如果你的条件是这样的(匹配一个值)，一个简单的更优雅的方式是:

$results = User::where([
         'this' => value,
         'that' => value,
         'this_too' => value,
          ...
      ])
    ->get();

但如果你需要OR子句，那么确保你对每个OR where()子句重复必须满足条件。

    $player = Player::where([
            'name' => $name,
            'team_id' => $team_id
        ])
        ->orWhere([
            ['nickname', $nickname],
            ['team_id', $team_id]
        ])

你可以像这样在匿名函数中使用子查询:

 $results = User::where('this', '=', 1)
       ->where('that', '=', 1)
       ->where(
           function($query) {
             return $query
                    ->where('this_too', 'LIKE', '%fake%')
                    ->orWhere('that_too', '=', 1);
            })
            ->get();

$variable = array('this' => 1,
                    'that' => 1
                    'that' => 1,
                    'this_too' => 1,
                    'that_too' => 1,
                    'this_as_well' => 1,
                    'that_as_well' => 1,
                    'this_one_too' => 1,
                    'that_one_too' => 1,
                    'this_one_as_well' => 1,
                    'that_one_as_well' => 1);

foreach ($variable as $key => $value) {
    User::where($key, '=', $value);
}

一定要对子查询应用任何其他过滤器，否则or可能会收集所有记录。

$query = Activity::whereNotNull('id');
$count = 0;
foreach ($this->Reporter()->get() as $service) {
        $condition = ($count == 0) ? "where" : "orWhere";
        $query->$condition(function ($query) use ($service) {
            $query->where('branch_id', '=', $service->branch_id)
                  ->where('activity_type_id', '=', $service->activity_type_id)
                  ->whereBetween('activity_date_time', [$this->start_date, $this->end_date]);
        });
    $count++;
}
return $query->get();

whereColumn方法可以传递一个包含多个条件的数组。这些条件将使用and操作符进行连接。

例子:

$users = DB::table('users')
            ->whereColumn([
                ['first_name', '=', 'last_name'],
                ['updated_at', '>', 'created_at']
            ])->get();

$users = User::whereColumn([
                ['first_name', '=', 'last_name'],
                ['updated_at', '>', 'created_at']
            ])->get();

有关更多信息，请查看文档的这一部分 https://laravel.com/docs/5.4/queries#where-clauses

使用纯Eloquent，像这样实现它。这段代码返回所有帐户处于活动状态的已登录用户。 $用户= \ App \用户::(“状态”,“积极”)——> (logged_in,真的)- > ();