我有以下YAML:
paths:
patha: /path/to/root/a
pathb: /path/to/root/b
pathc: /path/to/root/c
我如何“正常化”它，通过从三个路径中删除/path/到/root/，并将其作为自己的设置，类似于:
paths:
root: /path/to/root/
patha: *root* + a
pathb: *root* + b
pathc: *root* + c
显然这是无效的，我瞎编的。真正的语法是什么?这能做到吗?
当前回答
YML定义:
dir:
default: /home/data/in/
proj1: ${dir.default}p1
proj2: ${dir.default}p2
proj3: ${dir.default}p3
在百里叶的某个地方
<p th:utext='${@environment.getProperty("dir.default")}' />
<p th:utext='${@environment.getProperty("dir.proj1")}' />
输出: / home /数据/ in / / home /数据/ in / p1
其他回答
是的，使用自定义标签。Python中的示例，使用!join标记连接数组中的字符串:
import yaml
## define custom tag handler
def join(loader, node):
seq = loader.construct_sequence(node)
return ''.join([str(i) for i in seq])
## register the tag handler
yaml.add_constructor('!join', join)
## using your sample data
yaml.load("""
paths:
root: &BASE /path/to/root/
patha: !join [*BASE, a]
pathb: !join [*BASE, b]
pathc: !join [*BASE, c]
""")
结果是:
{
'paths': {
'patha': '/path/to/root/a',
'pathb': '/path/to/root/b',
'pathc': '/path/to/root/c',
'root': '/path/to/root/'
}
}
join的参数数组可以包含任意数量的任何数据类型的元素，只要它们可以转换为字符串，因此!join [*a， "/"， *b， "/"， *c]就是您所期望的那样。
在某些语言中，你可以使用替代库，例如，tampax是YAML处理变量的实现:
const tampax = require('tampax');
const yamlString = `
dude:
name: Arthur
weapon:
favorite: Excalibur
useless: knife
sentence: "{{dude.name}} use {{weapon.favorite}}. The goal is {{goal}}."`;
const r = tampax.yamlParseString(yamlString, { goal: 'to kill Mordred' });
console.log(r.sentence);
// output : "Arthur use Excalibur. The goal is to kill Mordred."
编者注:海报作者也是本包的作者。
使用Yglu，你可以这样写你的例子:
paths:
root: /path/to/root/
patha: !? .paths.root + a
pathb: !? .paths.root + b
pathc: !? .paths.root + c
声明:我是Yglu的作者。
我已经创建了一个库，在Packagist上可用，执行这个函数: https://packagist.org/packages/grasmash/yaml-expander
YAML文件示例:
type: book
book:
title: Dune
author: Frank Herbert
copyright: ${book.author} 1965
protaganist: ${characters.0.name}
media:
- hardcover
characters:
- name: Paul Atreides
occupation: Kwisatz Haderach
aliases:
- Usul
- Muad'Dib
- The Preacher
- name: Duncan Idaho
occupation: Swordmaster
summary: ${book.title} by ${book.author}
product-name: ${${type}.title}
例子逻辑:
// Parse a yaml string directly, expanding internal property references.
$yaml_string = file_get_contents("dune.yml");
$expanded = \Grasmash\YamlExpander\Expander::parse($yaml_string);
print_r($expanded);
结果数组:
array (
'type' => 'book',
'book' =>
array (
'title' => 'Dune',
'author' => 'Frank Herbert',
'copyright' => 'Frank Herbert 1965',
'protaganist' => 'Paul Atreides',
'media' =>
array (
0 => 'hardcover',
),
),
'characters' =>
array (
0 =>
array (
'name' => 'Paul Atreides',
'occupation' => 'Kwisatz Haderach',
'aliases' =>
array (
0 => 'Usul',
1 => 'Muad\'Dib',
2 => 'The Preacher',
),
),
1 =>
array (
'name' => 'Duncan Idaho',
'occupation' => 'Swordmaster',
),
),
'summary' => 'Dune by Frank Herbert',
);
YML定义:
dir:
default: /home/data/in/
proj1: ${dir.default}p1
proj2: ${dir.default}p2
proj3: ${dir.default}p3
在百里叶的某个地方
<p th:utext='${@environment.getProperty("dir.default")}' />
<p th:utext='${@environment.getProperty("dir.proj1")}' />
输出: / home /数据/ in / / home /数据/ in / p1
