在UITableView中检测哪个UIButton被按下了

我有一个UITableView和5个uitableviewcell。每个单元格包含一个UIButton，设置如下:

- (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath
{
     NSString *identifier = @"identifier";
     UITableViewCell *cell = [tableView dequeueReusableCellWithIdentifier:identifier];
     if (cell == nil) {
         cell = [[UITableView alloc] initWithStyle:UITableViewCellStyleDefault reuseIdentifier:identifier];
         [cell autorelelase];

         UIButton *button = [[UIButton alloc] initWithFrame:CGRectMake(10, 5, 40, 20)];
         [button addTarget:self action:@selector(buttonPressedAction:) forControlEvents:UIControlEventTouchUpInside];
         [button setTag:1];
         [cell.contentView addSubview:button];

         [button release];
     }

     UIButton *button = (UIButton *)[cell viewWithTag:1];
     [button setTitle:@"Edit" forState:UIControlStateNormal];

     return cell;
}

我的问题是:在buttonPressedAction:方法中，我如何知道哪个按钮被按下了。我考虑过使用标签，但我不确定这是最好的方法。我希望能够以某种方式将indexPath标记到控件上。

- (void)buttonPressedAction:(id)sender
{
    UIButton *button = (UIButton *)sender;
    // how do I know which button sent this message?
    // processing button press for this row requires an indexPath. 
}

标准的做法是什么?

编辑:

我已经通过以下方法解决了这个问题。我还是想知道这是标准的方法还是有更好的方法?

- (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath
{
     NSString *identifier = @"identifier";
     UITableViewCell *cell = [tableView dequeueReusableCellWithIdentifier:identifier];
     if (cell == nil) {
         cell = [[UITableView alloc] initWithStyle:UITableViewCellStyleDefault reuseIdentifier:identifier];
         [cell autorelelase];

         UIButton *button = [[UIButton alloc] initWithFrame:CGRectMake(10, 5, 40, 20)];
         [button addTarget:self action:@selector(buttonPressedAction:) forControlEvents:UIControlEventTouchUpInside];
         [cell.contentView addSubview:button];

         [button release];
     }

     UIButton *button = (UIButton *)[cell.contentView.subviews objectAtIndex:0];
     [button setTag:indexPath.row];
     [button setTitle:@"Edit" forState:UIControlStateNormal];

     return cell;
}

- (void)buttonPressedAction:(id)sender
{
    UIButton *button = (UIButton *)sender;
    int row = button.tag;
}

需要注意的是，我不能在创建单元格时设置标记，因为单元格可能会退出队列。感觉很脏。一定有更好的办法。

当前回答

在其他地方找到了一个很好的解决这个问题的方法，没有在按钮上的标签上搞砸:

- (void)buttonPressedAction:(id)sender {

    NSSet *touches = [event allTouches];
    UITouch *touch = [touches anyObject];
    CGPoint currentTouchPosition = [touch locationInView:self.tableView];
    NSIndexPath *indexPath = [self.tableView indexPathForRowAtPoint: currentTouchPosition];

    // do stuff with the indexPath...
}

2009-12-10 23:32:15

其他回答

我是这样做的。简洁明了:

- (IBAction)buttonTappedAction:(id)sender
{
    CGPoint buttonPosition = [sender convertPoint:CGPointZero
                                           toView:self.tableView];
    NSIndexPath *indexPath = [self.tableView indexPathForRowAtPoint:buttonPosition];
    ...
}

2012-09-17 04:51:52

在Apple的配件示例中，使用了以下方法:

[button addTarget:self action:@selector(checkButtonTapped:) forControlEvents:UIControlEventTouchUpInside];

然后在触摸处理程序中检索触摸坐标，并从该坐标计算索引路径:

- (void)checkButtonTapped:(id)sender
{
    CGPoint buttonPosition = [sender convertPoint:CGPointZero toView:self.tableView];
    NSIndexPath *indexPath = [self.tableView indexPathForRowAtPoint:buttonPosition];
    if (indexPath != nil)
    {
     ...
    }
}

2009-11-26 10:31:52

func buttonAction(sender:UIButton!)
    {
        var position: CGPoint = sender.convertPoint(CGPointZero, toView: self.tablevw)
        let indexPath = self.tablevw.indexPathForRowAtPoint(position)
        let cell: TableViewCell = tablevw.cellForRowAtIndexPath(indexPath!) as TableViewCell
        println(indexPath?.row)
        println("Button tapped")
    }

2015-03-31 05:58:11

@Vladimir的答案是Swift:

var buttonPosition = sender.convertPoint(CGPointZero, toView: self.tableView)
var indexPath = self.tableView.indexPathForRowAtPoint(buttonPosition)!

虽然检查indexPath != nil给了我手指…NSIndexPath不是NSString的子类型

2014-12-11 19:29:54

注意这里我使用自定义单元格，这段代码完全适合我

 @IBAction func call(sender: UIButton)
    {
        var contentView = sender.superview;
        var cell = contentView?.superview as EmployeeListCustomCell
        if (!(cell.isKindOfClass(EmployeeListCustomCell)))
        {
            cell = (contentView?.superview)?.superview as EmployeeListCustomCell
        }

        let phone = cell.lblDescriptionText.text!
        //let phone = detailObject!.mobile!
        let url:NSURL = NSURL(string:"tel://"+phone)!;
        UIApplication.sharedApplication().openURL(url);
    }

2015-02-06 12:46:09

在UITableView中检测哪个UIButton被按下了

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