多年后，我回来对他们说:不要这样做!看XOR加密有什么问题?获取详细信息。

一种非常简单的双向加密是异或加密。

Come up with a password. Let's have it be mypass. Convert the password into binary (according to ASCII). The password becomes 01101101 01111001 01110000 01100001 01110011 01110011. Take the message you want to encode. Convert that into binary, also. Look at the length of the message. If the message length is 400 bytes, turn the password into a 400 byte string by repeating it over and over again. It would become 01101101 01111001 01110000 01100001 01110011 01110011 01101101 01111001 01110000 01100001 01110011 01110011 01101101 01111001 01110000 01100001 01110011 01110011... (or mypassmypassmypass...) XOR the message with the long password. Send the result. Another time, XOR the encrypted message with the same password (mypassmypassmypass...). There's your message!

在System.Security.Cryptography中使用TripleDESCryptoServiceProvider:

public static class CryptoHelper
{
    private const string Key = "MyHashString";
    private static TripleDESCryptoServiceProvider GetCryproProvider()
    {
        var md5 = new MD5CryptoServiceProvider();
        var key = md5.ComputeHash(Encoding.UTF8.GetBytes(Key));
        return new TripleDESCryptoServiceProvider() { Key = key, Mode = CipherMode.ECB, Padding = PaddingMode.PKCS7 };
    }

    public static string Encrypt(string plainString)
    {
        var data = Encoding.UTF8.GetBytes(plainString);
        var tripleDes = GetCryproProvider();
        var transform = tripleDes.CreateEncryptor();
        var resultsByteArray = transform.TransformFinalBlock(data, 0, data.Length);
        return Convert.ToBase64String(resultsByteArray);
    }

    public static string Decrypt(string encryptedString)
    {
        var data = Convert.FromBase64String(encryptedString);
        var tripleDes = GetCryproProvider();
        var transform = tripleDes.CreateDecryptor();
        var resultsByteArray = transform.TransformFinalBlock(data, 0, data.Length);
        return Encoding.UTF8.GetString(resultsByteArray);
    }
}

我想发布我的解决方案，因为上面的解决方案都不像我的那么简单。让我知道你的想法:

 // This will return an encrypted string based on the unencrypted parameter
 public static string Encrypt(this string DecryptedValue)
 {
      HttpServerUtility.UrlTokenEncode(MachineKey.Protect(Encoding.UTF8.GetBytes(DecryptedValue.Trim())));
 }

 // This will return an unencrypted string based on the parameter
 public static string Decrypt(this string EncryptedValue)
 {
      Encoding.UTF8.GetString(MachineKey.Unprotect(HttpServerUtility.UrlTokenDecode(EncryptedValue)));
 }

可选

这里假设用于加密该值的服务器的MachineKey与用于解密该值的MachineKey相同。如果需要，您可以在Web中指定一个静态MachineKey。配置，使您的应用程序可以解密/加密数据，而不管它在哪里运行(例如开发还是生产服务器)。您可以按照这些说明生成一个静态机器密钥。

命名空间System.Security.Cryptography包含TripleDESCryptoServiceProvider类和RijndaelManaged类

不要忘记添加对系统的引用。安全大会。

马克斯(优秀)答案的变体

添加“使用” 将类设置为IDisposable 删除URL编码代码以简化示例。 添加一个简单的测试装置来演示使用方法

希望这能有所帮助

[TestFixture]
public class RijndaelHelperTests
{
    [Test]
    public void UseCase()
    {
        //These two values should not be hard coded in your code.
        byte[] key = {251, 9, 67, 117, 237, 158, 138, 150, 255, 97, 103, 128, 183, 65, 76, 161, 7, 79, 244, 225, 146, 180, 51, 123, 118, 167, 45, 10, 184, 181, 202, 190};
        byte[] vector = {214, 11, 221, 108, 210, 71, 14, 15, 151, 57, 241, 174, 177, 142, 115, 137};

        using (var rijndaelHelper = new RijndaelHelper(key, vector))
        {
            var encrypt = rijndaelHelper.Encrypt("StringToEncrypt");
            var decrypt = rijndaelHelper.Decrypt(encrypt);
            Assert.AreEqual("StringToEncrypt", decrypt);
        }
    }
}

public class RijndaelHelper : IDisposable
{
    Rijndael rijndael;
    UTF8Encoding encoding;

    public RijndaelHelper(byte[] key, byte[] vector)
    {
        encoding = new UTF8Encoding();
        rijndael = Rijndael.Create();
        rijndael.Key = key;
        rijndael.IV = vector;
    }

    public byte[] Encrypt(string valueToEncrypt)
    {
        var bytes = encoding.GetBytes(valueToEncrypt);
        using (var encryptor = rijndael.CreateEncryptor())
        using (var stream = new MemoryStream())
        using (var crypto = new CryptoStream(stream, encryptor, CryptoStreamMode.Write))
        {
            crypto.Write(bytes, 0, bytes.Length);
            crypto.FlushFinalBlock();
            stream.Position = 0;
            var encrypted = new byte[stream.Length];
            stream.Read(encrypted, 0, encrypted.Length);
            return encrypted;
        }
    }

    public string Decrypt(byte[] encryptedValue)
    {
        using (var decryptor = rijndael.CreateDecryptor())
        using (var stream = new MemoryStream())
        using (var crypto = new CryptoStream(stream, decryptor, CryptoStreamMode.Write))
        {
            crypto.Write(encryptedValue, 0, encryptedValue.Length);
            crypto.FlushFinalBlock();
            stream.Position = 0;
            var decryptedBytes = new Byte[stream.Length];
            stream.Read(decryptedBytes, 0, decryptedBytes.Length);
            return encoding.GetString(decryptedBytes);
        }
    }

    public void Dispose()
    {
        if (rijndael != null)
        {
            rijndael.Dispose();
        }
    }
}

加密很简单:正如其他人指出的那样，在System.Security.Cryptography名称空间中有一些类可以为您完成所有工作。使用它们，而不是任何自制的解决方案。

但是解密也很容易。您遇到的问题不是加密算法，而是保护对用于解密的密钥的访问。

我会使用以下解决方案之一:

DPAPI using the ProtectedData class with CurrentUser scope. This is easy as you don't need to worry about a key. Data can only be decrypted by the same user, so no good for sharing data between users or machines. DPAPI using the ProtectedData class with LocalMachine scope. Good for e.g. protecting configuration data on a single secure server. But anyone who can log into the machine can encrypt it, so no good unless the server is secure. Any symmetric algorithm. I typically use the static SymmetricAlgorithm.Create() method if I don't care what algorithm is used (in fact it's Rijndael by default). In this case you need to protect your key somehow. E.g. you can obfuscate it in some way and hide it in your code. But be aware that anyone who is smart enough to decompile your code will likely be able to find the key.