我用express 3在node.js中创建了一个文件上传函数。

我想抓取图像的文件扩展名。所以我可以重命名文件,然后附加文件扩展名。

app.post('/upload', function(req, res, next) {
    var is = fs.createReadStream(req.files.upload.path),
        fileExt = '', // I want to get the extension of the image here
        os = fs.createWriteStream('public/images/users/' + req.session.adress + '.' + fileExt);
});

如何在node.js中获得图像的扩展名?


当前回答

扩展String.prototype的一行代码:

Object.defineProperty(String.prototype, "ext", {get: function(x) {return this.split('.').pop()}})
str = 'fox.fbx';
str.ext

结果:

其他回答

const path = require('path');

function getExt(str) {
  const basename = path
    .basename(str)
    // Patch: for hidden files
    // Removes all dots at the beginning of a line
    .replace(/^(\.+)/i, '');

  const firstDot = basename.indexOf('.');
  const lastDot = basename.lastIndexOf('.');
  const extname = path.extname(basename).replace(/(\.[a-z0-9]+).*/i, '$1');

  if (firstDot === lastDot) {
    return extname;
  }

  return basename.slice(firstDot, lastDot) + extname;
}
const files = [
  '/home/charlike/bar/.hidden.tar.gz~',     // ".tar.gz"
  '/home/charlike/bar/file.tar.gz~',        // ".tar.gz"
  '/home/charlike/bar/file.tar.gz+cdf2',    // ".tar.gz"
  '/home/charlike/bar/file.tar.gz?quz=zaz', // ".tar.gz"
];

const fileAndExt = files.map((file) => [ file, getExt(file) ]);

console.log(JSON.stringify(fileAndExt, null, 2));
// you can send full url here
function getExtension(filename) {
    return filename.split('.').pop();
}

如果您正在使用express,请在配置中间件时添加以下行(bodyParser)

app.use(express.bodyParser({ keepExtensions: true}));
var fileName = req.files.upload.name;

var arr = fileName.split('.');

var extension = arr[length-1];

使用substr()方法比使用split() & pop()方法更有效

在这里看看性能差异:http://jsperf.com/remove-first-character-from-string

// returns: 'html'
var path = require('path');
path.extname('index.html').substr(1);

Update August 2019 As pointed out by @xentek in the comments; substr() is now considered a legacy function (MDN documentation). You can use substring() instead. The difference between substr() and substring() is that the second argument of substr() is the maximum length to return while the second argument of substring() is the index to stop at (without including that character). Also, substr() accepts negative start positions to be used as an offset from the end of the string while substring() does not.

试试这个

const path = require('path');

function getExt(str) {
  const basename = path.basename(str);
  const firstDot = basename.indexOf('.');
  const lastDot = basename.lastIndexOf('.');
  const extname = path.extname(basename).replace(/(\.[a-z0-9]+).*/i, '$1');

  if (firstDot === lastDot) {
    return extname;
  }

  return basename.slice(firstDot, lastDot) + extname;
}

// all are `.gz`
console.log(getExt('/home/charlike/bar/file.gz'));
console.log(getExt('/home/charlike/bar/file.gz~'));
console.log(getExt('/home/charlike/bar/file.gz+cdf2'));
console.log(getExt('/home/charlike/bar/file.gz?quz=zaz'));

// all are `.tar.gz`
console.log(getExt('/home/charlike/bar/file.tar.gz'));
console.log(getExt('/home/charlike/bar/file.tar.gz~'));
console.log(getExt('/home/charlike/bar/file.tar.gz+cdf2'));
console.log(getExt('/home/charlike/bar/file.tar.gz?quz=zaz'));