你可以使用旧的Stupid Scanner技巧在线程序来做到这一点，而不需要任何额外的依赖，如番石榴:

String text = new Scanner(AppropriateClass.class.getResourceAsStream("foo.txt"), "UTF-8").useDelimiter("\\A").next();

伙计们，除非你真的需要，否则不要用第三方的东西。JDK中已经有很多功能了。

package test;

import java.io.InputStream;
import java.nio.charset.StandardCharsets;
import java.util.Scanner;

public class Main {
    public static void main(String[] args) {
        try {
            String fileContent = getFileFromResources("resourcesFile.txt");
            System.out.println(fileContent);
        } catch (Exception e) {
            e.printStackTrace();
        }
    }

    //USE THIS FUNCTION TO READ CONTENT OF A FILE, IT MUST EXIST IN "RESOURCES" FOLDER
    public static String getFileFromResources(String fileName) throws Exception {
        ClassLoader classLoader = Main.class.getClassLoader();
        InputStream stream = classLoader.getResourceAsStream(fileName);
        String text = null;
        try (Scanner scanner = new Scanner(stream, StandardCharsets.UTF_8.name())) {
            text = scanner.useDelimiter("\\A").next();
        }
        return text;
    }
}

下面是一个使用Java 11的Files.readString的解决方案:

public class Utils {
    public static String readResource(String name) throws URISyntaxException, IOException {
        var uri = Utils.class.getResource("/" + name).toURI();
        var path = Paths.get(uri);
        return Files.readString(path);
    }
}

我使用以下从类路径读取资源文件:

import java.io.IOException;
import java.io.InputStream;
import java.net.URISyntaxException;
import java.util.Scanner;

public class ResourceUtilities
{
    public static String resourceToString(String filePath) throws IOException, URISyntaxException
    {
        try (InputStream inputStream = ResourceUtilities.class.getClassLoader().getResourceAsStream(filePath))
        {
            return inputStreamToString(inputStream);
        }
    }

    private static String inputStreamToString(InputStream inputStream)
    {
        try (Scanner scanner = new Scanner(inputStream).useDelimiter("\\A"))
        {
            return scanner.hasNext() ? scanner.next() : "";
        }
    }
}

不需要第三方依赖。

public static byte[] readResoureStream(String resourcePath) throws IOException {
    ByteArrayOutputStream byteArray = new ByteArrayOutputStream();
    InputStream in = CreateBffFile.class.getResourceAsStream(resourcePath);

    //Create buffer
    byte[] buffer = new byte[4096];
    for (;;) {
        int nread = in.read(buffer);
        if (nread <= 0) {
            break;
        }
        byteArray.write(buffer, 0, nread);
    }
    return byteArray.toByteArray();
}

Charset charset = StandardCharsets.UTF_8;
String content = new   String(FileReader.readResoureStream("/resource/...*.txt"), charset);
String lines[] = content.split("\\n");

yegor256用Apache Commons IO找到了一个很好的解决方案:

import org.apache.commons.io.IOUtils;

String text = IOUtils.toString(this.getClass().getResourceAsStream("foo.xml"),
                               "UTF-8");