使用Python从字符串中剥离所有非字母数字字符的最佳方法是什么?
在这个问题的PHP变体中提出的解决方案可能会进行一些小的调整,但对我来说似乎不太“python化”。
声明一下,我不只是想去掉句号和逗号(以及其他标点符号),还想去掉引号、括号等。
使用Python从字符串中剥离所有非字母数字字符的最佳方法是什么?
在这个问题的PHP变体中提出的解决方案可能会进行一些小的调整,但对我来说似乎不太“python化”。
声明一下,我不只是想去掉句号和逗号(以及其他标点符号),还想去掉引号、括号等。
当前回答
我用perfplot(我的一个项目)检查了结果,发现对于短字符串,
"".join(filter(str.isalnum, s))
是最快的。对于长字符串(200+字符)
re.sub("[\W_]", "", s)
是最快的。
代码重现情节:
import perfplot
import random
import re
import string
pattern = re.compile("[\W_]+")
def setup(n):
return "".join(random.choices(string.ascii_letters + string.digits, k=n))
def string_alphanum(s):
return "".join(ch for ch in s if ch.isalnum())
def filter_str(s):
return "".join(filter(str.isalnum, s))
def re_sub1(s):
return re.sub("[\W_]", "", s)
def re_sub2(s):
return re.sub("[\W_]+", "", s)
def re_sub3(s):
return pattern.sub("", s)
b = perfplot.bench(
setup=setup,
kernels=[string_alphanum, filter_str, re_sub1, re_sub2, re_sub3],
n_range=[2**k for k in range(10)],
)
b.save("out.png")
b.show()
其他回答
for char in my_string:
if not char.isalnum():
my_string = my_string.replace(char,"")
如果我理解正确,最简单的方法是使用正则表达式,因为它为您提供了很大的灵活性,但另一个简单的方法是使用循环以下是示例代码,我还计算了单词的出现并存储在字典中。
s = """An... essay is, generally, a piece of writing that gives the author's own
argument — but the definition is vague,
overlapping with those of a paper, an article, a pamphlet, and a short story. Essays
have traditionally been
sub-classified as formal and informal. Formal essays are characterized by "serious
purpose, dignity, logical
organization, length," whereas the informal essay is characterized by "the personal
element (self-revelation,
individual tastes and experiences, confidential manner), humor, graceful style,
rambling structure, unconventionality
or novelty of theme," etc.[1]"""
d = {} # creating empty dic
words = s.split() # spliting string and stroing in list
for word in words:
new_word = ''
for c in word:
if c.isalnum(): # checking if indiviual chr is alphanumeric or not
new_word = new_word + c
print(new_word, end=' ')
# if new_word not in d:
# d[new_word] = 1
# else:
# d[new_word] = d[new_word] +1
print(d)
如果这个答案是有用的,请评价这个!
对于简单的一行代码(Python 3.0):
''.join(filter( lambda x: x in '0123456789abcdefghijklmnopqrstuvwxyz', the_string_you_want_stripped ))
对于Python < 3.0:
filter( lambda x: x in '0123456789abcdefghijklmnopqrstuvwxyz', the_string_you_want_stripped )
注意:如果需要,您可以将其他字符添加到允许字符列表中(例如:“0123456789 abcdefghijklmnopqrstuvwxyz。_”)。
我只是出于好奇计算了一些函数的时间。在这些测试中,我从字符串string中删除非字母数字字符。Printable(内置字符串模块的一部分)。使用编译的'[\W_]+'和模式。Sub (", str)被发现是最快的。
$ python -m timeit -s \
"import string" \
"''.join(ch for ch in string.printable if ch.isalnum())"
10000 loops, best of 3: 57.6 usec per loop
$ python -m timeit -s \
"import string" \
"filter(str.isalnum, string.printable)"
10000 loops, best of 3: 37.9 usec per loop
$ python -m timeit -s \
"import re, string" \
"re.sub('[\W_]', '', string.printable)"
10000 loops, best of 3: 27.5 usec per loop
$ python -m timeit -s \
"import re, string" \
"re.sub('[\W_]+', '', string.printable)"
100000 loops, best of 3: 15 usec per loop
$ python -m timeit -s \
"import re, string; pattern = re.compile('[\W_]+')" \
"pattern.sub('', string.printable)"
100000 loops, best of 3: 11.2 usec per loop
你可以试试:
print ''.join(ch for ch in some_string if ch.isalnum())