我有一个网络调用要执行。但在此之前,我需要检查设备是否有互联网连接。
这是我目前为止所做的:
var connectivityResult = new Connectivity().checkConnectivity();// User defined class
if (connectivityResult == ConnectivityResult.mobile ||
connectivityResult == ConnectivityResult.wifi) {*/
this.getData();
} else {
neverSatisfied();
}
上述方法行不通。
使用connectivity_widget: ^0.1.7
添加附件:
dependencies:
connectivity_widget: ^0.1.7
添加代码:
ConnectivityWidget(
builder: (context, isOnline) => Center(
child: Column(
mainAxisAlignment: MainAxisAlignment.center,
children: <Widget>[
Text(
"${isOnline ? 'Connected' : 'Offline'}",
style: TextStyle(
fontSize: 30,
color: isOnline ? Colors.green : Colors.red),
),
],
),
),
)
输出:
import 'dart:async';
import 'dart:io';
import 'package:flutter/material.dart';
import 'package:app_settings/app_settings.dart';
import 'package:connectivity/connectivity.dart';
class InternetConnect extends StatefulWidget {
@override
InternetConnectState createState() => InternetConnectState();
}
class InternetConnectState extends State<InternetConnect> {
ConnectivityResult previous;
bool dialogshown = false;
StreamSubscription connectivitySubscription;
Future<bool> checkinternet() async {
try {
final result = await InternetAddress.lookup('google.com');
if (result.isNotEmpty && result[0].rawAddress.isNotEmpty) {
return Future.value(true);
}
} on SocketException catch (_) {
return Future.value(false);
}
}
void checkInternetConnect(BuildContext context) {
connectivitySubscription = Connectivity()
.onConnectivityChanged
.listen((ConnectivityResult connresult) {
if (connresult == ConnectivityResult.none) {
dialogshown = true;
showDialog(
context: context, barrierDismissible: false, child: alertDialog());
} else if (previous == ConnectivityResult.none) {
checkinternet().then((result) {
if (result == true) {
if (dialogshown == true) {
dialogshown = false;
Navigator.pop(context);
}
}
});
}
previous = connresult;
});
}
AlertDialog alertDialog() {
return AlertDialog(
title: Text('ERROR'),
content: Text("No Internet Detected."),
actions: <Widget>[
FlatButton(
// method to exit application programitacally
onPressed: () {
AppSettings.openWIFISettings();
},
child: Text("Settings"),
),
],
);
}
@override
Widget build(BuildContext context) {
return Container();
}
}
and you can use this method in init of any class
@override
void initState() {
// TODO: implement initState
InternetConnectState().checkInternetConnect(context);
super.initState();
}
在@dennmatt的回答之后,我注意到InternetAddress。查找可能会返回成功的结果,即使互联网连接断开-我测试它从我的模拟器连接到我的家庭WiFi,然后断开我的路由器的电缆。我认为原因是路由器缓存了域查找结果,所以它不必在每个查找请求时查询DNS服务器。
不管怎样,如果你像我一样使用Firestore,你可以用一个空事务替换try-SocketException-catch块并捕获TimeoutExceptions:
try {
await Firestore.instance.runTransaction((Transaction tx) {}).timeout(Duration(seconds: 5));
hasConnection = true;
} on PlatformException catch(_) { // May be thrown on Airplane mode
hasConnection = false;
} on TimeoutException catch(_) {
hasConnection = false;
}
另外,请注意,previousConnection是在async internet -check之前设置的,因此理论上,如果checkConnection()在短时间内被调用多次,那么在一行中可能有多个hasConnection=true或多个hasConnection=false。
我不确定@dennmatt是否故意这样做,但在我们的用例中没有副作用(setState只被调用两次,具有相同的值)。
迟答,但用这个包来检查。
包名:data_connection_checker
在你的酒吧里。yuml文件:
dependencies:
data_connection_checker: ^0.3.4
创建一个名为connection的文件。达特,随便你叫什么都行。
导入包:
import 'package:data_connection_checker/data_connection_checker.dart';
检查是否有网络连接:
print(await DataConnectionChecker().hasConnection);
我为小部件状态创建了一个基类
使用BaseState<LoginPage>代替State<LoginPage>
然后使用布尔变量isOnline
Text(isOnline ? 'is Online' : 'is Offline')
首先,添加连接性插件:
dependencies:
connectivity: ^0.4.3+2
然后添加BaseState类
import 'dart:async';
import 'dart:io';
import 'package:flutter/services.dart';
import 'package:connectivity/connectivity.dart';
import 'package:flutter/widgets.dart';
/// a base class for any statful widget for checking internet connectivity
abstract class BaseState<T extends StatefulWidget> extends State {
void castStatefulWidget();
final Connectivity _connectivity = Connectivity();
StreamSubscription<ConnectivityResult> _connectivitySubscription;
/// the internet connectivity status
bool isOnline = true;
/// initialize connectivity checking
/// Platform messages are asynchronous, so we initialize in an async method.
Future<void> initConnectivity() async {
// Platform messages may fail, so we use a try/catch PlatformException.
try {
await _connectivity.checkConnectivity();
} on PlatformException catch (e) {
print(e.toString());
}
// If the widget was removed from the tree while the asynchronous platform
// message was in flight, we want to discard the reply rather than calling
// setState to update our non-existent appearance.
if (!mounted) {
return;
}
await _updateConnectionStatus().then((bool isConnected) => setState(() {
isOnline = isConnected;
}));
}
@override
void initState() {
super.initState();
initConnectivity();
_connectivitySubscription = Connectivity()
.onConnectivityChanged
.listen((ConnectivityResult result) async {
await _updateConnectionStatus().then((bool isConnected) => setState(() {
isOnline = isConnected;
}));
});
}
@override
void dispose() {
_connectivitySubscription.cancel();
super.dispose();
}
Future<bool> _updateConnectionStatus() async {
bool isConnected;
try {
final List<InternetAddress> result =
await InternetAddress.lookup('google.com');
if (result.isNotEmpty && result[0].rawAddress.isNotEmpty) {
isConnected = true;
}
} on SocketException catch (_) {
isConnected = false;
return false;
}
return isConnected;
}
}
您需要像这样在您的状态下强制转换小部件
@override
void castStatefulWidget() {
// ignore: unnecessary_statements
widget is StudentBoardingPage;
}