如何使用javascript正则表达式将字符串转换为驼峰大小写?

设备类名称或 设备类名或设备类名或设备类名

应该全部变成:equipmentClassName。


当前回答

去找骆驼凯斯

ES5

var camalize = function camalize(str) {
    return str.toLowerCase().replace(/[^a-zA-Z0-9]+(.)/g, function(match, chr)
    {
        return chr.toUpperCase();
    });
}

ES6

var camalize = function camalize(str) {
    return str.toLowerCase().replace(/[^a-zA-Z0-9]+(.)/g, (m, chr) => chr.toUpperCase());
}

> To get ***C**amel**S**entence**C**ase* or ***P**ascal**C**ase*
var camelSentence = function camelSentence(str) {
    return  (" " + str).toLowerCase().replace(/[^a-zA-Z0-9]+(.)/g, function(match, chr)
    {
        return chr.toUpperCase();
    });
}

注意: 对于那些有口音的语言。是否包括如下的正则表达式À-ÖØ-öø- ux .replace (/ [^ a-zA-ZA-OØ- oø-y0-9) + () / g,这只是一种语言。对于另一种语言,你必须搜索和发现

其他回答

这就是我的解决方案:

const toCamelWord = (word, idx) => Idx === 0 ? word.toLowerCase (): word.charAt(0).toUpperCase() + word.slice(1).toLowerCase(); const toCamelCase = text => 文本 .split (/ [_ - \] + /) . map (toCamelWord) . join (" "); console.log (toCamelCase(用户ID))

您可以使用以下解决方案:

String.prototype.toCamelCase = function(){ return this.replace(/\s(\w)/ig, function(all, letter){return letter. touppercase ();}) .replace (/ (^ \ w)、功能(1美元){返回1.美元tolowercase ()}); }; console.log(“设备名称”.toCamelCase ());

为了有效地创建一个将字符串的大小写转换为驼峰式大小写的函数,该函数还需要首先将每个字符串转换为小写,然后再将非第一个字符串的第一个字符转换为大写字母。

我的示例字符串是:

"text That I WaNt to make cAMEL case"

对于这个问题提供的许多其他解决方案返回这个:

"textThatIWaNtToMakeCAMELCase"

我认为应该是预期的,期望的输出将是这样的,其中所有的中间字符串大写字符首先转换为小写:

"textThatIWanrtToMakeCamelCase"

这可以在不使用任何replace()方法调用的情况下完成,通过使用String.prototype.split(), Array.prototype.map()和Array.prototype.join()方法:

≤ES5版本

function makeCamelCase(str) {
  return str
    .split(' ')
    .map((e,i) => i
      ? e.charAt(0).toUpperCase() + e.slice(1).toLowerCase()
      : e.toLowerCase()
    )
    .join('')
}

makeCamelCase("text That I WaNt to make cAMEL case")
// -> "textThatIWanrtToMakeCamelCase" ✅

我将分解每一行的功能,然后以其他两种格式提供相同的解决方案——ES6格式和字符串格式。prototype方法,不过我建议不要像这样直接扩展内置的JavaScript原型。

讲解员

function makeCamelCase(str) {
  return str
    // split string into array of different words by splitting at spaces
    .split(' ')
    // map array of words into two different cases, one for the first word (`i == false`) and one for all other words in the array (where `i == true`). `i` is a parameter that denotes the current index of the array item being evaluated. Because indexes start at `0` and `0` is a "falsy" value, we can use the false/else case of this ternary expression to match the first string where `i === 0`.
    .map((e,i) => i
      // for all non-first words, use a capitalized form of the first character + the lowercase version of the rest of the word (excluding the first character using the slice() method)
      ? e.charAt(0).toUpperCase() + e.slice(1).toLowerCase()
      // for the first word, we convert the entire word to lowercase
      : e.toLowerCase()
    )
    // finally, we join the different strings back together into a single string without spaces, our camel-cased string
    .join('')
}

makeCamelCase("text That I WaNt to make cAMEL case")
// -> "textThatIWanrtToMakeCamelCase" ✅

压缩ES6+(一行程序)版本

const makeCamelCase = str => str.split(' ').map((e,i) => i ? e.charAt(0).toUpperCase() + e.slice(1).toLowerCase() : e.toLowerCase()).join('')

makeCamelCase("text That I WaNt to make cAMEL case")
// -> "textThatIWanrtToMakeCamelCase" ✅

字符串。原型方法版本

String.prototype.toCamelCase = function() {
  return this
    .split(' ')
    .map((e,i) => i
      ? e.charAt(0).toUpperCase() + e.slice(1).toLowerCase()
      : e.toLowerCase()
    )
    .join('')
}

"text That I WaNt to make cAMEL case".toCamelCase()
// -> "textThatIWanrtToMakeCamelCase" ✅

我想出了这个内衬,它也适用于烤肉盒到骆驼盒:

string.replace(/^(.)|[\s-](.)/g,
                (match) =>
                    match[1] !== undefined
                        ? match[1].toUpperCase()
                        : match[0].toUpperCase()
            )

可靠的高性能示例:

function camelize(text) {
    const a = text.toLowerCase()
        .replace(/[-_\s.]+(.)?/g, (_, c) => c ? c.toUpperCase() : '');
    return a.substring(0, 1).toLowerCase() + a.substring(1);
}

情况下,修改字符:

连字符- 下划线_ 时期。 空间