我有一个复杂的json文件,我必须处理javascript使其分层,以便稍后构建树。 json的每个条目都有: Id:唯一的Id, parentId:父节点的id(如果节点是树的根,则为0) Level:树的深度级别

json数据已经“有序”。我的意思是,一个条目在它上面有一个父节点或兄弟节点,在它下面有一个子节点或兄弟节点。

输入:

{
    "People": [
        {
            "id": "12",
            "parentId": "0",
            "text": "Man",
            "level": "1",
            "children": null
        },
        {
            "id": "6",
            "parentId": "12",
            "text": "Boy",
            "level": "2",
            "children": null
        },
                {
            "id": "7",
            "parentId": "12",
            "text": "Other",
            "level": "2",
            "children": null
        },
        {
            "id": "9",
            "parentId": "0",
            "text": "Woman",
            "level": "1",
            "children": null
        },
        {
            "id": "11",
            "parentId": "9",
            "text": "Girl",
            "level": "2",
            "children": null
        }
    ],
    "Animals": [
        {
            "id": "5",
            "parentId": "0",
            "text": "Dog",
            "level": "1",
            "children": null
        },
        {
            "id": "8",
            "parentId": "5",
            "text": "Puppy",
            "level": "2",
            "children": null
        },
        {
            "id": "10",
            "parentId": "13",
            "text": "Cat",
            "level": "1",
            "children": null
        },
        {
            "id": "14",
            "parentId": "13",
            "text": "Kitten",
            "level": "2",
            "children": null
        },
    ]
}

预期产量:

{
    "People": [
        {
            "id": "12",
            "parentId": "0",
            "text": "Man",
            "level": "1",
            "children": [
                {
                    "id": "6",
                    "parentId": "12",
                    "text": "Boy",
                    "level": "2",
                    "children": null
                },
                {
                    "id": "7",
                    "parentId": "12",
                    "text": "Other",
                    "level": "2",
                    "children": null
                }   
            ]
        },
        {
            "id": "9",
            "parentId": "0",
            "text": "Woman",
            "level": "1",
            "children":
            {

                "id": "11",
                "parentId": "9",
                "text": "Girl",
                "level": "2",
                "children": null
            }
        }

    ],    

    "Animals": [
        {
            "id": "5",
            "parentId": "0",
            "text": "Dog",
            "level": "1",
            "children": 
                {
                    "id": "8",
                    "parentId": "5",
                    "text": "Puppy",
                    "level": "2",
                    "children": null
                }
        },
        {
            "id": "10",
            "parentId": "13",
            "text": "Cat",
            "level": "1",
            "children": 
            {
                "id": "14",
                "parentId": "13",
                "text": "Kitten",
                "level": "2",
                "children": null
            }
        }

    ]
}

当前回答

这是一个旧线程,但我认为更新永远不会伤害,与ES6你可以做到:

const data = [{ id: 1, parent_id: 0 }, { id: 2, parent_id: 1 }, { id: 3, parent_id: 1 }, { id: 4, parent_id: 2 }, { id: 5, parent_id: 4 }, { id: 8, parent_id: 7 }, { id: 9, parent_id: 8 }, { id: 10, parent_id: 9 }]; const arrayToTree = (items=[], id = null, link = 'parent_id') => items.filter(item => id==null ? !items.some(ele=>ele.id===item[link]) : item[link] === id ).map(item => ({ ...item, children: arrayToTree(items, item.id) })) const temp1=arrayToTree(data) console.log(temp1) const treeToArray = (items=[], key = 'children') => items.reduce((acc, curr) => [...acc, ...treeToArray(curr[key])].map(({ [`${key}`]: child, ...ele }) => ele), items); const temp2=treeToArray(temp1) console.log(temp2)

希望它能帮助到别人

其他回答

使用ES6方法。工作很有魅力

//数据集 //一个顶级注释 Const注释= [{ id: 1、 parent_id:零 }, { id: 2 parent_id: 1 }, { id: 3, parent_id: 1 }, { id: 4 parent_id: 2 }, { id: 5 parent_id: 4 }); Const nest = (items, id = null, link = 'parent_id') => 项目 .filter(item => item[link] === id) .map(item =>({…Item, children: nest(items, Item .id)})); console.log ( 巢(评论) )

下面是Steven Harris的一个修改版本,它是普通的ES5,返回一个以id为键的对象,而不是返回顶层和子层的节点数组。

unflattenToObject = function(array, parent) {
  var tree = {};
  parent = typeof parent !== 'undefined' ? parent : {id: 0};

  var childrenArray = array.filter(function(child) {
    return child.parentid == parent.id;
  });

  if (childrenArray.length > 0) {
    var childrenObject = {};
    // Transform children into a hash/object keyed on token
    childrenArray.forEach(function(child) {
      childrenObject[child.id] = child;
    });
    if (parent.id == 0) {
      tree = childrenObject;
    } else {
      parent['children'] = childrenObject;
    }
    childrenArray.forEach(function(child) {
      unflattenToObject(array, child);
    })
  }

  return tree;
};

var arr = [
    {'id':1 ,'parentid': 0},
    {'id':2 ,'parentid': 1},
    {'id':3 ,'parentid': 1},
    {'id':4 ,'parentid': 2},
    {'id':5 ,'parentid': 0},
    {'id':6 ,'parentid': 0},
    {'id':7 ,'parentid': 4}
];
tree = unflattenToObject(arr);

这是一个旧线程,但我认为更新永远不会伤害,与ES6你可以做到:

const data = [{ id: 1, parent_id: 0 }, { id: 2, parent_id: 1 }, { id: 3, parent_id: 1 }, { id: 4, parent_id: 2 }, { id: 5, parent_id: 4 }, { id: 8, parent_id: 7 }, { id: 9, parent_id: 8 }, { id: 10, parent_id: 9 }]; const arrayToTree = (items=[], id = null, link = 'parent_id') => items.filter(item => id==null ? !items.some(ele=>ele.id===item[link]) : item[link] === id ).map(item => ({ ...item, children: arrayToTree(items, item.id) })) const temp1=arrayToTree(data) console.log(temp1) const treeToArray = (items=[], key = 'children') => items.reduce((acc, curr) => [...acc, ...treeToArray(curr[key])].map(({ [`${key}`]: child, ...ele }) => ele), items); const temp2=treeToArray(temp1) console.log(temp2)

希望它能帮助到别人

你可以使用npm包数组到树https://github.com/alferov/array-to-tree。 它将普通的节点数组(带有指向父节点的指针)转换为嵌套的数据结构。

解决了从数据库数据集检索到嵌套数据结构(即导航树)的转换问题。

用法:

var arrayToTree = require('array-to-tree');

var dataOne = [
  {
    id: 1,
    name: 'Portfolio',
    parent_id: undefined
  },
  {
    id: 2,
    name: 'Web Development',
    parent_id: 1
  },
  {
    id: 3,
    name: 'Recent Works',
    parent_id: 2
  },
  {
    id: 4,
    name: 'About Me',
    parent_id: undefined
  }
];

arrayToTree(dataOne);

/*
 * Output:
 *
 * Portfolio
 *   Web Development
 *     Recent Works
 * About Me
 */

var data = [{"country":"india","gender":"male","type":"lower","class":"X"}, {"country":"china","gender":"female","type":"upper"}, {"country":"india","gender":"female","type":"lower"}, {"country":"india","gender":"female","type":"upper"}]; var seq = ["country","type","gender","class"]; var treeData = createHieArr(data,seq); console.log(treeData) function createHieArr(data,seq){ var hieObj = createHieobj(data,seq,0), hieArr = convertToHieArr(hieObj,"Top Level"); return [{"name": "Top Level", "parent": "null", "children" : hieArr}] function convertToHieArr(eachObj,parent){ var arr = []; for(var i in eachObj){ arr.push({"name":i,"parent":parent,"children":convertToHieArr(eachObj[i],i)}) } return arr; } function createHieobj(data,seq,ind){ var s = seq[ind]; if(s == undefined){ return []; } var childObj = {}; for(var ele of data){ if(ele[s] != undefined){ if(childObj[ele[s]] == undefined){ childObj[ele[s]] = []; } childObj[ele[s]].push(ele); } } ind = ind+1; for(var ch in childObj){ childObj[ch] = createHieobj(childObj[ch],seq,ind) } return childObj; } }