执行以下命令:

显示Oracle数据库中的所有表

SELECT table_name FROM dba_tables;

显示当前用户拥有的表

SELECT table_name FROM user_tables;

显示当前用户可以访问的表

sql> SELECT table_name FROM all_tables

尝试从user_tables中选择，其中列出了当前用户拥有的表。

试试下面的数据字典视图。

tabs
dba_tables
all_tables
user_tables

SELECT owner, table_name
  FROM dba_tables

This is assuming that you have access to the DBA_TABLES data dictionary view. If you do not have those privileges but need them, you can request that the DBA explicitly grants you privileges on that table, or, that the DBA grants you the SELECT ANY DICTIONARY privilege or the SELECT_CATALOG_ROLE role (either of which would allow you to query any data dictionary table). Of course, you may want to exclude certain schemas like SYS and SYSTEM which have large numbers of Oracle tables that you probably don't care about.

或者，如果您没有访问DBA_TABLES，您可以通过ALL_TABLES视图查看您的帐户访问的所有表:

SELECT owner, table_name
  FROM all_tables

不过，这可能是数据库中可用表的一个子集(ALL_TABLES显示用户已被授予访问权限的所有表的信息)。

如果你只关心你拥有的表，而不是那些你可以访问的表，你可以使用USER_TABLES:

SELECT table_name
  FROM user_tables

因为USER_TABLES只包含关于您拥有的表的信息，所以它没有OWNER列——根据定义，所有者就是您自己。

Oracle also has a number of legacy data dictionary views-- TAB, DICT, TABS, and CAT for example-- that could be used. In general, I would not suggest using these legacy views unless you absolutely need to backport your scripts to Oracle 6. Oracle has not changed these views in a long time so they often have problems with newer types of objects. For example, the TAB and CAT views both show information about tables that are in the user's recycle bin while the [DBA|ALL|USER]_TABLES views all filter those out. CAT also shows information about materialized view logs with a TABLE_TYPE of "TABLE" which is unlikely to be what you really want. DICT combines tables and synonyms and doesn't tell you who owns the object.

我找不到一个有用的答案

DBA_ALL_TABLES (ALL_ALL_TABLES/USER_ALL_TABLES)

所以决定加上我的版本。 这个视图实际上返回比DBA_TABLES更多的数据，因为它也返回对象表(http://docs.oracle.com/cd/E11882_01/server.112/e40402/statviews_1003.htm)。

我正在寻找一个包含所有列名的列表，这些列名属于一个模式表，按照列id的顺序排序。

这是我使用的查询:-

SELECT COLUMN_NAME
FROM ALL_TAB_COLUMNS
WHERE OWNER = 'schema_owner_username' AND TABLE_NAME='table_name'
ORDER BY COLUMN_ID ASC;