我想最多四舍五入两位小数,但只有在必要时。
输入:
10
1.7777777
9.1
输出:
10
1.78
9.1
如何在JavaScript中执行此操作?
我想最多四舍五入两位小数,但只有在必要时。
输入:
10
1.7777777
9.1
输出:
10
1.78
9.1
如何在JavaScript中执行此操作?
当前回答
MarkG和Lavamantis提供了一个比已被接受的解决方案更好的解决方案。很遗憾他们没有得到更多的支持票!
这是我用来解决浮点小数问题的函数,也是基于MDN的。它甚至比Lavamantis的解决方案更通用(但不够简洁):
function round(value, exp) {
if (typeof exp === 'undefined' || +exp === 0)
return Math.round(value);
value = +value;
exp = +exp;
if (isNaN(value) || !(typeof exp === 'number' && exp % 1 === 0))
return NaN;
// Shift
value = value.toString().split('e');
value = Math.round(+(value[0] + 'e' + (value[1] ? (+value[1] + exp) : exp)));
// Shift back
value = value.toString().split('e');
return +(value[0] + 'e' + (value[1] ? (+value[1] - exp) : -exp));
}
将其用于:
round(10.8034, 2); // Returns 10.8
round(1.275, 2); // Returns 1.28
round(1.27499, 2); // Returns 1.27
round(1.2345678e+2, 2); // Returns 123.46
与拉瓦曼蒂斯的解决方案相比,我们可以做到。。。
round(1234.5678, -2); // Returns 1200
round("123.45"); // Returns 123
其他回答
避免舍入到任意位数的二进制问题的适当方法是:
function roundToDigits(number, digits) {
return Number(Math.round(Number(number + 'e' + digits)) + 'e-' + digits);
}
修复toFixed()函数的一种方法是:
Number.prototype.toFixed = (prototype => {
const toFixed = prototype.toFixed;
// noinspection JSVoidFunctionReturnValueUsed
return function (fractionDigits) {
if (!fractionDigits) {
return toFixed.call(this);
} else {
// Avoid binary rounding issues
fractionDigits = Math.floor(fractionDigits);
const n = Number(Math.round(Number(+this + 'e' + fractionDigits)) + 'e-' + fractionDigits);
return toFixed.call(n, fractionDigits);
}
};
})(Number.prototype);
我正在构建一个简单的tipCalculator,这里有很多答案似乎使问题过于复杂。所以我发现总结这个问题是真正回答这个问题的最佳方式。
如果要创建舍入的十进制数,首先调用Fixed(要保留的小数位数),然后将其包装在number()中。
最终结果是:
let amountDue = 286.44;
tip = Number((amountDue * 0.2).toFixed(2));
console.log(tip) // 57.29 instead of 57.288
这对我(TypeScript)起到了作用:
round(decimal: number, decimalPoints: number): number{
let roundedValue = Math.round(decimal * Math.pow(10, decimalPoints)) / Math.pow(10, decimalPoints);
console.log(`Rounded ${decimal} to ${roundedValue}`);
return roundedValue;
}
样本输出
Rounded 18.339840000000436 to 18.34
Rounded 52.48283999999984 to 52.48
Rounded 57.24612000000036 to 57.25
Rounded 23.068320000000142 to 23.07
Rounded 7.792980000000398 to 7.79
Rounded 31.54157999999981 to 31.54
Rounded 36.79686000000004 to 36.8
Rounded 34.723080000000124 to 34.72
Rounded 8.4375 to 8.44
Rounded 15.666960000000074 to 15.67
Rounded 29.531279999999924 to 29.53
Rounded 8.277420000000006 to 8.28
我的解决方案将输入视为字符串,并使用n位数字的“数学舍入”算法:取n位数字,如果数字n+1等于或大于5,则加1。它还允许指定负数,例如,将123.45舍入为-1的数字为120。它也适用于科学符号(例如1.2e-3)。我没有测量它的速度,我认为这不是最好的表现。
function safeRound( numInput, numPrecision ) {
const strNumber = numInput.toString().replace( 'E', 'e' );
const bSign = '+-'.indexOf( strNumber[ 0 ] ) !== -1;
const strSign = bSign ? strNumber[ 0 ] : '';
const numSign = strSign !== '-' ? +1 : -1;
const ixExponent = ( ixFound => ixFound !== -1 ? ixFound : strNumber.length )( strNumber.indexOf( 'e' ) );
const strExponent = strNumber.substr( ixExponent + 1 );
const numExponent = ixExponent !== strNumber.length ? Number.parseInt( strExponent ) : 0;
const ixDecimal = ( ixFound => ixFound !== -1 ? ixFound : ixExponent )( strNumber.indexOf( '.' ) );
const strInteger = strNumber.substring( !bSign ? 0 : 1, ixDecimal );
const strFraction = strNumber.substring( ixDecimal + 1, ixExponent );
const numPrecisionAdjusted = numPrecision + numExponent;
const strIntegerKeep = strInteger.substring( 0, strInteger.length + Math.min( 0, numPrecisionAdjusted ) ) + '0'.repeat( -Math.min( 0, numPrecisionAdjusted ) );
const strFractionKeep = strFraction.substring( 0, Math.max( 0, numPrecisionAdjusted ) );
const strRoundedDown = strSign + ( strIntegerKeep === '' ? '0' : strIntegerKeep ) + ( strFractionKeep === '' ? '' : '.' + strFractionKeep ) + ( strExponent === '' ? '' : 'e' + strExponent );
const chRoundUp = 0 <= numPrecisionAdjusted ? strFraction.substr( numPrecisionAdjusted, 1 ) : ( '0' + strInteger ).substr( numPrecisionAdjusted, 1 );
const bRoundUp = '5' <= chRoundUp && chRoundUp <= '9';
const numRoundUp = bRoundUp ? numSign * Math.pow( 10, -numPrecision ) : 0;
return Number.parseFloat( strRoundedDown ) + numRoundUp;
}
function safeRoundTest( numInput, numPrecision, strExpected ) {
const strActual = safeRound( numInput, numPrecision ).toString();
const bPassed = strActual === strExpected;
console.log( 'numInput', numInput, 'numPrecision', numPrecision, 'strExpected', strExpected, 'strActual', strActual, 'bPassed', bPassed );
return bPassed ? 0 : 1;
}
function safeRoundTests() {
let numFailed = 0;
numFailed += safeRoundTest( 0, 0, '0' );
numFailed += safeRoundTest( '0', 0, '0' );
numFailed += safeRoundTest( '0.1', 0, '0' );
numFailed += safeRoundTest( '+0.1', 0, '0' );
numFailed += safeRoundTest( '-0.1', 0, '0' );
numFailed += safeRoundTest( '0.1', 1, '0.1' );
numFailed += safeRoundTest( '+0.1', 1, '0.1' );
numFailed += safeRoundTest( '-0.1', 1, '-0.1' );
numFailed += safeRoundTest( '0.9', 0, '1' );
numFailed += safeRoundTest( '+0.9', 0, '1' );
numFailed += safeRoundTest( '-0.9', 0, '-1' );
numFailed += safeRoundTest( '0.9', 1, '0.9' );
numFailed += safeRoundTest( '+0.9', 1, '0.9' );
numFailed += safeRoundTest( '-0.9', 1, '-0.9' );
numFailed += safeRoundTest( '0.5', 0, '1' );
numFailed += safeRoundTest( '+0.5', 0, '1' );
numFailed += safeRoundTest( '-0.5', 0, '-1' );
numFailed += safeRoundTest( '0.4999', 0, '0' );
numFailed += safeRoundTest( '+0.4999', 0, '0' );
numFailed += safeRoundTest( '-0.4999', 0, '0' );
numFailed += safeRoundTest( '1.005', 2, '1.01' );
numFailed += safeRoundTest( '1.00499999999', 2, '1' );
numFailed += safeRoundTest( '012.3456', -4, '0' );
numFailed += safeRoundTest( '012.3456', -3, '0' );
numFailed += safeRoundTest( '012.3456', -2, '0' );
numFailed += safeRoundTest( '012.3456', -1, '10' );
numFailed += safeRoundTest( '012.3456', 0, '12' );
numFailed += safeRoundTest( '012.3456', 1, '12.3' );
numFailed += safeRoundTest( '012.3456', 2, '12.35' );
numFailed += safeRoundTest( '012.3456', 3, '12.346' );
numFailed += safeRoundTest( '012.3456', 4, '12.3456' );
numFailed += safeRoundTest( '012.3456', 5, '12.3456' );
numFailed += safeRoundTest( '12.', 0, '12' );
numFailed += safeRoundTest( '.12', 2, '0.12' );
numFailed += safeRoundTest( '0e0', 0, '0' );
numFailed += safeRoundTest( '1.2e3', 0, '1200' );
numFailed += safeRoundTest( '1.2e+3', 0, '1200' );
numFailed += safeRoundTest( '1.2e-3', 0, '0' );
numFailed += safeRoundTest( '1.2e-3', 3, '0.001' );
numFailed += safeRoundTest( '1.2e-3', 4, '0.0012' );
numFailed += safeRoundTest( '1.2e-3', 5, '0.0012' );
numFailed += safeRoundTest( '+12.', 0, '12' );
numFailed += safeRoundTest( '+.12', 2, '0.12' );
numFailed += safeRoundTest( '+0e0', 0, '0' );
numFailed += safeRoundTest( '+1.2e3', 0, '1200' );
numFailed += safeRoundTest( '+1.2e+3', 0, '1200' );
numFailed += safeRoundTest( '+1.2e-3', 0, '0' );
numFailed += safeRoundTest( '+1.2e-3', 3, '0.001' );
numFailed += safeRoundTest( '+1.2e-3', 4, '0.0012' );
numFailed += safeRoundTest( '+1.2e-3', 5, '0.0012' );
numFailed += safeRoundTest( '-12.', 0, '-12' );
numFailed += safeRoundTest( '-.12', 2, '-0.12' );
numFailed += safeRoundTest( '-0e0', 0, '0' );
numFailed += safeRoundTest( '-1.2e3', 0, '-1200' );
numFailed += safeRoundTest( '-1.2e+3', 0, '-1200' );
numFailed += safeRoundTest( '-1.2e-3', 0, '0' );
numFailed += safeRoundTest( '-1.2e-3', 3, '-0.001' );
numFailed += safeRoundTest( '-1.2e-3', 4, '-0.0012' );
numFailed += safeRoundTest( '-1.2e-3', 5, '-0.0012' );
numFailed += safeRoundTest( '9876.543e210', 0, '9.876543e+213' );
numFailed += safeRoundTest( '9876.543e210', -210, '9.877e+213' );
numFailed += safeRoundTest( '9876.543e210', -209, '9.8765e+213' );
numFailed += safeRoundTest( '9876.543e+210', 0, '9.876543e+213' );
numFailed += safeRoundTest( '9876.543e+210', -210, '9.877e+213' );
numFailed += safeRoundTest( '9876.543e+210', -209, '9.8765e+213' );
numFailed += safeRoundTest( '9876.543e-210', 213, '9.876543e-207' );
numFailed += safeRoundTest( '9876.543e-210', 210, '9.877e-207' );
numFailed += safeRoundTest( '9876.543e-210', 211, '9.8765e-207' );
console.log( 'numFailed', numFailed );
}
safeRoundTests();
这个答案更关乎速度。
var precalculatedPrecisions = [1e0, 1e1, 1e2, 1e3, 1e4, 1e5, 1e6, 1e7, 1e8, 1e9, 1e10];
function round(num, _prec) {
_precision = precalculatedPrecisions[_prec]
return Math.round(num * _precision + 1e-14) / _precision ;
}
jsPerf关于这一点。