我创建了一个递归函数来遍历表示json结构的套字典。

  myjson={}
  myjson["Country"]= {"KR": { "id": "220", "name": "South Korea"}}
  myjson["Creative"]= {
                    "1067405": {
                        "id": "1067405",
                        "url": "https://cdn.gowadogo.com/559d1ba1-8d50-4c7f-b3f5-d80f918006e0.jpg"
                    },
                    "1067406": {
                        "id": "1067406",
                        "url": "https://cdn.gowadogo.com/3799a70d-339c-4ecb-bc1f-a959dde675b8.jpg"
                    },
                    "1067407": {
                        "id": "1067407",
                        "url": "https://cdn.gowadogo.com/180af6a5-251d-4aa9-9cd9-51b2fc77d0c6.jpg"
                    }
                }
   myjson["Offer"]= {
                    "advanced_targeting_enabled": "f",
                    "category_name": "E-commerce/ Shopping",
                    "click_lifespan": "168",
                    "conversion_cap": "50",
                    "currency": "USD",
                    "default_payout": "1.5"
                }

   json_data = json.dumps(myjson)

   #reverse back into a json

   paths=[]
   def walk_the_tree(inputDict,suffix=None):
       for key, value in inputDict.items():
            if isinstance(value, dict):
                if suffix==None:
                    suffix=key
                else:
                    suffix+=":"+key

                walk_the_tree(value,suffix)
            else:
                paths.append(suffix+":"+key+":"+value)
 walk_the_tree(myjson)
 print(paths)  

 #split and build your nested dictionary
 json_specs = {}
 for path in paths:
     parts=path.split(':')
     value=(parts[-1])
     d=json_specs
     for p in parts[:-1]:
         if p==parts[-2]:
             d = d.setdefault(p,value)
         else:
             d = d.setdefault(p,{})
    
 print(json_specs)        

 Paths:
 ['Country:KR:id:220', 'Country:KR:name:South Korea', 'Country:Creative:1067405:id:1067405', 'Country:Creative:1067405:url:https://cdn.gowadogo.com/559d1ba1-8d50-4c7f-b3f5-d80f918006e0.jpg', 'Country:Creative:1067405:1067406:id:1067406', 'Country:Creative:1067405:1067406:url:https://cdn.gowadogo.com/3799a70d-339c-4ecb-bc1f-a959dde675b8.jpg', 'Country:Creative:1067405:1067406:1067407:id:1067407', 'Country:Creative:1067405:1067406:1067407:url:https://cdn.gowadogo.com/180af6a5-251d-4aa9-9cd9-51b2fc77d0c6.jpg', 'Country:Creative:Offer:advanced_targeting_enabled:f', 'Country:Creative:Offer:category_name:E-commerce/ Shopping', 'Country:Creative:Offer:click_lifespan:168', 'Country:Creative:Offer:conversion_cap:50', 'Country:Creative:Offer:currency:USD', 'Country:Creative:Offer:default_payout:1.5']

你可以使用jsonCreater模块创建json文件

        `jsonCreator.createJson(dict,”fileName”,[“path”])`

在将对象编码为JSON字符串之前构建对象:

import json

data = {}
data['key'] = 'value'
json_data = json.dumps(data)

JSON是一种序列化格式，文本数据表示一种结构。它本身并不是那种结构。

已经提供了一个解决方案，允许构建一个字典，(或嵌套字典更复杂的数据)，但如果你想构建一个对象，那么也许可以尝试'ObjDict'。这样可以更好地控制要创建的json，例如保留顺序，并允许将构建作为一个对象，这可能是您的概念的首选表示。

先安装PIP对象。

from objdict import ObjDict

data = ObjDict()
data.key = 'value'
json_data = data.dumps()

您可以创建Python字典，并在一行中将其序列化为JSON，它甚至不难看。

my_json_string = json.dumps({'key1': val1, 'key2': val2})

你可以使用EasyDict库(doc):

EasyDict允许将dict值作为属性访问(递归地工作)。python字典的类似javascript的属性点表示法。 用途不同 将easydict导入为敕令 >>> d =敕令({'foo':3， 'bar':{'x':1， 'y':2}}) > > > d.foo 3. > > > d.bar.x 1 >>> d =诏书(foo=3) > > > d.foo 3.

(安装):

PIP安装easydict