注意:我之所以指出这个解决方案，是因为如果下一次打印的长度小于前一次打印的长度，我所见过的大多数其他解决方案都不起作用。

如果您知道要删除什么，并且可以使用全局变量，那么只需用空格覆盖最后一行。

在打印之前，将字符串的长度存储为' n '。 打印它，但以' \r '结尾(它返回行首)。 下次，在打印信息之前，在该行上打印“n”个空格。

_last_print_len = 0
def reprint(msg, finish=False):
    global _last_print_len
    
    # Ovewrites line with spaces.
    print(' '*_last_print_len, end='\r')
    
    if finish:
        end = '\n'
        # If we're finishing the line, we won't need to overwrite it in the next print.
        _last_print_len = 0
    else:
        end = '\r'
        # Store len for the next print.
        _last_print_len = len(msg)
    
    # Printing message.
    print(msg, end=end)

例子:

for i in range(10):
    reprint('Loading.')
    time.sleep(1)
    reprint('Loading..')
    time.sleep(1)
    reprint('Loading...')
    time.sleep(1)

for i in range(10):
    reprint('Loading.')
    time.sleep(1)
    reprint('Loading..')
    time.sleep(1)
    reprint('Loading...', finish=True)
    time.sleep(1)

使用print item，使print语句省略换行符。

在python3中，它是print(item, end=" ")。

如果你想让每个数字都显示在相同的位置，使用例如(Python 2.7):

to = 20
digits = len(str(to - 1))
delete = "\b" * (digits + 1)
for i in range(to):
    print "{0}{1:{2}}".format(delete, i, digits),

在Python 3中，这有点复杂;这里你需要刷新系统。Stdout或者在循环结束之前它不会打印任何东西:

import sys
to = 20
digits = len(str(to - 1))
delete = "\b" * (digits)
for i in range(to):
   print("{0}{1:{2}}".format(delete, i, digits), end="")
   sys.stdout.flush()

实现这一点的最佳方法是使用\r字符

试试下面的代码:

import time
for n in range(500):
  print(n, end='\r')
  time.sleep(0.01)
print()  # start new line so most recently printed number stays

对于那些像我一样挣扎的人，我提出了以下似乎在python 3.7.4和3.5.2中都可以工作的方法。

I expanded the range from 100 to 1,000,000 because it runs very fast and you may not see the output. This is because one side effect of setting end='\r' is that the final loop iteration clears all of the output. A longer number was needed to demonstrate that it works. This result may not be desirable in all cases, but was fine in mine, and OP didn't specify one way or another. You could potentially circumvent this with an if statement that evaluates the length of the array being iterated over, etc. The key to get it working in my case was to couple the brackets "{}" with .format(). Otherwise, it didn't work.

以下应按原样工作:

#!/usr/bin/env python3

for item in range(1,1000000):
    print("{}".format(item), end='\r', flush=True)

如果您希望它作为字符串，您可以使用

number_string = ""
for i in range(1, 100):
  number_string += str(i)
print(number_string)

将打印项更改为:

在Python 2.7中，打印项 print(item, end=" "

如果你想动态打印数据，请使用以下语法:

打印(item, sep=' '， end= "， flush=True