如何使用PHP获取客户端IP地址?

我想通过他/她的IP地址登录到我的网站的用户的记录。


当前回答

下面是一个很好的获取用户IP地址的干净代码示例。

$ip = $_SERVER['HTTP_CLIENT_IP'] 
   ? $_SERVER['HTTP_CLIENT_IP'] 
   : ($_SERVER['HTTP_X_FORWARDED_FOR'] 
        ? $_SERVER['HTTP_X_FORWARDED_FOR'] 
        : $_SERVER['REMOTE_ADDR']);

下面是一个使用elvis操作符的简短版本:

$_SERVER['HTTP_CLIENT_IP'] 
   ? : ($_SERVER['HTTP_X_FORWARDED_FOR'] 
   ? : $_SERVER['REMOTE_ADDR']);

下面是一个使用isset删除通知的版本(谢谢你,@shasi kanth):

$ip = isset($_SERVER['HTTP_CLIENT_IP']) 
    ? $_SERVER['HTTP_CLIENT_IP'] 
    : (isset($_SERVER['HTTP_X_FORWARDED_FOR']) 
      ? $_SERVER['HTTP_X_FORWARDED_FOR'] 
      : $_SERVER['REMOTE_ADDR']);

其他回答

function get_client_ip()
{
    foreach (array(
                'HTTP_CLIENT_IP',
                'HTTP_X_FORWARDED_FOR',
                'HTTP_X_FORWARDED',
                'HTTP_X_CLUSTER_CLIENT_IP',
                'HTTP_FORWARDED_FOR',
                'HTTP_FORWARDED',
                'REMOTE_ADDR') as $key) {
        if (array_key_exists($key, $_SERVER)) {
            foreach (explode(',', $_SERVER[$key]) as $ip) {
                $ip = trim($ip);
                if ((bool) filter_var($ip, FILTER_VALIDATE_IP,
                                FILTER_FLAG_IPV4 |
                                FILTER_FLAG_NO_PRIV_RANGE |
                                FILTER_FLAG_NO_RES_RANGE)) {
                    return $ip;
                }
            }
        }
    }
    return null;
}

或压缩版:

function get_ip() {
    foreach (array('HTTP_CLIENT_IP', 'HTTP_X_FORWARDED_FOR', 'HTTP_X_FORWARDED', 'HTTP_X_CLUSTER_CLIENT_IP', 'HTTP_FORWARDED_FOR', 'HTTP_FORWARDED', 'REMOTE_ADDR') as $key) {
        if (array_key_exists($key, $_SERVER) === true) {
            foreach (array_map('trim', explode(',', $_SERVER[$key])) as $ip) {
                if (filter_var($ip, FILTER_VALIDATE_IP, FILTER_FLAG_NO_PRIV_RANGE | FILTER_FLAG_NO_RES_RANGE) !== false) {
                    return $ip;
                }
            }
        }
    }
}

像下面这样?

if (($ip=filter_input(INPUT_SERVER, 'REMOTE_ADDR', validate_ip)) === false or empty($ip)) {
    exit;
}
echo $ip;

PS

if (($ip=filter_input(INPUT_SERVER, 'REMOTE_ADDR', FILTER_VALIDATE_IP|FILTER_FLAG_NO_PRIV_RANGE|FILTER_FLAG_NO_RES_RANGE)) === false) {
    header('HTTP/1.0 400 Bad Request');
    exit;
}

所有以'HTTP_'或'X-'开头的报头都可能被欺骗,分别由用户定义。如果你想要跟踪,可以使用cookie等。

下面是一个很好的获取用户IP地址的干净代码示例。

$ip = $_SERVER['HTTP_CLIENT_IP'] 
   ? $_SERVER['HTTP_CLIENT_IP'] 
   : ($_SERVER['HTTP_X_FORWARDED_FOR'] 
        ? $_SERVER['HTTP_X_FORWARDED_FOR'] 
        : $_SERVER['REMOTE_ADDR']);

下面是一个使用elvis操作符的简短版本:

$_SERVER['HTTP_CLIENT_IP'] 
   ? : ($_SERVER['HTTP_X_FORWARDED_FOR'] 
   ? : $_SERVER['REMOTE_ADDR']);

下面是一个使用isset删除通知的版本(谢谢你,@shasi kanth):

$ip = isset($_SERVER['HTTP_CLIENT_IP']) 
    ? $_SERVER['HTTP_CLIENT_IP'] 
    : (isset($_SERVER['HTTP_X_FORWARDED_FOR']) 
      ? $_SERVER['HTTP_X_FORWARDED_FOR'] 
      : $_SERVER['REMOTE_ADDR']);

快速解决方案(无错误)

function getClientIP():string
{
    $keys=array('HTTP_CLIENT_IP','HTTP_X_FORWARDED_FOR','HTTP_X_FORWARDED','HTTP_FORWARDED_FOR','HTTP_FORWARDED','REMOTE_ADDR');
    foreach($keys as $k)
    {
        if (!empty($_SERVER[$k]) && filter_var($_SERVER[$k], FILTER_VALIDATE_IP))
        {
            return $_SERVER[$k];
        }
    }
    return "UNKNOWN";
}

试试这个:

 $_SERVER['REMOTE_ADDR'];