是的，你能做到。在你的typescript组件上编写这段代码，然后享受吧!

import { Location } from '@angular/common'
import { Component, Input } from '@angular/core'

@Component({
    selector: 'return_page',
    template: `<button mat-button (click)="onReturn()">Back</button>`,
})
export class ReturnPageComponent {
  constructor(private location: Location) { }

  onReturn() {
    this.location.back();
  }
}

是的，你能做到。在你的typescript组件上编写这段代码，然后享受吧!

import { Location } from '@angular/common'
import { Component, Input } from '@angular/core'

@Component({
    selector: 'return_page',
    template: `<button mat-button (click)="onReturn()">Back</button>`,
})
export class ReturnPageComponent {
  constructor(private location: Location) { }

  onReturn() {
    this.location.back();
  }
}

在angular 4中使用preserveQueryParams，例如:

url: /list?page=1

<a [routerLink]="['edit',id]" [preserveQueryParams]="true"></a>

当点击链接时，您将被重定向编辑/10?Page =1，保留参数

裁判:https://angular.io/docs/ts/latest/guide/router.html # !# link-parameters-array

RC4:

import {Location} from '@angular/common';

用Angular 5.2.9测试过

如果你使用锚而不是按钮，你必须使用href="javascript:void(0)"将其设置为被动链接，以使Angular Location正常工作。

app.component.ts

import { Component } from '@angular/core';
import { Location } from '@angular/common';

@Component({
  selector: 'app-root',
  templateUrl: './app.component.html',
  styleUrls: [ './app.component.css' ]
})
export class AppComponent {

  constructor( private location: Location ) { 
  }

  goBack() {
    // window.history.back();
    this.location.back();

    console.log( 'goBack()...' );
  }
}

app.component.html

<!-- anchor must be a passive link -->
<a href="javascript:void(0)" (click)="goBack()">
  <-Back
</a>

只需使用Location，这是一个Angular服务，应用程序可以使用它与浏览器的URL进行交互。

导入:

import { Location } from '@angular/common';

注射:

constructor(private location: Location) { }

简单地使用它:

goBack() {
    this.location.back(); // Navigates back in the platform's history
}