考虑下面的代码:
DummyBean dum = new DummyBean();
dum.setDummy("foo");
System.out.println(dum.getDummy()); // prints 'foo'
DummyBean dumtwo = dum;
System.out.println(dumtwo.getDummy()); // prints 'foo'
dum.setDummy("bar");
System.out.println(dumtwo.getDummy()); // prints 'bar' but it should print 'foo'
所以,我想把dumm复制到dum2,在不影响dum2的情况下改变dumm。但是上面的代码并没有这样做。当我改变了dumm中的一些东西,同样的变化也会发生在dum2中。
我想,当我说dumtwo = dum时,Java只复制了引用。那么,有没有办法创建一个新的dum副本并将其分配给dumtwo呢?
替代egaga的构造函数复制方法。您可能已经有了一个POJO,因此只需添加另一个方法copy(),该方法返回初始化对象的副本。
class DummyBean {
private String dummyStr;
private int dummyInt;
public DummyBean(String dummyStr, int dummyInt) {
this.dummyStr = dummyStr;
this.dummyInt = dummyInt;
}
public DummyBean copy() {
return new DummyBean(dummyStr, dummyInt);
}
//... Getters & Setters
}
如果你已经有一个DummyBean,想要一个副本:
DummyBean bean1 = new DummyBean("peet", 2);
DummyBean bean2 = bean1.copy(); // <-- Create copy of bean1
System.out.println("bean1: " + bean1.getDummyStr() + " " + bean1.getDummyInt());
System.out.println("bean2: " + bean2.getDummyStr() + " " + bean2.getDummyInt());
//Change bean1
bean1.setDummyStr("koos");
bean1.setDummyInt(88);
System.out.println("bean1: " + bean1.getDummyStr() + " " + bean1.getDummyInt());
System.out.println("bean2: " + bean2.getDummyStr() + " " + bean2.getDummyInt());
输出:
Bean1:宠物2
Bean2: peet 2
豆1:库斯88
Bean2: peet 2
但两者都很好,最终取决于你……
使用Kotlin扩展函数
fun <T : Any?> T.duplicate(): T? {
var copyObject: T? = null
try {
val byteArrayOutputStream = ByteArrayOutputStream()
val objectOutputStream = ObjectOutputStream(byteArrayOutputStream)
objectOutputStream.writeObject(this)
objectOutputStream.flush()
objectOutputStream.close()
byteArrayOutputStream.close()
val byteData = byteArrayOutputStream.toByteArray()
val byteArrayInputStream = ByteArrayInputStream(byteData)
try {
copyObject = ObjectInputStream(byteArrayInputStream).readObject() as T
} catch (e: ClassNotFoundException) {
e.printStackTrace()
}
} catch (e: IOException) {
e.printStackTrace()
}
return copyObject
}
用例
var object = Any()
var duplicateObject = object.duplicate()
Java
<T extends Object> T copyObject(T sourceObject) {
T copyObject = null;
try {
ByteArrayOutputStream byteArrayOutputStream = new ByteArrayOutputStream();
ObjectOutputStream objectOutputStream = new ObjectOutputStream(byteArrayOutputStream);
objectOutputStream.writeObject(sourceObject);
objectOutputStream.flush();
objectOutputStream.close();
byteArrayOutputStream.close();
byte[] byteData = byteArrayOutputStream.toByteArray();
ByteArrayInputStream byteArrayInputStream = new ByteArrayInputStream(byteData);
try {
copyObject = (T) new ObjectInputStream(byteArrayInputStream).readObject();
} catch (ClassNotFoundException e) {
e.printStackTrace();
}
} catch (IOException e) {
e.printStackTrace();
}
return copyObject;
}
用例
Object object = new Object();
Object duplicateObject = copyObject(object);
==============================================
芬兰湾的科特林更新
如果您使用数据类,那么您将有复制方法来复制Kotlin数据类。很酷的是,你还可以通过一些值来修改对象的新副本。我推荐这种方式。
例子:
/ /类
data class TestModel(val title: String, var subtitle: String)
用例
val testClass = TestModel("Test title", "Test subtitle")
val newInstance = testClass.copy(subtitle = "new subtitle for copy instance")
为什么使用反射API没有答案?
private static Object cloneObject(Object obj){
try{
Object clone = obj.getClass().newInstance();
for (Field field : obj.getClass().getDeclaredFields()) {
field.setAccessible(true);
field.set(clone, field.get(obj));
}
return clone;
}catch(Exception e){
return null;
}
}
这真的很简单。
EDIT:通过递归包含子对象
private static Object cloneObject(Object obj){
try{
Object clone = obj.getClass().newInstance();
for (Field field : obj.getClass().getDeclaredFields()) {
field.setAccessible(true);
if(field.get(obj) == null || Modifier.isFinal(field.getModifiers())){
continue;
}
if(field.getType().isPrimitive() || field.getType().equals(String.class)
|| field.getType().getSuperclass().equals(Number.class)
|| field.getType().equals(Boolean.class)){
field.set(clone, field.get(obj));
}else{
Object childObj = field.get(obj);
if(childObj == obj){
field.set(clone, clone);
}else{
field.set(clone, cloneObject(field.get(obj)));
}
}
}
return clone;
}catch(Exception e){
return null;
}
}
我使用谷歌的JSON库来序列化它,然后创建序列化对象的新实例。它进行深度复制,但有一些限制:
不能有任何递归引用
它不会复制不同类型的数组
数组和列表应该被类型化,否则它将找不到要实例化的类
您可能需要在自己声明的类中封装字符串
我还使用这个类来保存用户首选项,窗口和在运行时重新加载的东西。这是非常容易使用和有效的。
import com.google.gson.*;
public class SerialUtils {
//___________________________________________________________________________________
public static String serializeObject(Object o) {
Gson gson = new Gson();
String serializedObject = gson.toJson(o);
return serializedObject;
}
//___________________________________________________________________________________
public static Object unserializeObject(String s, Object o){
Gson gson = new Gson();
Object object = gson.fromJson(s, o.getClass());
return object;
}
//___________________________________________________________________________________
public static Object cloneObject(Object o){
String s = serializeObject(o);
Object object = unserializeObject(s,o);
return object;
}
}