我试图使用一个选择语句从某个MySQL表中获得除一个以外的所有列。有什么简单的方法吗?
编辑:在这个表格中有53列(不是我的设计)
当前回答
如果你想排除一个字段的值，例如安全问题/敏感信息，你可以检索该列为空。
e.g.
SELECT *, NULL AS salary FROM users
其他回答
即使要查询所有列，也最好指定要查询的列。
因此，我建议您在语句中写下每一列的名称(不包括您不想要的列)。
SELECT
col1
, col2
, col3
, col..
, col53
FROM table
视图在这种情况下工作得更好吗?
CREATE VIEW vwTable
as
SELECT
col1
, col2
, col3
, col..
, col53
FROM table
在尝试@Mahomedalid和@Junaid的解决方案时，我发现了一个问题。所以我想分享一下。如果列名中有空格或连字符(如check-in)，则查询将失败。简单的解决方法是在列名周围使用反标记。修改后的查询如下
SET @SQL = CONCAT('SELECT ', (SELECT GROUP_CONCAT(CONCAT("`", COLUMN_NAME, "`")) FROM
INFORMATION_SCHEMA.COLUMNS WHERE TABLE_NAME = 'users' AND COLUMN_NAME NOT IN ('id')), ' FROM users');
PREPARE stmt1 FROM @SQL;
EXECUTE stmt1;
也许我有一个解决Jan Koritak指出的矛盾的方法
SELECT CONCAT('SELECT ',
( SELECT GROUP_CONCAT(t.col)
FROM
(
SELECT CASE
WHEN COLUMN_NAME = 'eid' THEN NULL
ELSE COLUMN_NAME
END AS col
FROM INFORMATION_SCHEMA.COLUMNS
WHERE TABLE_NAME = 'employee' AND TABLE_SCHEMA = 'test'
) t
WHERE t.col IS NOT NULL) ,
' FROM employee' );
表:
SELECT table_name,column_name
FROM INFORMATION_SCHEMA.COLUMNS
WHERE TABLE_NAME = 'employee' AND TABLE_SCHEMA = 'test'
= = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = =
table_name column_name
employee eid
employee name_eid
employee sal
= = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = =
查询结果:
'SELECT name_eid,sal FROM employee'
虽然我同意Thomas的答案(+1;))，但我想补充一点，即我假设您不想要的列几乎不包含任何数据。如果它包含大量的文本、xml或二进制blob，那么请花时间单独选择每一列。否则你的表现就会受到影响。干杯!
