scrollToRowAtIndexPath:atScrollPosition:animated:。

我认为也可以通过添加键盘通知的观察者来动态地显示和隐藏tableFooterView，但我还没有尝试过:

- (void)viewWillAppear:(BOOL)animated
{
    [super viewWillAppear:animated];

    [[NSNotificationCenter defaultCenter] addObserver:self 
                                             selector:@selector(keyboardWillShow:) 
                                                 name:UIKeyboardWillShowNotification 
                                               object:nil];
    [[NSNotificationCenter defaultCenter] addObserver:self 
                                             selector:@selector(keyboardWillHide:) 
                                                 name:UIKeyboardWillHideNotification 
                                               object:nil];
}

- (void)keyboardWillShow:(NSNotification *)notification 
{
     [m_tableView setTableFooterView:m_footerView];
}

- (void)keyboardWillHide:(NSNotification *)notification 
{
     [m_tableView setTableFooterView:nil];
}

- (void)viewWillDisappear:(BOOL)animated
{
    [super viewWillDisappear:animated];

    [[NSNotificationCenter defaultCenter] removeObserver:self name:UIKeyboardWillShowNotification object:nil];
    [[NSNotificationCenter defaultCenter] removeObserver:self name:UIKeyboardWillHideNotification object:nil];
}

Swift最简单的解决方案:

override func viewDidLoad() {
    super.viewDidLoad()
    
    searchBar?.becomeFirstResponder()
    NSNotificationCenter.defaultCenter().addObserver(self, selector: #selector(MyViewController.keyboardWillShow(_:)), name: UIKeyboardDidShowNotification, object: nil)
    NSNotificationCenter.defaultCenter().addObserver(self, selector: #selector(MyViewController.keyboardWillHide(_:)), name: UIKeyboardDidHideNotification, object: nil)
}

deinit {
    NSNotificationCenter.defaultCenter().removeObserver(self)
}

func keyboardWillShow(notification: NSNotification) {
    if let userInfo = notification.userInfo {
        if let keyboardHeight = userInfo[UIKeyboardFrameEndUserInfoKey]?.CGRectValue.size.height {
            tableView.contentInset = UIEdgeInsetsMake(0, 0, keyboardHeight, 0)
        }
    }
}

func keyboardWillHide(notification: NSNotification) {
    UIView.animateWithDuration(0.2, animations: { self.table_create_issue.contentInset = UIEdgeInsetsMake(0, 0, 0, 0) })
    // For some reason adding inset in keyboardWillShow is animated by itself but removing is not, that's why we have to use animateWithDuration here
    }

Swift 4.2或更高版本

override func viewDidLoad() {
    super.viewDidLoad()
    searchBar?.becomeFirstResponder()
    NotificationCenter.default.addObserver(self, selector: #selector(self.keyboardWillShow), name: UIResponder.keyboardDidShowNotification, object: nil)
    NotificationCenter.default.addObserver(self, selector: #selector(self.keyboardWillHide), name: UIResponder.keyboardDidHideNotification, object: nil)
}

deinit {
    NotificationCenter.default.removeObserver(self)
}

 @objc func keyboardWillShow(notification: NSNotification) {
    if let userInfo = notification.userInfo {
            let keyboardHeight = (userInfo[UIResponder.keyboardFrameEndUserInfoKey] as AnyObject).cgRectValue.size.height
            accountSettingsTableView.contentInset = UIEdgeInsets(top: 0, left: 0, bottom: keyboardHeight, right: 0)
        
    }
}
@objc func keyboardWillHide(notification: NSNotification) {
    UIView.animate(withDuration: 0.2, animations: { self.accountSettingsTableView.contentInset = UIEdgeInsets(top: 0, left: 0, bottom: 0, right: 0) })}
}

我刚刚解决了这样一个问题，我参考了大量的解决方案通过谷歌和堆栈溢出。

首先，请确保你已经为UIScrollView设置了IBOutlet， 那么请仔细看看Apple Doc: Keyboard Management。 最后，如果你可以滚动背景，但键盘仍然覆盖文本字段，请看看这段代码:

// If active text field is hidden by keyboard, scroll it so it's visible
// Your application might not need or want this behavior.
CGRect aRect = self.view.frame;
aRect.size.height -= kbSize.height;

if (aRect.size.height < activeField.frame.origin.y+activeField.frame.size.height) {

    CGPoint scrollPoint = CGPointMake(0.0, activeField.frame.origin.y+activeField.frame.size.height-aRect.size.height);

    [scrollView setContentOffset:scrollPoint animated:YES];

这款游戏与苹果游戏的主要区别在于if条件。我认为apple计算滚动距离和键盘是否覆盖文本字段的条件不准确，所以我做了如上修改。

如果有用请告诉我

我尝试了几乎相同的方法，并提出了一个更简单、更小的代码。 我创建了一个IBOutlet iTextView，并与IB中的UITextView相关联。

 -(void)keyboardWillShow:(NSNotification *)notification
    {
        NSLog(@"Keyboard");
        CGRect keyFrame = [[[notification userInfo]objectForKey:UIKeyboardFrameEndUserInfoKey]CGRectValue];

        [UIView beginAnimations:@"resize view" context:nil];
        [UIView setAnimationCurve:1];
        [UIView setAnimationDuration:1.0];
        CGRect frame = iTableView.frame;
        frame.size.height = frame.size.height -  keyFrame.size.height;
        iTableView.frame = frame;
        [iTableView scrollRectToVisible:frame animated:YES];
        [UIView commitAnimations];

    }

Swift 4.2的小变化…

在我的UITableView上，我有很多部分，但我必须避免浮动标题效果，所以我使用了“dummyViewHeight”方法，就像在Stack Overflow上看到的其他地方一样… 这就是我对这个问题的解决方案(它也适用于键盘+工具栏+建议):

将其声明为类常量:

let dummyViewHeight: CGFloat = 40.0

Then

override func viewDidLoad() {
    super.viewDidLoad()
    //... some stuff here, not needed for this example

    // Create non floating header
    tableView.tableHeaderView = UIView(frame: CGRect(x: 0, y: 0, width: tableView.bounds.size.width, height: dummyViewHeight))
    tableView.contentInset = UIEdgeInsets(top: -dummyViewHeight, left: 0, bottom: 0, right: 0)

    addObservers()
}

override func viewWillDisappear(_ animated: Bool) {
    super.viewWillDisappear(animated)
    removeObservers()
}

这里所有的魔法……

@objc func keyboardWillShow(notification: NSNotification) {
    if let userInfo = notification.userInfo {
        let keyboardHeight = (userInfo[UIResponder.keyboardFrameEndUserInfoKey] as AnyObject).cgRectValue.size.height
        tableView.tableHeaderView = UIView(frame: CGRect(x: 0, y: 0, width: self.tableView.bounds.size.width, height: dummyViewHeight))
        tableView.contentInset = UIEdgeInsets(top: -dummyViewHeight, left: 0, bottom: keyboardHeight, right: 0)
    }
}

@objc func keyboardWillHide(notification: NSNotification) {
    UIView.animate(withDuration: 0.25) {
        self.tableView.tableHeaderView = UIView(frame: CGRect(x: 0, y: 0, width: self.tableView.bounds.size.width, height: self.dummyViewHeight))
        self.tableView.contentInset = UIEdgeInsets(top: -self.dummyViewHeight, left: 0, bottom: 0, right: 0)
    }
}