我想通过他们的IP吸引游客…现在我正在使用这个(http://api.hostip.info/country.php?ip=......)

这是我的代码:

<?php

if (isset($_SERVER['HTTP_CLIENT_IP']))
{
    $real_ip_adress = $_SERVER['HTTP_CLIENT_IP'];
}

if (isset($_SERVER['HTTP_X_FORWARDED_FOR']))
{
    $real_ip_adress = $_SERVER['HTTP_X_FORWARDED_FOR'];
}
else
{
    $real_ip_adress = $_SERVER['REMOTE_ADDR'];
}

$cip = $real_ip_adress;
$iptolocation = 'http://api.hostip.info/country.php?ip=' . $cip;
$creatorlocation = file_get_contents($iptolocation);

?>

好吧,它正常工作,但问题是,这返回国家代码,如US或CA.,而不是整个国家名称,如美国或加拿大。

那么,除了hostip.info提供的这些,还有什么好的选择吗?

我知道我可以编写一些代码,最终将这两个字母转换为整个国家的名称,但我实在懒得编写包含所有国家的代码……

注:出于某种原因,我不想使用任何现成的CSV文件或任何代码,将抓取这个信息为我,像ip2country现成的代码和CSV。


当前回答

试试这个简单的PHP函数。

<?php

function ip_info($ip = NULL, $purpose = "location", $deep_detect = TRUE) {
    $output = NULL;
    if (filter_var($ip, FILTER_VALIDATE_IP) === FALSE) {
        $ip = $_SERVER["REMOTE_ADDR"];
        if ($deep_detect) {
            if (filter_var(@$_SERVER['HTTP_X_FORWARDED_FOR'], FILTER_VALIDATE_IP))
                $ip = $_SERVER['HTTP_X_FORWARDED_FOR'];
            if (filter_var(@$_SERVER['HTTP_CLIENT_IP'], FILTER_VALIDATE_IP))
                $ip = $_SERVER['HTTP_CLIENT_IP'];
        }
    }
    $purpose    = str_replace(array("name", "\n", "\t", " ", "-", "_"), NULL, strtolower(trim($purpose)));
    $support    = array("country", "countrycode", "state", "region", "city", "location", "address");
    $continents = array(
        "AF" => "Africa",
        "AN" => "Antarctica",
        "AS" => "Asia",
        "EU" => "Europe",
        "OC" => "Australia (Oceania)",
        "NA" => "North America",
        "SA" => "South America"
    );
    if (filter_var($ip, FILTER_VALIDATE_IP) && in_array($purpose, $support)) {
        $ipdat = @json_decode(file_get_contents("http://www.geoplugin.net/json.gp?ip=" . $ip));
        if (@strlen(trim($ipdat->geoplugin_countryCode)) == 2) {
            switch ($purpose) {
                case "location":
                    $output = array(
                        "city"           => @$ipdat->geoplugin_city,
                        "state"          => @$ipdat->geoplugin_regionName,
                        "country"        => @$ipdat->geoplugin_countryName,
                        "country_code"   => @$ipdat->geoplugin_countryCode,
                        "continent"      => @$continents[strtoupper($ipdat->geoplugin_continentCode)],
                        "continent_code" => @$ipdat->geoplugin_continentCode
                    );
                    break;
                case "address":
                    $address = array($ipdat->geoplugin_countryName);
                    if (@strlen($ipdat->geoplugin_regionName) >= 1)
                        $address[] = $ipdat->geoplugin_regionName;
                    if (@strlen($ipdat->geoplugin_city) >= 1)
                        $address[] = $ipdat->geoplugin_city;
                    $output = implode(", ", array_reverse($address));
                    break;
                case "city":
                    $output = @$ipdat->geoplugin_city;
                    break;
                case "state":
                    $output = @$ipdat->geoplugin_regionName;
                    break;
                case "region":
                    $output = @$ipdat->geoplugin_regionName;
                    break;
                case "country":
                    $output = @$ipdat->geoplugin_countryName;
                    break;
                case "countrycode":
                    $output = @$ipdat->geoplugin_countryCode;
                    break;
            }
        }
    }
    return $output;
}

?>

使用方法:

Example1:获取访问者IP地址的详细信息

<?php

echo ip_info("Visitor", "Country"); // India
echo ip_info("Visitor", "Country Code"); // IN
echo ip_info("Visitor", "State"); // Andhra Pradesh
echo ip_info("Visitor", "City"); // Proddatur
echo ip_info("Visitor", "Address"); // Proddatur, Andhra Pradesh, India

print_r(ip_info("Visitor", "Location")); // Array ( [city] => Proddatur [state] => Andhra Pradesh [country] => India [country_code] => IN [continent] => Asia [continent_code] => AS )

?>

例2:获取任意IP地址的详细信息。[支持IPV4和IPV6]

<?php

echo ip_info("173.252.110.27", "Country"); // United States
echo ip_info("173.252.110.27", "Country Code"); // US
echo ip_info("173.252.110.27", "State"); // California
echo ip_info("173.252.110.27", "City"); // Menlo Park
echo ip_info("173.252.110.27", "Address"); // Menlo Park, California, United States

print_r(ip_info("173.252.110.27", "Location")); // Array ( [city] => Menlo Park [state] => California [country] => United States [country_code] => US [continent] => North America [continent_code] => NA )

?>

其他回答

我有一个简短的答案,我在一个项目中使用过。 在我的回答中,我认为你有访问者IP地址。

$ip = "202.142.178.220";
$ipdat = @json_decode(file_get_contents("http://www.geoplugin.net/json.gp?ip=" . $ip));
//get ISO2 country code
if(property_exists($ipdat, 'geoplugin_countryCode')) {
    echo $ipdat->geoplugin_countryCode;
}
//get country full name
if(property_exists($ipdat, 'geoplugin_countryName')) {
    echo $ipdat->geoplugin_countryName;
}

实际上,您可以调用http://api.hostip.info/?ip=123.125.114.144来获取以XML形式显示的信息。

仅用4行代码就实现了这一点!

$user_ip = '0.0.0.0';
$user_ip = $_SERVER['REMOTE_ADDR'];
$close_url = stream_context_create(array('http' => array('header'=>'Connection: close\r\n')));
$user_country = json_decode(file_get_contents("https://ipinfo.io/$user_ip/json",false,$close_url));
echo "Yes! we ship to your country: <b>" . $user_country->country . "</b>";

/ /输出是的!我们的船到你的国家美国

注意: $close_url用于在内容被检索后尽快结束file_get_contents,它提高了请求的速度x5。

如果你想显示完整的国家名称,你可以点击下面,看看如何。

在这里输入链接描述

//呼应“世界和平”;

使用MaxMind GeoIP(或GeoIPLite,如果你还没有准备好支付)。

$gi = geoip_open('GeoIP.dat', GEOIP_MEMORY_CACHE);
$country = geoip_country_code_by_addr($gi, $_SERVER['REMOTE_ADDR']);
geoip_close($gi);

截至2022年,MaxMind国家数据库可如下使用:

<?php
require_once 'vendor/autoload.php';
use MaxMind\Db\Reader;
$databaseFile = 'GeoIP2-Country.mmdb';
$reader = new Reader($databaseFile);
$cc = $reader->get($_SERVER['REMOTE_ADDR'])['country']['iso_code'] # US/GB...
$reader->close();

来源: https://github.com/maxmind/MaxMind-DB-Reader-php