假设我有这样的伪代码:
bool conditionA = executeStepA();
if (conditionA){
bool conditionB = executeStepB();
if (conditionB){
bool conditionC = executeStepC();
if (conditionC){
...
}
}
}
executeThisFunctionInAnyCase();
函数executeStepX当且仅当前一个成功时执行。
在任何情况下，executeThisFunctionInAnyCase函数都应该在最后被调用。
我在编程方面是一个新手，所以很抱歉提出一个非常基本的问题:有没有一种方法(例如在C/ c++中)以代码易读性为代价，避免长if链产生那种“金字塔式代码”?
我知道如果我们可以跳过executeThisFunctionInAnyCase函数调用，代码可以简化为:
bool conditionA = executeStepA();
if (!conditionA) return;
bool conditionB = executeStepB();
if (!conditionB) return;
bool conditionC = executeStepC();
if (!conditionC) return;
但是约束是executeThisFunctionInAnyCase函数调用。
break语句可以以某种方式使用吗?
如果条件被移动到单独的步骤下，条件可以被简化，这是一个c#伪代码，
其思想是使用编排而不是中央编排。
void Main()
{
Request request = new Request();
Response response = null;
// enlist all the processors
var processors = new List<IProcessor>() {new StepA() };
var factory = new ProcessorFactory(processors);
// execute as a choreography rather as a central orchestration.
var processor = factory.Get(request, response);
while (processor != null)
{
processor.Handle(request, out response);
processor = factory.Get(request, response);
}
// final result...
//response
}
public class Request
{
}
public class Response
{
}
public interface IProcessor
{
bool CanProcess(Request request, Response response);
bool Handle(Request request, out Response response);
}
public interface IProcessorFactory
{
IProcessor Get(Request request, Response response);
}
public class ProcessorFactory : IProcessorFactory
{
private readonly IEnumerable<IProcessor> processors;
public ProcessorFactory(IEnumerable<IProcessor> processors)
{
this.processors = processors;
}
public IProcessor Get(Request request, Response response)
{
// this is an iterator
var matchingProcessors = processors.Where(x => x.CanProcess(request, response)).ToArray();
if (!matchingProcessors.Any())
{
return null;
}
return matchingProcessors[0];
}
}
// Individual request processors, you will have many of these...
public class StepA: IProcessor
{
public bool CanProcess(Request request, Response response)
{
// Validate wether this can be processed -- if condition here
return false;
}
public bool Handle(Request request, out Response response)
{
response = null;
return false;
}
}
如果条件被移动到单独的步骤下，条件可以被简化，这是一个c#伪代码，
其思想是使用编排而不是中央编排。
void Main()
{
Request request = new Request();
Response response = null;
// enlist all the processors
var processors = new List<IProcessor>() {new StepA() };
var factory = new ProcessorFactory(processors);
// execute as a choreography rather as a central orchestration.
var processor = factory.Get(request, response);
while (processor != null)
{
processor.Handle(request, out response);
processor = factory.Get(request, response);
}
// final result...
//response
}
public class Request
{
}
public class Response
{
}
public interface IProcessor
{
bool CanProcess(Request request, Response response);
bool Handle(Request request, out Response response);
}
public interface IProcessorFactory
{
IProcessor Get(Request request, Response response);
}
public class ProcessorFactory : IProcessorFactory
{
private readonly IEnumerable<IProcessor> processors;
public ProcessorFactory(IEnumerable<IProcessor> processors)
{
this.processors = processors;
}
public IProcessor Get(Request request, Response response)
{
// this is an iterator
var matchingProcessors = processors.Where(x => x.CanProcess(request, response)).ToArray();
if (!matchingProcessors.Any())
{
return null;
}
return matchingProcessors[0];
}
}
// Individual request processors, you will have many of these...
public class StepA: IProcessor
{
public bool CanProcess(Request request, Response response)
{
// Validate wether this can be processed -- if condition here
return false;
}
public bool Handle(Request request, out Response response)
{
response = null;
return false;
}
}
你也可以这样做:
bool isOk = true;
std::vector<bool (*)(void)> funcs; //vector of function ptr
funcs.push_back(&executeStepA);
funcs.push_back(&executeStepB);
funcs.push_back(&executeStepC);
//...
//this will stop at the first false return
for (auto it = funcs.begin(); it != funcs.end() && isOk; ++it)
isOk = (*it)();
if (isOk)
//doSomeStuff
executeThisFunctionInAnyCase();
通过这种方式，您可以获得最小的线性增长大小，每次调用+1行，并且易于维护。
编辑:(谢谢@Unda)我不太喜欢，因为在我看来你失去了能见度:
bool isOk = true;
auto funcs { //using c++11 initializer_list
&executeStepA,
&executeStepB,
&executeStepC
};
for (auto it = funcs.begin(); it != funcs.end() && isOk; ++it)
isOk = (*it)();
if (isOk)
//doSomeStuff
executeThisFunctionInAnyCase();
