我尝试了上面的例子，但它没有显示超过4000个字符，然后我对它进行了一点点修改，并能够得到整个存储过程定义。请参阅下面更新的脚本-

SELECT SCHEMA_NAME(O.SCHEMA_ID) [SCHEMA_NAME], O.NAME, OBJECT_DEFINITION(OBJECT_ID) TEXT
FROM   SYSCOMMENTS AS C
       INNER JOIN SYS.OBJECTS AS O ON C.ID = O.[OBJECT_ID]
       INNER JOIN SYS.SCHEMAS AS S ON O.SCHEMA_ID = S.SCHEMA_ID
WHERE  OBJECT_DEFINITION(OBJECT_ID) LIKE '%FOO%'
ORDER BY  SCHEMA_NAME(O.SCHEMA_ID), O.NAME

SELECT * FROM sys.procedures WHERE Name LIKE '%CompanySpecialisation%'

这是我在SQL 2012中编写的，以选择所有名称为“CompanySpecialisation”的存储过程。

我尝试了上面的例子，但它没有显示超过4000个字符，然后我对它进行了一点点修改，并能够得到整个存储过程定义。请参阅下面更新的脚本-

SELECT SCHEMA_NAME(O.SCHEMA_ID) [SCHEMA_NAME], O.NAME, OBJECT_DEFINITION(OBJECT_ID) TEXT
FROM   SYSCOMMENTS AS C
       INNER JOIN SYS.OBJECTS AS O ON C.ID = O.[OBJECT_ID]
       INNER JOIN SYS.SCHEMAS AS S ON O.SCHEMA_ID = S.SCHEMA_ID
WHERE  OBJECT_DEFINITION(OBJECT_ID) LIKE '%FOO%'
ORDER BY  SCHEMA_NAME(O.SCHEMA_ID), O.NAME

select * from sys.system_objects
where name like '%cdc%'

首先确保在用户凭证下运行查询，并且在正确的数据库上下文中运行查询。

USE YOUR_DATABASE_NAME;

否则,系统。过程不会返回任何东西。现在运行查询如下所示:

select * from sys.procedures p 
join sys.syscomments s on p.object_id = s.id 
where text like '%YOUR_TEXT%';

另一种选择是使用INFORMATION_SCHEMA.ROUTINES。ROUTINE_DEFINITION，但是请注意它只保存例程的有限数量的字符(即，前4000个字符)。

select * from YOUR_DATABASE_NAME.INFORMATION_SCHEMA.ROUTINES
where ROUTINE_DEFINITION like '%YOUR_TEXT%';

我在Microsoft SQL Server 2008 R2 (SP1) - 10.50.2500.0 (X64)上进行测试

如果你也需要schema:

SELECT   DISTINCT SCHEMA_NAME(o.schema_id),o.name,[text]
FROM     syscomments AS c
         INNER JOIN sys.objects AS o ON c.id = o.[object_id]
         INNER JOIN sys.schemas AS s ON o.schema_id = s.schema_id
WHERE    text LIKE '%foo%'
ORDER BY  SCHEMA_NAME(o.schema_id),o.name