下面是我用来创建目录的ES6代码(当它不存在时):

const fs = require('fs');
const path = require('path');

function createDirectory(directoryPath) {
  const directory = path.normalize(directoryPath);

  return new Promise((resolve, reject) => {
    fs.stat(directory, (error) => {
      if (error) {
        if (error.code === 'ENOENT') {
          fs.mkdir(directory, (error) => {
            if (error) {
              reject(error);
            } else {
              resolve(directory);
            }
          });
        } else {
          reject(error);
        }
      } else {
        resolve(directory);
      }
    });
  });
}

const directoryPath = `${__dirname}/test`;

createDirectory(directoryPath).then((path) => {
  console.log(`Successfully created directory: '${path}'`);
}).catch((error) => {
  console.log(`Problem creating directory: ${error.message}`)
});

注意:

In the beginning of the createDirectory function, I normalize the path to guarantee that the path seperator type of the operating system will be used consistently (e.g. this will turn C:\directory/test into C:\directory\test (when being on Windows) fs.exists is deprecated, that's why I use fs.stat to check if the directory already exists If a directory doesn't exist, the error code will be ENOENT (Error NO ENTry) The directory itself will be created using fs.mkdir I prefer the asynchronous function fs.mkdir over it's blocking counterpart fs.mkdirSync and because of the wrapping Promise it will be guaranteed that the path of the directory will only be returned after the directory has been successfully created

如果你想要一个快速而脏的眼线笔，使用这个:

fs.existsSync("directory") || fs.mkdirSync("directory");

您可以使用File System模块完成所有这些操作。

const
  fs = require('fs'),
  dirPath = `path/to/dir`

// Check if directory exists.
fs.access(dirPath, fs.constants.F_OK, (err)=>{
  if (err){
    // Create directory if directory does not exist.
    fs.mkdir(dirPath, {recursive:true}, (err)=>{
      if (err) console.log(`Error creating directory: ${err}`)
      else console.log('Directory created successfully.')
    })
  }
  // Directory now exists.
})

您甚至不需要检查目录是否存在。下面的代码还保证目录已经存在或已创建。

const
  fs = require('fs'),
  dirPath = `path/to/dir`

// Create directory if directory does not exist.
fs.mkdir(dirPath, {recursive:true}, (err)=>{
  if (err) console.log(`Error creating directory: ${err}`)
  // Directory now exists.
})

上面@Liberateur的答案对我来说无效(Node v8.10.0)。 做了一点修改，但我不确定这是否是一个正确的方式。请建议。

// Get modules node
const fs   = require('fs');
const path = require('path');

// Create
function mkdirpath(dirPath)
{
    try {
        fs.accessSync(dirPath, fs.constants.R_OK | fs.constants.W_OK);
    }
    catch(err) {
        try
        {
            fs.mkdirSync(dirPath);
        }
        catch(e)
        {
            mkdirpath(path.dirname(dirPath));
            mkdirpath(dirPath);
        }
    }
}

// Create folder path
mkdirpath('my/new/folder/create');

在我看来，在使用Javascript编写代码时，最好不要计算文件系统的命中次数。 然而，(1)stat & mkdir和(2)mkdir和检查(或丢弃)错误代码，这两种方法都是正确的方法来做你想要的。

Raugaral的回答，但是有-p功能。很丑，但很管用:

function mkdirp(dir) {
    let dirs = dir.split(/\\/).filter(asdf => !asdf.match(/^\s*$/))
    let fullpath = ''

    // Production directory will begin \\, test is on my local drive.
    if (dirs[0].match(/C:/i)) {
        fullpath = dirs[0] + '\\'
    }
    else {
        fullpath = '\\\\' + dirs[0] + '\\'
    }

    // Start from root directory + 1, build out one level at a time.
    dirs.slice(1).map(asdf => {
        fullpath += asdf + '\\'
        if (!fs.existsSync(fullpath)) {
            fs.mkdirSync(fullpath)
        }
    })
}//mkdirp