以下内容是否会使对象满足枚举在JavaScript中的所有特性?类似于:
my.namespace.ColorEnum = {
RED : 0,
GREEN : 1,
BLUE : 2
}
// later on
if(currentColor == my.namespace.ColorEnum.RED) {
// whatever
}
还是有其他方法可以做到这一点?
以下内容是否会使对象满足枚举在JavaScript中的所有特性?类似于:
my.namespace.ColorEnum = {
RED : 0,
GREEN : 1,
BLUE : 2
}
// later on
if(currentColor == my.namespace.ColorEnum.RED) {
// whatever
}
还是有其他方法可以做到这一点?
当前回答
我认为它很容易使用。https://stackoverflow.com/a/32245370/4365315
var A = {a:11, b:22},
enumA = new TypeHelper(A);
if(enumA.Value === A.b || enumA.Key === "a"){
...
}
var keys = enumA.getAsList();//[object, object]
//set
enumA.setType(22, false);//setType(val, isKey)
enumA.setType("a", true);
enumA.setTypeByIndex(1);
更新:
这是我的助手代码(TypeHelper)。
var助手={isEmpty:函数(obj){回来obj | | obj===null | | obj===未定义| | Array.isArray(obj)&&obj.length===0;},isObject:函数(obj){return(对象类型==“object”);},sortObjectKeys:函数(对象){return Object.keys(对象).sort(函数(a,b){c=a-b;返回c});},containsItem:函数(arr,item){if(arr&&Array.isArray(arr)){return arr.indexOf(项)>-1;}其他{返回arr==项;}},pushArray:函数(arr1,arr2){if(arr1&&arr2&&Array.isArray(arr1)){arr1.push.apply(arr1,Array.isArray(arr2)?arr2:[arr2]);}}};函数TypeHelper(){var_types=参数[0],_defTypeIndex=0,_电流类型,_值,_allKeys=助手.sortObjectKeys(_types);if(arguments.length==2){_defTypeIndex=参数[1];}对象定义属性(this{关键字:{get:函数(){return _currentType;},集合:函数(val){_currentType.setType(val,true);},可枚举:真},值:{get:函数(){返回类型[_currentType];},集合:函数(val){_value.setType(val,false);},可枚举:真}});this.getAsList=函数(键){var列表=[];_allKeys.forEach(函数(键、idx、数组){if(键和类型[key]){if(!Helper.isEmpty(keys)&&Helper.containsItem(keys,key)|| Helper.isEmpty(key)){var json={};json.Key=密钥;json.Value=_types[key];Helper.pushArray(列表,json);}}});返回列表;};this.setType=函数(值,isKey){if(!Helper.isEmpty(value)){Object.keys(_types).forEach(函数(key,idx,array){if(Helper.isObject(值)){if(value&&value.Key==Key){_currentType=键;}}else if(isKey){if(value&&value.toString()==key.toString()){_currentType=键;}}否则如果(value&&value.toString()==_types[key]){_currentType=键;}});}其他{this.setDefaultType();}return isKey_类型[_currentType]:_currentType;};this.setTypeByIndex=函数(索引){对于(变量i=0;i<_allKeys.length;i++){如果(索引==i){_currentType=_allKeys[index];打破}}};this.setDefaultType=函数(){this.setTypeByIndex(_defTypeIndex);};this.setDefaultType();}变量类型A={“-1”:“任意”,“2”:“2L”,“100”:“100L”,“200”:“200L”,“1000”:“1000升”};var enumA=新的TypeHelper(TypeA,4);document.writeln(“Key=”,enumA.Key,”,Value=“,enumA.Value,”<br>“);enumA.setType(“200L”,假);document.writeln(“Key=”,enumA.Key,”,Value=“,enumA.Value,”<br>“);enumA.setDefaultType();document.writeln(“Key=”,enumA.Key,”,Value=“,enumA.Value,”<br>“);enumA.setTypeByIndex(1);document.writeln(“Key=”,enumA.Key,”,Value=“,enumA.Value,”<br>“);document.writeln(“等于=”,(enumA.Value==TypeA[“2”]));
其他回答
这是Typescript将其枚举转换为Javascript的方式:
var makeEnum = function(obj) {
obj[ obj['Active'] = 1 ] = 'Active';
obj[ obj['Closed'] = 2 ] = 'Closed';
obj[ obj['Deleted'] = 3 ] = 'Deleted';
}
Now:
makeEnum( NewObj = {} )
// => {1: "Active", 2: "Closed", 3: "Deleted", Active: 1, Closed: 2, Deleted: 3}
起初我很困惑obj[1]为什么返回“Active”,但后来意识到它的死简单赋值运算符赋值,然后返回:
obj['foo'] = 1
// => 1
class Enum {
constructor (...vals) {
vals.forEach( val => {
const CONSTANT = Symbol(val);
Object.defineProperty(this, val.toUpperCase(), {
get () {
return CONSTANT;
},
set (val) {
const enum_val = "CONSTANT";
// generate TypeError associated with attempting to change the value of a constant
enum_val = val;
}
});
});
}
}
用法示例:
const COLORS = new Enum("red", "blue", "green");
我编写了enumeranjs一个非常小的库来解决这个问题,它确保了类型安全,允许枚举常量从原型继承,保证枚举常量和枚举类型是不可变的+许多小特性。它允许重构大量代码,并在枚举定义中移动一些逻辑。下面是一个示例:
var CloseEventCodes = new Enumeration("closeEventCodes", {
CLOSE_NORMAL: { _id: 1000, info: "Connection closed normally" },
CLOSE_GOING_AWAY: { _id: 1001, info: "Connection closed going away" },
CLOSE_PROTOCOL_ERROR: { _id: 1002, info: "Connection closed due to protocol error" },
CLOSE_UNSUPPORTED: { _id: 1003, info: "Connection closed due to unsupported operation" },
CLOSE_NO_STATUS: { _id: 1005, info: "Connection closed with no status" },
CLOSE_ABNORMAL: { _id: 1006, info: "Connection closed abnormally" },
CLOSE_TOO_LARGE: { _id: 1009, info: "Connection closed due to too large packet" }
},{ talk: function(){
console.log(this.info);
}
});
CloseEventCodes.CLOSE_TOO_LARGE.talk(); //prints "Connection closed due to too large packet"
CloseEventCodes.CLOSE_TOO_LARGE instanceof CloseEventCodes //evaluates to true
枚举基本上是一个工厂。
此处提供完整记录的指南。希望这有帮助。
我修改了Andre“Fi”的解决方案:
function Enum() {
var that = this;
for (var i in arguments) {
that[arguments[i]] = i;
}
this.name = function(value) {
for (var key in that) {
if (that[key] == value) {
return key;
}
}
};
this.exist = function(value) {
return (typeof that.name(value) !== "undefined");
};
if (Object.freeze) {
Object.freeze(that);
}
}
测试:
var Color = new Enum('RED', 'GREEN', 'BLUE');
undefined
Color.name(Color.REDs)
undefined
Color.name(Color.RED)
"RED"
Color.exist(Color.REDs)
false
Color.exist(Color.RED)
true
外星人的解决方案是让事情尽可能简单:
使用enum关键字(在javascript中保留)如果enum关键字只是保留的,但未在javascript中实现,请定义以下内容constenumerate=spec=>spec.split(/\s*,\s*/).reduce((e,n)=>对象.assign(e,{[n]:n}),{})
现在,您可以轻松使用它
const kwords = enumerate("begin,end, procedure,if")
console.log(kwords, kwords.if, kwords.if == "if", kwords.undef)
我认为没有理由使枚举值显式变量。无论如何,脚本都是纯文本的,如果代码的一部分是字符串或有效代码,则没有任何区别。真正重要的是,无论何时使用或定义引号,都不需要处理成吨的引号。