JavaScript中没有“引用传递”。你可以传递一个对象(也就是说，你可以按值传递一个对象的引用)，然后让一个函数修改对象的内容:

function alterObject(obj) {
  obj.foo = "goodbye";
}

var myObj = { foo: "hello world" };

alterObject(myObj);

alert(myObj.foo); // "goodbye" instead of "hello world"

如果需要，可以使用数值索引遍历数组的属性，并修改数组的每个单元格。

var arr = [1, 2, 3];

for (var i = 0; i < arr.length; i++) { 
    arr[i] = arr[i] + 1; 
}

需要注意的是，“引用传递”是一个非常具体的术语。这并不仅仅意味着可以将引用传递给一个可修改的对象。相反，这意味着可以通过允许函数在调用上下文中修改该值的方式传递简单变量。所以:

 function swap(a, b) {
   var tmp = a;
   a = b;
   b = tmp; //assign tmp to b
 }

 var x = 1, y = 2;
 swap(x, y);

 alert("x is " + x + ", y is " + y); // "x is 1, y is 2"

在c++这样的语言中，这样做是可能的，因为该语言确实(在某种程度上)具有引用传递。

edit — this recently (March 2015) blew up on Reddit again over a blog post similar to mine mentioned below, though in this case about Java. It occurred to me while reading the back-and-forth in the Reddit comments that a big part of the confusion stems from the unfortunate collision involving the word "reference". The terminology "pass by reference" and "pass by value" predates the concept of having "objects" to work with in programming languages. It's really not about objects at all; it's about function parameters, and specifically how function parameters are "connected" (or not) to the calling environment. In particular, note that in a true pass-by-reference language — one that does involve objects — one would still have the ability to modify object contents, and it would look pretty much exactly like it does in JavaScript. However, one would also be able to modify the object reference in the calling environment, and that's the key thing that you can't do in JavaScript. A pass-by-reference language would pass not the reference itself, but a reference to the reference.

编辑-这里有一篇关于这个主题的博客文章。(注意那篇文章的注释，解释了c++并没有真正的引用传递。这是真的。然而，c++所拥有的是创建对普通变量的引用的能力，可以在函数调用时显式地创建指针，也可以在调用其参数类型签名要求这样做的函数时隐式地创建指针。这些都是JavaScript不支持的关键。)

JavaScript中没有“引用传递”。你可以传递一个对象(也就是说，你可以按值传递一个对象的引用)，然后让一个函数修改对象的内容:

function alterObject(obj) {
  obj.foo = "goodbye";
}

var myObj = { foo: "hello world" };

alterObject(myObj);

alert(myObj.foo); // "goodbye" instead of "hello world"

如果需要，可以使用数值索引遍历数组的属性，并修改数组的每个单元格。

var arr = [1, 2, 3];

for (var i = 0; i < arr.length; i++) { 
    arr[i] = arr[i] + 1; 
}

需要注意的是，“引用传递”是一个非常具体的术语。这并不仅仅意味着可以将引用传递给一个可修改的对象。相反，这意味着可以通过允许函数在调用上下文中修改该值的方式传递简单变量。所以:

 function swap(a, b) {
   var tmp = a;
   a = b;
   b = tmp; //assign tmp to b
 }

 var x = 1, y = 2;
 swap(x, y);

 alert("x is " + x + ", y is " + y); // "x is 1, y is 2"

在c++这样的语言中，这样做是可能的，因为该语言确实(在某种程度上)具有引用传递。

edit — this recently (March 2015) blew up on Reddit again over a blog post similar to mine mentioned below, though in this case about Java. It occurred to me while reading the back-and-forth in the Reddit comments that a big part of the confusion stems from the unfortunate collision involving the word "reference". The terminology "pass by reference" and "pass by value" predates the concept of having "objects" to work with in programming languages. It's really not about objects at all; it's about function parameters, and specifically how function parameters are "connected" (or not) to the calling environment. In particular, note that in a true pass-by-reference language — one that does involve objects — one would still have the ability to modify object contents, and it would look pretty much exactly like it does in JavaScript. However, one would also be able to modify the object reference in the calling environment, and that's the key thing that you can't do in JavaScript. A pass-by-reference language would pass not the reference itself, but a reference to the reference.

编辑-这里有一篇关于这个主题的博客文章。(注意那篇文章的注释，解释了c++并没有真正的引用传递。这是真的。然而，c++所拥有的是创建对普通变量的引用的能力，可以在函数调用时显式地创建指针，也可以在调用其参数类型签名要求这样做的函数时隐式地创建指针。这些都是JavaScript不支持的关键。)

I've been playing around with syntax to do this sort of thing, but it requires some helpers that are a little unusual. It starts with not using 'var' at all, but a simple 'DECLARE' helper that creates a local variable and defines a scope for it via an anonymous callback. By controlling how variables are declared, we can choose to wrap them into objects so that they can always be passed by reference, essentially. This is similar to one of the Eduardo Cuomo's answer above, but the solution below does not require using strings as variable identifiers. Here's some minimal code to show the concept.

function Wrapper(val){
    this.VAL = val;
}
Wrapper.prototype.toString = function(){
    return this.VAL.toString();
}

function DECLARE(val, callback){
    var valWrapped = new Wrapper(val);    
    callback(valWrapped);
}

function INC(ref){
    if(ref && ref.hasOwnProperty('VAL')){
        ref.VAL++; 
    }
    else{
        ref++;//or maybe throw here instead?
    }

    return ref;
}

DECLARE(5, function(five){ //consider this line the same as 'let five = 5'
console.log("five is now " + five);
INC(five); // increment
console.log("five is incremented to " + five);
});

另一种通过引用传递任何(局部的，基本的)变量的方法是通过eval“动态”地用闭包包装变量。这也适用于“use strict”。(注意:注意eval对JavaScript优化器不友好，并且变量名周围缺少引号可能会导致不可预测的结果)

"use strict"

// Return text that will reference variable by name (by capturing that variable to closure)
function byRef(varName){
    return "({get value(){return "+varName+";}, set value(v){"+varName+"=v;}})";
}

// Demo

// Assign argument by reference
function modifyArgument(argRef, multiplier){
    argRef.value = argRef.value * multiplier;
}

(function(){
    var x = 10;

    alert("x before: " + x);
    modifyArgument(eval(byRef("x")), 42);
    alert("x after: " + x);
})()

现场示例:https://jsfiddle.net/t3k4403w/

像字符串和数字这样的基本类型变量总是按值传递。 数组和对象通过引用或基于以下条件的值传递:

如果你正在设置一个对象或数组的值，它是通过值传递。 Object1 = {prop: "car"}; Array1 = [1,2,3]; 如果你正在改变一个对象或数组的属性值，那么它是引用传递。 中的object1。道具= "汽车"; Array1 [0] = 9;

Code

函数passVar(obj1, obj2, num) { 其中obj1。道具= "笔记本电脑";//将改变原来的 Obj2 ={道具:"电脑"};//不影响原 Num = Num + 1;//不影响原 ｝ Var object1 = { 道具:“车” }; Var object2 = { 道具:“自行车” }; Var number1 = 10; passVar(object1, object2, number1); console.log(中的object1);//输出:对象{道具:"笔记本电脑"} console.log (object2);//输出:Object {prop: "bike"} console.log (number1);//输出:10

使用解构这里是一个例子，我有3个变量，对每个我做多个操作:

如果value小于0，则改为0， 如果大于255，则改为1， 否则，将数字俯冲255以将0-255的范围转换为0-1的范围。

let a = 52.4, b = -25.1, c = 534.5;
[a, b, c] = [a, b, c].map(n => n < 0 ? 0 : n > 255 ? 1 : n / 255);
console.log(a, b, c); // 0.20549019607843136 0 1