查找包含特定外键(如employee_id)的所有表

SELECT DISTINCT TABLE_NAME 
FROM INFORMATION_SCHEMA.COLUMNS
WHERE COLUMN_NAME IN ('employee_id')
AND TABLE_SCHEMA='table_name';

对于表格:

SELECT 
  TABLE_NAME,COLUMN_NAME,CONSTRAINT_NAME, REFERENCED_TABLE_NAME,REFERENCED_COLUMN_NAME
FROM
  INFORMATION_SCHEMA.KEY_COLUMN_USAGE
WHERE
  REFERENCED_TABLE_SCHEMA = '<database>' AND
  REFERENCED_TABLE_NAME = '<table>';

对于列:

SELECT 
  TABLE_NAME,COLUMN_NAME,CONSTRAINT_NAME, REFERENCED_TABLE_NAME,REFERENCED_COLUMN_NAME
FROM
  INFORMATION_SCHEMA.KEY_COLUMN_USAGE
WHERE
  REFERENCED_TABLE_SCHEMA = '<database>' AND
  REFERENCED_TABLE_NAME = '<table>' AND
  REFERENCED_COLUMN_NAME = '<column>';

基本上，我们用where子句中的REFERENCED_COLUMN_NAME更改了REFERENCED_TABLE_NAME。

我提出的解决方案是脆弱的;它依赖于django的外键命名约定。

USE information_schema;
tee mysql_output
SELECT * FROM TABLE_CONSTRAINTS WHERE CONSTRAINT_TYPE = 'FOREIGN KEY' AND TABLE_SCHEMA = 'database_name';
notee

然后在壳层中，

grep 'refs_tablename_id' mysql_output

查找包含特定外键(如employee_id)的所有表

SELECT DISTINCT TABLE_NAME 
FROM INFORMATION_SCHEMA.COLUMNS
WHERE COLUMN_NAME IN ('employee_id')
AND TABLE_SCHEMA='table_name';

如果你使用InnoDB并定义了FK，你可以查询information_schema数据库，例如:

SELECT * FROM information_schema.TABLE_CONSTRAINTS 
WHERE information_schema.TABLE_CONSTRAINTS.CONSTRAINT_TYPE = 'FOREIGN KEY' 
AND information_schema.TABLE_CONSTRAINTS.TABLE_SCHEMA = 'myschema'
AND information_schema.TABLE_CONSTRAINTS.TABLE_NAME = 'mytable';

了解更新和删除行为通常是有帮助的，这是其他答案没有提供的。现在开始。

SELECT cu.table_name,
       cu.column_name,
       cu.constraint_name,
       cu.referenced_table_name,
       cu.referenced_column_name,
       IF(rc.update_rule = 'NO ACTION', 'RESTRICT', rc.update_rule) AS update_rule,-- See: https://stackoverflow.com/a/1498015/2742117
       IF(rc.delete_rule = 'NO ACTION', 'RESTRICT', rc.delete_rule) AS delete_rule -- See: https://stackoverflow.com/a/1498015/2742117
FROM information_schema.key_column_usage cu
INNER JOIN information_schema.referential_constraints rc ON rc.constraint_schema = cu.table_schema
AND rc.table_name = cu.table_name
AND rc.constraint_name = cu.constraint_name
WHERE cu.referenced_table_schema = '<your schema>'
  AND cu.referenced_table_name = '<your table>';