你可以这样写一个Kotlin扩展:

fun String.isValidEmail() =
        isNotEmpty() && android.util.Patterns.EMAIL_ADDRESS.matcher(this).matches()

然后像这样调用它:

email.isValidEmail()

你可以通过oval.jar文件在android中进行任何类型的验证。OVal是一种实用的、可扩展的通用验证框架，适用于任何类型的Java对象。

点击这个链接:http://oval.sourceforge.net/userguide.html

你可以从这里下载:http://oval.sourceforge.net/userguide.html#download

您可以通过在变量中设置标记来使用验证

public class Something{

    @NotEmpty  //not empty validation
    @Email     //email validation
    @SerializedName("emailAddress")
    private String emailAddress;
}

   private void checkValidation() {
        Something forgotpass.setEmailAddress(LoginActivity.this.dialog_email.getText().toString());
        Validator validator = new Validator();
        //collect the constraint violations
        List<ConstraintViolation> violations = validator.validate(forgotpass);
        if(violations.size()>0){
            for (ConstraintViolation cv : violations){
                if(cv.getMessage().contains("emailAddress")){
                    dialog_email.setError(ValidationMessage.formattedError(cv.getMessage(), forgotpass));
                }
            }
        }
}

对于正则表达式爱好者来说，我迄今为止发现的最好的(例如与RFC 822一致)电子邮件模式如下(在PHP提供过滤器之前)。我想对于那些使用API < 8的人来说，将其翻译成Java很容易:

private static function email_regex_pattern() {
// Source:  http://www.iamcal.com/publish/articles/php/parsing_email
$qtext = '[^\\x0d\\x22\\x5c\\x80-\\xff]';
$dtext = '[^\\x0d\\x5b-\\x5d\\x80-\\xff]';
$atom = '[^\\x00-\\x20\\x22\\x28\\x29\\x2c\\x2e\\x3a-\\x3c'.
    '\\x3e\\x40\\x5b-\\x5d\\x7f-\\xff]+';
$quoted_pair = '\\x5c[\\x00-\\x7f]';
$domain_literal = "\\x5b($dtext|$quoted_pair)*\\x5d";
$quoted_string = "\\x22($qtext|$quoted_pair)*\\x22";
$domain_ref = $atom;
$sub_domain = "($domain_ref|$domain_literal)";
$word = "($atom|$quoted_string)";
$domain = "$sub_domain(\\x2e$sub_domain)*";
$local_part = "$word(\\x2e$word)*";
$pattern = "!^$local_part\\x40$domain$!";
return $pattern ;
}

最简单的电子邮件验证方式。

EditText TF;
public Button checkButton;

public final Pattern EMAIL_ADDRESS_PATTERN = Pattern.compile(
          "[a-zA-Z0-9+._%-+]{1,256}" +
          "@" +
          "[a-zA-Z0-9][a-zA-Z0-9-]{0,64}" +
          "(" +
          "." +
          "[a-zA-Z0-9][a-zA-Z0-9-]{0,25}" +
          ")+"
      );
 @Override
 public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    requestWindowFeature(Window.FEATURE_NO_TITLE);
    setContentView(R.layout.main);

   TF=(EditText) findViewById(R.id.TF);
   checkButton=(Button) findViewById(R.id.checkButton);

    checkButton.setOnClickListener(new OnClickListener() {
    public void onClick(View v) {
           String email=TF.getText().toString();
           if(checkEmail(email))
              Toast.makeText(getApplicationContext(),"Valid Email Addresss", Toast.LENGTH_SHORT).show();
           else
              Toast.makeText(getApplicationContext(),"Invalid Email Addresss", Toast.LENGTH_SHORT).show();
    }
    });
}
private boolean checkEmail(String email) {
    return EMAIL_ADDRESS_PATTERN.matcher(email).matches();
}}

试试这段代码..它真的有效。

            if (!email
                    .matches("^[\\w-_\\.+]*[\\w-_\\.]\\@([\\w]+\\.)+[\\w]+[\\w]$"))
            {
                Toast.makeText(getApplicationContext(), "Email is invalid",
                        Toast.LENGTH_LONG).show();
                return;
            }

这是Android Studio的建议:

public static boolean isEmailValid(String email) {
    return !(email == null || TextUtils.isEmpty(email)) && android.util.Patterns.EMAIL_ADDRESS.matcher(email).matches();
}