这里有一个来自这个博客的解决方案:http://brigitzblog.blogspot.com/2011/10/java-compare-dates.html

long milliseconds1 = calendar1.getTimeInMillis();
long milliseconds2 = calendar2.getTimeInMillis();
long diff = milliseconds2 - milliseconds1;
long diffDays = diff / (24 * 60 * 60 * 1000);
System.out.println("Time in days: " + diffDays  + " days.");

也就是说，你可以看到以毫秒为单位的时间差是否小于一天的长度。

我不知道这是新的想法或其他，但我给你展示我所做的

SimpleDateFormat dtf = new SimpleDateFormat("dd/MM/yyyy");
Date td_date = new Date();
String first_date = dtf.format(td_date);    //First seted in String 
String second_date = "30/11/2020";          //Second date you can set hear in String

String result = (first_date.equals(second_date)) ? "Yes, Its Equals":"No, It is not Equals";
System.out.println(result);

我的建议:

    Calendar cal = Calendar.getInstance();
    cal.set(1999,10,01);   // nov 1st, 1999
    cal.set(Calendar.AM_PM,Calendar.AM);
    cal.set(Calendar.HOUR,0);
    cal.set(Calendar.MINUTE,0);
    cal.set(Calendar.SECOND,0);
    cal.set(Calendar.MILLISECOND,0);

    // date column in the Thought table is of type sql date
    Thought thought = thoughtDao.getThought(date, language);

    Assert.assertEquals(cal.getTime(), thought.getDate());

我也更喜欢Joda Time，但这里有一个替代方案:

long oneDay = 24 * 60 * 60 * 1000
long d1 = first.getTime() / oneDay
long d2 = second.getTime() / oneDay
d1 == d2

EDIT

我把UTC的东西放在下面，以防你需要比较UTC以外的特定时区的日期。如果你确实有这样的需求，那么我真的建议你去找Joda。

long oneDay = 24 * 60 * 60 * 1000
long hoursFromUTC = -4 * 60 * 60 * 1000 // EST with Daylight Time Savings
long d1 = (first.getTime() + hoursFromUTC) / oneDay
long d2 = (second.getTime() + hoursFromUTC) / oneDay
d1 == d2

如果你正在寻找一个简单的解决方案，但你不想从你的项目中更改已弃用的java.util.Date类，你可以将这个方法添加到你的项目中，并继续你的探索:

使用java.util.concurrent.TimeUnit

`

public boolean isSameDay(Date first, Date second) {
    long difference_In_Time = first.getTime() - second.getTime();
        // calculate difference in days
        long difference_In_Days = 
        TimeUnit
              .MILLISECONDS
              .toDays(difference_In_Time);
        if (difference_In_Days == 0) {
            return true;
        }
        return false;
    }

`

像这样实现它:

`

Date first = ...;
Date second = ...;
if (isSameDay(first, second)) {
    // congratulations, they are the same
}
else {
   // heads up champ, they are not the same
}

`

如果你只想比较两个没有时间的日期，那么下面的代码可能会帮助你:

final SimpleDateFormat dateFormat = new SimpleDateFormat("yyyyMMdd");
Date dLastUpdateDate = dateFormat.parse(20111116);
Date dCurrentDate = dateFormat.parse(dateFormat.format(new Date()));
if (dCurrentDate.after(dLastUpdateDate))
{
   add your logic
}