我使用Laravel雄辩的查询构建器，我有一个查询，我想在多个条件上有一个where子句。它能起作用，但并不优雅。
例子:
$results = User::where('this', '=', 1)
->where('that', '=', 1)
->where('this_too', '=', 1)
->where('that_too', '=', 1)
->where('this_as_well', '=', 1)
->where('that_as_well', '=', 1)
->where('this_one_too', '=', 1)
->where('that_one_too', '=', 1)
->where('this_one_as_well', '=', 1)
->where('that_one_as_well', '=', 1)
->get();
有没有更好的方法，或者我应该坚持这个方法?
当前回答
您可以在where子句中使用数组，如下所示。
$result=DB::table('users')->where(array(
'column1' => value1,
'column2' => value2,
'column3' => value3))
->get();
其他回答
多个where子句
$query=DB::table('users')
->whereRaw("users.id BETWEEN 1003 AND 1004")
->whereNotIn('users.id', [1005,1006,1007])
->whereIn('users.id', [1008,1009,1010]);
$query->where(function($query2) use ($value)
{
$query2->where('user_type', 2)
->orWhere('value', $value);
});
if ($user == 'admin'){
$query->where('users.user_name', $user);
}
终于得到了结果
$result = $query->get();
在这种情况下，你可以使用这样的代码:
User::where('this', '=', 1)
->whereNotNull('created_at')
->whereNotNull('updated_at')
->where(function($query){
return $query
->whereNull('alias')
->orWhere('alias', '=', 'admin');
});
它应该为你提供这样的查询:
SELECT * FROM `user`
WHERE `user`.`this` = 1
AND `user`.`created_at` IS NOT NULL
AND `user`.`updated_at` IS NOT NULL
AND (`alias` IS NULL OR `alias` = 'admin')
使用Array的条件:
$users = User::where([
'column1' => value1,
'column2' => value2,
'column3' => value3
])->get();
将产生如下查询:
SELECT * FROM TABLE WHERE column1 = value1 and column2 = value2 and column3 = value3
使用匿名函数的条件:
$users = User::where('column1', '=', value1)
->where(function($query) use ($variable1,$variable2){
$query->where('column2','=',$variable1)
->orWhere('column3','=',$variable2);
})
->where(function($query2) use ($variable1,$variable2){
$query2->where('column4','=',$variable1)
->where('column5','=',$variable2);
})->get();
将产生如下查询:
SELECT * FROM TABLE WHERE column1 = value1 and (column2 = value2 or column3 = value3) and (column4 = value4 and column5 = value5)
一定要对子查询应用任何其他过滤器，否则or可能会收集所有记录。
$query = Activity::whereNotNull('id');
$count = 0;
foreach ($this->Reporter()->get() as $service) {
$condition = ($count == 0) ? "where" : "orWhere";
$query->$condition(function ($query) use ($service) {
$query->where('branch_id', '=', $service->branch_id)
->where('activity_type_id', '=', $service->activity_type_id)
->whereBetween('activity_date_time', [$this->start_date, $this->end_date]);
});
$count++;
}
return $query->get();
如果你的条件是这样的(匹配一个值)，一个简单的更优雅的方式是:
$results = User::where([
'this' => value,
'that' => value,
'this_too' => value,
...
])
->get();
但如果你需要OR子句，那么确保你对每个OR where()子句重复必须满足条件。
$player = Player::where([
'name' => $name,
'team_id' => $team_id
])
->orWhere([
['nickname', $nickname],
['team_id', $team_id]
])
