为什么他们决定在Java和。net(和其他一些语言)中使字符串不可变?为什么不让它变呢?
当前回答
根据Effective Java,第4章,第73页,第二版:
"There are many good reasons for this: Immutable classes are easier to design, implement, and use than mutable classes. They are less prone to error and are more secure. [...] "Immutable objects are simple. An immutable object can be in exactly one state, the state in which it was created. If you make sure that all constructors establish class invariants, then it is guaranteed that these invariants will remain true for all time, with no effort on your part. [...] Immutable objects are inherently thread-safe; they require no synchronization. They cannot be corrupted by multiple threads accessing them concurrently. This is far and away the easiest approach to achieving thread safety. In fact, no thread can ever observe any effect of another thread on an immutable object. Therefore, immutable objects can be shared freely [...]
同一章的其他要点:
不仅可以共享不可变对象,还可以共享它们的内部结构。 […] 不可变对象为其他对象提供了很好的构建块,无论是可变的还是不可变的。 […] 不可变类的唯一缺点是,它们需要为每个不同的值提供一个单独的对象。
其他回答
线程安全和性能。如果一个字符串不能被修改,那么在多个线程之间传递引用是安全且快速的。如果字符串是可变的,则总是必须将字符串的所有字节复制到新实例,或者提供同步。一个典型的应用程序在每次需要修改字符串时将读取字符串100次。参见维基百科关于不变性的内容。
几乎每条规则都有例外:
using System;
using System.Runtime.InteropServices;
namespace Guess
{
class Program
{
static void Main(string[] args)
{
const string str = "ABC";
Console.WriteLine(str);
Console.WriteLine(str.GetHashCode());
var handle = GCHandle.Alloc(str, GCHandleType.Pinned);
try
{
Marshal.WriteInt16(handle.AddrOfPinnedObject(), 4, 'Z');
Console.WriteLine(str);
Console.WriteLine(str.GetHashCode());
}
finally
{
handle.Free();
}
}
}
}
Java中的字符串并不是真正不可变的,您可以使用反射和或类加载来更改它们的值。你不应该依赖这个属性来保证安全。 有关示例请参见:Java中的魔术
不可变性与安全性并没有那么紧密的联系。为此,至少在。net中,你得到了SecureString类。
稍后编辑:在Java中,你会发现GuardedString,一个类似的实现。
根据Effective Java,第4章,第73页,第二版:
"There are many good reasons for this: Immutable classes are easier to design, implement, and use than mutable classes. They are less prone to error and are more secure. [...] "Immutable objects are simple. An immutable object can be in exactly one state, the state in which it was created. If you make sure that all constructors establish class invariants, then it is guaranteed that these invariants will remain true for all time, with no effort on your part. [...] Immutable objects are inherently thread-safe; they require no synchronization. They cannot be corrupted by multiple threads accessing them concurrently. This is far and away the easiest approach to achieving thread safety. In fact, no thread can ever observe any effect of another thread on an immutable object. Therefore, immutable objects can be shared freely [...]
同一章的其他要点:
不仅可以共享不可变对象,还可以共享它们的内部结构。 […] 不可变对象为其他对象提供了很好的构建块,无论是可变的还是不可变的。 […] 不可变类的唯一缺点是,它们需要为每个不同的值提供一个单独的对象。
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