我试图在PHP中创建一个随机字符串，我得到绝对没有输出:
<?php
function RandomString()
{
$characters = '0123456789abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ';
$randstring = '';
for ($i = 0; $i < 10; $i++) {
$randstring = $characters[rand(0, strlen($characters))];
}
return $randstring;
}
RandomString();
echo $randstring;
我做错了什么?
当前回答
function generateRandomString($length = 10, $hasNumber = true, $hasLowercase = true, $hasUppercase = true): string
{
$string = '';
if ($hasNumber)
$string .= '0123456789';
if ($hasLowercase)
$string .= 'abcdefghijklmnopqrstuvwxyz';
if ($hasUppercase)
$string .= 'ABCDEFGHIJKLMNOPQRSTUVWXYZ';
return substr(str_shuffle(str_repeat($x = $string, ceil($length / strlen($x)))), 1, $length);
}
和使用:
echo generateRandomString(32);
其他回答
以前的答案会生成不安全或难以输入的密码。
这是安全的，并且提供了用户更有可能实际使用的密码，而不是因为一些薄弱的东西而被丢弃。
// NOTE: On PHP 5.x you will need to install https://github.com/paragonie/random_compat
/**
* Generate a password that can easily be typed by users.
*
* By default, this will sacrifice strength by skipping characters that can cause
* confusion. Set $allowAmbiguous to allow these characters.
*/
static public function generatePassword($length=12, $mixedCase=true, $numericCount=2, $symbolCount=1, $allowAmbiguous=false, $allowRepeatingCharacters=false)
{
// sanity check to prevent endless loop
if ($numericCount + $symbolCount > $length) {
throw new \Exception('generatePassword(): $numericCount + $symbolCount are too high');
}
// generate a basic password with just alphabetic characters
$chars = 'qwertyupasdfghjkzxcvbnm';
if ($mixedCase) {
$chars .= 'QWERTYUPASDFGHJKZXCVBNML';
}
if ($allowAmbiguous) {
$chars .= 'iol';
if ($mixedCase) {
$chars .= 'IO';
}
}
$password = '';
foreach (range(1, $length) as $index) {
$char = $chars[random_int(0, strlen($chars) - 1)];
if (!$allowRepeatingCharacters) {
while ($char == substr($password, -1)) {
$char = $chars[random_int(0, strlen($chars) - 1)];
}
}
$password .= $char;
}
// add numeric characters
$takenSubstitutionIndexes = [];
if ($numericCount > 0) {
$chars = '23456789';
if ($allowAmbiguous) {
$chars .= '10';
}
foreach (range(1, $numericCount) as $_) {
$index = random_int(0, strlen($password) - 1);
while (in_array($index, $takenSubstitutionIndexes)) {
$index = random_int(0, strlen($password) - 1);
}
$char = $chars[random_int(0, strlen($chars) - 1)];
if (!$allowRepeatingCharacters) {
while (substr($password, $index - 1, 1) == $char || substr($password, $index + 1, 1) == $char) {
$char = $chars[random_int(0, strlen($chars) - 1)];
}
}
$password[$index] = $char;
$takenSubstitutionIndexes[] = $index;
}
}
// add symbols
$chars = '!@#$%&*=+?';
if ($allowAmbiguous) {
$chars .= '^~-_()[{]};:|\\/,.\'"`<>';
}
if ($symbolCount > 0) {
foreach (range(1, $symbolCount) as $_) {
$index = random_int(0, strlen($password) - 1);
while (in_array($index, $takenSubstitutionIndexes)) {
$index = random_int(0, strlen($password) - 1);
}
$char = $chars[random_int(0, strlen($chars) - 1)];
if (!$allowRepeatingCharacters) {
while (substr($password, $index - 1, 1) == $char || substr($password, $index + 1, 1) == $char) {
$char = $chars[random_int(0, strlen($chars) - 1)];
}
}
$password[$index] = $char;
$takenSubstitutionIndexes[] = $index;
}
}
return $password;
}
一条线的解决方案是
str_shuffle(base64_encode(date('mdyhis').date('mdyhis')));
试试这个，它可以生成到master的长度。但它简单，适合小字符串。
$master="ABCDEFGHIJKLMNOPQRSTUVWXYZ";
$master_array = str_split($master);
shuffle($master_array);
print_r(implode("",array_slice($master_array,0,10)));
function gen_uid($l=5){
return substr(str_shuffle("ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789"), 10, $l);
}
echo gen_uid();
默认值[5]:WvPJz
echo gen_uid(30);
价值[30]:cAiGgtf1lDpFWoVwjykNKXxv6SC4Q2
@tasmaniski:你的答案对我有用。我也有同样的问题，我想把它推荐给那些一直在寻找同样答案的人。以下是来自@tasmaniski的留言:
<?php
$random = substr(md5(mt_rand()), 0, 7);
echo $random;
?>
这是一个youtube视频，向我们展示如何创建一个随机数
