我想有一个compareTo方法来忽略java.util.Date的时间部分。我想有很多方法可以解决这个问题。最简单的方法是什么?


当前回答

// Create one day 00:00:00 calendar
int oneDayTimeStamp = 1523017440;
Calendar oneDayCal = Calendar.getInstance();
oneDayCal.setTimeInMillis(oneDayTimeStamp * 1000L);
oneDayCal.set(Calendar.HOUR_OF_DAY, 0);
oneDayCal.set(Calendar.MINUTE, 0);
oneDayCal.set(Calendar.SECOND, 0);
oneDayCal.set(Calendar.MILLISECOND, 0);

// Create current day 00:00:00 calendar
Calendar currentCal = Calendar.getInstance();
currentCal.set(Calendar.HOUR_OF_DAY, 0);
currentCal.set(Calendar.MINUTE, 0);
currentCal.set(Calendar.SECOND, 0);
currentCal.set(Calendar.MILLISECOND, 0);

if (oneDayCal.compareTo(currentCal) == 0) {
    // Same day (excluding time)
}

其他回答

我的建议:

    Calendar cal = Calendar.getInstance();
    cal.set(1999,10,01);   // nov 1st, 1999
    cal.set(Calendar.AM_PM,Calendar.AM);
    cal.set(Calendar.HOUR,0);
    cal.set(Calendar.MINUTE,0);
    cal.set(Calendar.SECOND,0);
    cal.set(Calendar.MILLISECOND,0);

    // date column in the Thought table is of type sql date
    Thought thought = thoughtDao.getThought(date, language);

    Assert.assertEquals(cal.getTime(), thought.getDate());
public Date saveDateWithoutTime(Date date) {
    Calendar calendar = Calendar.getInstance();

    calendar.setTime( date );
    calendar.set(Calendar.HOUR_OF_DAY, 0);
    calendar.set(Calendar.HOUR, 0);
    calendar.set(Calendar.MINUTE, 0);
    calendar.set(Calendar.SECOND, 0);
    calendar.set(Calendar.MILLISECOND, 0);

    return calendar.getTime();
}

这将帮助你在不考虑时间的情况下比较日期。

如果严格使用Date (java.util.Date),或者不使用任何外部库。用这个:

public Boolean compareDateWithoutTime(Date d1, Date d2) {
    SimpleDateFormat sdf = new SimpleDateFormat("yyyyMMdd");
    return sdf.format(d1).equals(sdf.format(d2));
}

使用Apache commons你可以做到:

import org.apache.commons.lang3.time.DateUtils

DateUtils.truncatedEquals(first, second, Calendar.DAY_OF_MONTH)

对这个替代方案有什么意见吗?

SimpleDateFormat sdf = new SimpleDateFormat("yyyyMMdd");
sdf.format(date1).equals(sdf.format(date2));