给定这个函数，我想用随机颜色生成器替换颜色。
document.overlay = GPolyline.fromEncoded({
color: "#0000FF",
weight: 10,
points: encoded_points,
zoomFactor: 32,
levels: encoded_levels,
numLevels: 4
});
我该怎么做呢?
当前回答
'#'+Math.random().toString(16).slice(-3) // three-numbers format aka #f3c
'#'+Math.random().toString(16).slice(-6) // six-number format aka #abc123
其他回答
我喜欢这个:'#' + (Math.random().toString(16) + "000000").substring(2,8)
正则表达式
总是返回有效的十六进制6位颜色
"#xxxxxx".replace(/x/g, y=>(Math.random()*16|0).toString(16))
令c= "#xxxxxx"。替换(/ x / g, y = > (math . random () * 16 | 0) .toString (16)); console.log (c); document.body.style.background = c
创建一个基于任意随机值的唯一颜色
selectColor(numberOrString) {
if (typeof numberOrString === "string") {
// convert string to number
numberOrString = numberOrString.toLowerCase().split('').reduce(function (a, b) {
a = ((a << 5) - a) + b.charCodeAt(0); // explained here: https://stackoverflow.com/a/7616484/112731
return a & a
}, 0);
}
const hue = numberOrString * 137.508; // use golden angle approximation
return `hsl(${hue},50%,75%)`;
}
我的版本:
function RandomColor() {
var hex = (Math.round(Math.random()*0xffffff)).toString(16);
while (hex.length < 6) hex = "0" + hex;
return hex;
}
function get_random_color() {
return "#" + (Math.round(Math.random() * 0XFFFFFF)).toString(16);
}
http://jsfiddle.net/XmqDz/1/
