如果你想在ASP.net MVC环境下使用JQuery AJAX实现这个功能，请遵循以下步骤: (这是本线程提供的解决方案的总结)

假设"caller.com"(可以是任何网站)需要发布到"server.com"(一个ASP.net MVC应用程序)

On the "server.com" app's Web.config add the following section: <httpProtocol> <customHeaders> <add name="Access-Control-Allow-Origin" value="*" /> <add name="Access-Control-Allow-Headers" value="Content-Type" /> <add name="Access-Control-Allow-Methods" value="POST, GET, OPTIONS" /> </customHeaders> </httpProtocol> On the "server.com", we'll have the following action on the controller(called "Home") to which we will be posting: [HttpPost] public JsonResult Save() { //Handle the post data... return Json( new { IsSuccess = true }); } Then from the "caller.com", post data from a form(with the html id "formId") to "server.com" as follow: $.ajax({ type: "POST", url: "http://www.server.com/home/save", dataType: 'json', crossDomain: true, data: $(formId).serialize(), success: function (jsonResult) { //do what ever with the reply }, error: function (jqXHR, textStatus) { //handle error } });

如果您可以访问所有相关的服务器，请在另一个域请求的页面的回复标题中放入以下内容:

PHP:

header('Access-Control-Allow-Origin: *');

例如，在Drupal的xmlrpc.php代码中，你会这样做:

function xmlrpc_server_output($xml) {
    $xml = '<?xml version="1.0"?>'."\n". $xml;
    header('Connection: close');
    header('Content-Length: '. strlen($xml));
    header('Access-Control-Allow-Origin: *');
    header('Content-Type: application/x-www-form-urlencoded');
    header('Date: '. date('r'));
    // $xml = str_replace("\n", " ", $xml); 

    echo $xml;
    exit;
}

这可能会产生安全问题，您应该确保采取了适当的措施来验证请求。

应该可以用YQL自定义表+ JS XHR，看看: http://developer.yahoo.com/yql/guide/index.html

我用它来做一些客户端(js) html抓取，工作很好 (我有一个完整的音频播放器，搜索互联网/播放列表/歌词/最后调频信息，所有客户端js + YQL)

我知道这是一个老问题，但我想分享我的方法。我使用cURL作为代理，非常简单和一致。创建一个名为submit.php的php页面，并添加以下代码:

<?

function post($url, $data) {
$header = array("User-Agent: " . $_SERVER["HTTP_USER_AGENT"], "Content-Type: application/x-www-form-urlencoded");
$curl = curl_init();
curl_setopt($curl, CURLOPT_URL, $url);
curl_setopt($curl, CURLOPT_HTTPHEADER, $header);
curl_setopt($curl, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($curl, CURLOPT_POST, 1);
curl_setopt($curl, CURLOPT_POSTFIELDS, $data);
$response = curl_exec($curl);
curl_close($curl);
return $response;
}

$url = "your cross domain request here";
$data = $_SERVER["QUERY_STRING"];
echo(post($url, $data));

然后，在你的js(这里是jQuery):

$.ajax({
type: 'POST',
url: 'submit.php',
crossDomain: true,
data: '{"some":"json"}',
dataType: 'json',
success: function(responseData, textStatus, jqXHR) {
    var value = responseData.someKey;
},
error: function (responseData, textStatus, errorThrown) {
    alert('POST failed.');
}
});

我认为最好的方法是使用XMLHttpRequest(例如:jQuery中的$.ajax()， $.post())与跨起源资源共享polyfills之一https://github.com/Modernizr/Modernizr/wiki/HTML5-Cross-Browser-Polyfills#wiki-CORS

Create two hidden iframes (add "display: none;" to the css style). Make your second iframe point to something on your own domain. Create a hidden form, set its method to "post" with target = your first iframe, and optionally set enctype to "multipart/form-data" (I'm thinking you want to do POST because you want to send multipart data like pictures?) When ready, make the form submit() the POST. If you can get the other domain to return javascript that will do Cross-Domain Communication With Iframes (http://softwareas.com/cross-domain-communication-with-iframes) then you are in luck, and you can capture the response as well.

当然，如果您想使用您的服务器作为代理，您可以避免所有这些。只需将表单提交到您自己的服务器，该服务器将把请求代理到另一个服务器(假设另一个服务器没有设置为注意到IP差异)，获得响应，并返回您想要的任何内容。