如果有两个变量:
Object obj;
String methodName = "getName";
在不知道obj的类的情况下,我如何调用由methodName识别的方法?
被调用的方法没有参数,只有一个String返回值。它是Java bean的getter。
如果有两个变量:
Object obj;
String methodName = "getName";
在不知道obj的类的情况下,我如何调用由methodName识别的方法?
被调用的方法没有参数,只有一个String返回值。它是Java bean的getter。
当前回答
为了完成我同事的回答,你可能需要密切关注以下问题:
static or instance calls (in one case, you do not need an instance of the class, in the other, you might need to rely on an existing default constructor that may or may not be there) public or non-public method call (for the latter,you need to call setAccessible on the method within an doPrivileged block, other findbugs won't be happy) encapsulating into one more manageable applicative exception if you want to throw back the numerous java system exceptions (hence the CCException in the code below)
下面是一个旧的java1.4代码,它考虑了这些要点:
/**
* Allow for instance call, avoiding certain class circular dependencies. <br />
* Calls even private method if java Security allows it.
* @param aninstance instance on which method is invoked (if null, static call)
* @param classname name of the class containing the method
* (can be null - ignored, actually - if instance if provided, must be provided if static call)
* @param amethodname name of the method to invoke
* @param parameterTypes array of Classes
* @param parameters array of Object
* @return resulting Object
* @throws CCException if any problem
*/
public static Object reflectionCall(final Object aninstance, final String classname, final String amethodname, final Class[] parameterTypes, final Object[] parameters) throws CCException
{
Object res;// = null;
try {
Class aclass;// = null;
if(aninstance == null)
{
aclass = Class.forName(classname);
}
else
{
aclass = aninstance.getClass();
}
//Class[] parameterTypes = new Class[]{String[].class};
final Method amethod = aclass.getDeclaredMethod(amethodname, parameterTypes);
AccessController.doPrivileged(new PrivilegedAction() {
public Object run() {
amethod.setAccessible(true);
return null; // nothing to return
}
});
res = amethod.invoke(aninstance, parameters);
} catch (final ClassNotFoundException e) {
throw new CCException.Error(PROBLEM_TO_ACCESS+classname+CLASS, e);
} catch (final SecurityException e) {
throw new CCException.Error(PROBLEM_TO_ACCESS+classname+GenericConstants.HASH_DIESE+ amethodname + METHOD_SECURITY_ISSUE, e);
} catch (final NoSuchMethodException e) {
throw new CCException.Error(PROBLEM_TO_ACCESS+classname+GenericConstants.HASH_DIESE+ amethodname + METHOD_NOT_FOUND, e);
} catch (final IllegalArgumentException e) {
throw new CCException.Error(PROBLEM_TO_ACCESS+classname+GenericConstants.HASH_DIESE+ amethodname + METHOD_ILLEGAL_ARGUMENTS+String.valueOf(parameters)+GenericConstants.CLOSING_ROUND_BRACKET, e);
} catch (final IllegalAccessException e) {
throw new CCException.Error(PROBLEM_TO_ACCESS+classname+GenericConstants.HASH_DIESE+ amethodname + METHOD_ACCESS_RESTRICTION, e);
} catch (final InvocationTargetException e) {
throw new CCException.Error(PROBLEM_TO_ACCESS+classname+GenericConstants.HASH_DIESE+ amethodname + METHOD_INVOCATION_ISSUE, e);
}
return res;
}
其他回答
对于那些在同一个类中调用非静态方法的方法,请参见下面的代码:
class Person {
public void method1() {
try {
Method m2 = this.getClass().getDeclaredMethod("method2");
m1.invoke(this);
} catch (NoSuchMethodException e) {
e.printStackTrace();
} catch (IllegalAccessException e) {
e.printStackTrace();
} catch (InvocationTargetException e) {
e.printStackTrace();
}
}
public void method2() {
// Do something
}
}
从通俗的角度来说,它应该是这样的:
java.lang.reflect.Method method;
try {
method = obj.getClass().getMethod(methodName, param1.class, param2.class, ..);
} catch (SecurityException e) { ... }
catch (NoSuchMethodException e) { ... }
参数确定你需要的非常具体的方法(如果有几个重载可用,如果方法没有参数,只给出methodName)。
然后通过调用调用该方法
try {
method.invoke(obj, arg1, arg2,...);
} catch (IllegalArgumentException e) { ... }
catch (IllegalAccessException e) { ... }
catch (InvocationTargetException e) { ... }
同样,如果没有.invoke中的参数,请省略。但是是的。阅读Java反射
try {
YourClass yourClass = new YourClass();
Method method = YourClass.class.getMethod("yourMethodName", ParameterOfThisMethod.class);
method.invoke(yourClass, parameter);
} catch (Exception e) {
e.printStackTrace();
}
为了完成我同事的回答,你可能需要密切关注以下问题:
static or instance calls (in one case, you do not need an instance of the class, in the other, you might need to rely on an existing default constructor that may or may not be there) public or non-public method call (for the latter,you need to call setAccessible on the method within an doPrivileged block, other findbugs won't be happy) encapsulating into one more manageable applicative exception if you want to throw back the numerous java system exceptions (hence the CCException in the code below)
下面是一个旧的java1.4代码,它考虑了这些要点:
/**
* Allow for instance call, avoiding certain class circular dependencies. <br />
* Calls even private method if java Security allows it.
* @param aninstance instance on which method is invoked (if null, static call)
* @param classname name of the class containing the method
* (can be null - ignored, actually - if instance if provided, must be provided if static call)
* @param amethodname name of the method to invoke
* @param parameterTypes array of Classes
* @param parameters array of Object
* @return resulting Object
* @throws CCException if any problem
*/
public static Object reflectionCall(final Object aninstance, final String classname, final String amethodname, final Class[] parameterTypes, final Object[] parameters) throws CCException
{
Object res;// = null;
try {
Class aclass;// = null;
if(aninstance == null)
{
aclass = Class.forName(classname);
}
else
{
aclass = aninstance.getClass();
}
//Class[] parameterTypes = new Class[]{String[].class};
final Method amethod = aclass.getDeclaredMethod(amethodname, parameterTypes);
AccessController.doPrivileged(new PrivilegedAction() {
public Object run() {
amethod.setAccessible(true);
return null; // nothing to return
}
});
res = amethod.invoke(aninstance, parameters);
} catch (final ClassNotFoundException e) {
throw new CCException.Error(PROBLEM_TO_ACCESS+classname+CLASS, e);
} catch (final SecurityException e) {
throw new CCException.Error(PROBLEM_TO_ACCESS+classname+GenericConstants.HASH_DIESE+ amethodname + METHOD_SECURITY_ISSUE, e);
} catch (final NoSuchMethodException e) {
throw new CCException.Error(PROBLEM_TO_ACCESS+classname+GenericConstants.HASH_DIESE+ amethodname + METHOD_NOT_FOUND, e);
} catch (final IllegalArgumentException e) {
throw new CCException.Error(PROBLEM_TO_ACCESS+classname+GenericConstants.HASH_DIESE+ amethodname + METHOD_ILLEGAL_ARGUMENTS+String.valueOf(parameters)+GenericConstants.CLOSING_ROUND_BRACKET, e);
} catch (final IllegalAccessException e) {
throw new CCException.Error(PROBLEM_TO_ACCESS+classname+GenericConstants.HASH_DIESE+ amethodname + METHOD_ACCESS_RESTRICTION, e);
} catch (final InvocationTargetException e) {
throw new CCException.Error(PROBLEM_TO_ACCESS+classname+GenericConstants.HASH_DIESE+ amethodname + METHOD_INVOCATION_ISSUE, e);
}
return res;
}
假设您从同一个类中的一个静态方法调用一个静态方法。为此,您可以对以下代码进行示例。
class MainClass
{
public static int foo()
{
return 123;
}
public static void main(String[] args)
{
Method method = MainClass.class.getMethod("foo");
int result = (int) method.invoke(null); // answer evaluates to 123
}
}
为了解释一下,因为我们在这里不打算执行真正的面向对象编程,因此避免创建不必要的对象,所以我们将利用class属性来调用getMethod()。
然后,我们将为invoke()方法传入null,因为我们没有对象来执行此操作。
最后,因为我们程序员,知道我们期待的是一个整数,那么 我们显式地将invoke()调用的返回值转换为一个整数。
现在您可能想知道:“用Java进行所有这些非面向对象的编程到底有什么意义?”
我的用例是用Java解决Project Euler问题。我有一个包含所有解决方案的Java源文件,我想传入命令行参数,以确定要运行哪个Project Euler问题。