我将一些代码放在一起，以平抑和反平抑复杂/嵌套的JavaScript对象。它可以工作，但有点慢(触发“长脚本”警告)。
对于扁平的名称，我希望用“.”作为分隔符，用[INDEX]作为数组。
例子:
un-flattened | flattened
---------------------------
{foo:{bar:false}} => {"foo.bar":false}
{a:[{b:["c","d"]}]} => {"a[0].b[0]":"c","a[0].b[1]":"d"}
[1,[2,[3,4],5],6] => {"[0]":1,"[1].[0]":2,"[1].[1].[0]":3,"[1].[1].[1]":4,"[1].[2]":5,"[2]":6}
我创建了一个基准测试，用于模拟我的用例http://jsfiddle.net/WSzec/
获得一个嵌套对象
压平它
查看它，并可能修改它，而扁平
将其平放回原始的嵌套格式，然后运走
我想要更快的代码:为了澄清，代码完成JSFiddle基准测试(http://jsfiddle.net/WSzec/)显著更快(~20%+会很好)在IE 9+， FF 24+和Chrome 29+。
以下是相关JavaScript代码:当前最快速度:http://jsfiddle.net/WSzec/6/
var unflatten = function(data) {
"use strict";
if (Object(data) !== data || Array.isArray(data))
return data;
var result = {}, cur, prop, idx, last, temp;
for(var p in data) {
cur = result, prop = "", last = 0;
do {
idx = p.indexOf(".", last);
temp = p.substring(last, idx !== -1 ? idx : undefined);
cur = cur[prop] || (cur[prop] = (!isNaN(parseInt(temp)) ? [] : {}));
prop = temp;
last = idx + 1;
} while(idx >= 0);
cur[prop] = data[p];
}
return result[""];
}
var flatten = function(data) {
var result = {};
function recurse (cur, prop) {
if (Object(cur) !== cur) {
result[prop] = cur;
} else if (Array.isArray(cur)) {
for(var i=0, l=cur.length; i<l; i++)
recurse(cur[i], prop ? prop+"."+i : ""+i);
if (l == 0)
result[prop] = [];
} else {
var isEmpty = true;
for (var p in cur) {
isEmpty = false;
recurse(cur[p], prop ? prop+"."+p : p);
}
if (isEmpty)
result[prop] = {};
}
}
recurse(data, "");
return result;
}
编辑1修改了上面的@Bergi的实现，这是目前最快的。顺便说一句，使用“。”用indexOf代替正则表达式。exec”在FF中快了20%左右，但在Chrome中慢了20%;所以我将坚持使用正则表达式，因为它更简单(这里是我尝试使用indexOf来取代正则表达式http://jsfiddle.net/WSzec/2/)。
在@Bergi的想法的基础上，我设法创建了一个更快的非正则表达式版本(在FF快3倍，在Chrome快10%)。http://jsfiddle.net/WSzec/6/在这个(当前)实现中，密钥名称的规则很简单，密钥不能以整数开头或包含句点。
例子:
{"foo":{"bar":[0]}} => {"foo.bar.0":0}
EDIT 3添加@AaditMShah的内联路径解析方法(而不是String.split)有助于提高unflatten性能。我对整体性能的提升非常满意。
最新版本的jsfiddle和jsperf:
http://jsfiddle.net/WSzec/14/
http://jsperf.com/flatten-un-flatten/4
这是我的。它在谷歌应用程序脚本中在一个相当大的对象上运行<2ms。它使用破折号而不是点作为分隔符，并且它不像提问者的问题中那样专门处理数组，但这是我想要的。
function flatten (obj) {
var newObj = {};
for (var key in obj) {
if (typeof obj[key] === 'object' && obj[key] !== null) {
var temp = flatten(obj[key])
for (var key2 in temp) {
newObj[key+"-"+key2] = temp[key2];
}
} else {
newObj[key] = obj[key];
}
}
return newObj;
}
例子:
var test = {
a: 1,
b: 2,
c: {
c1: 3.1,
c2: 3.2
},
d: 4,
e: {
e1: 5.1,
e2: 5.2,
e3: {
e3a: 5.31,
e3b: 5.32
},
e4: 5.4
},
f: 6
}
Logger.log("start");
Logger.log(JSON.stringify(flatten(test),null,2));
Logger.log("done");
示例输出:
[17-02-08 13:21:05:245 CST] start
[17-02-08 13:21:05:246 CST] {
"a": 1,
"b": 2,
"c-c1": 3.1,
"c-c2": 3.2,
"d": 4,
"e-e1": 5.1,
"e-e2": 5.2,
"e-e3-e3a": 5.31,
"e-e3-e3b": 5.32,
"e-e4": 5.4,
"f": 6
}
[17-02-08 13:21:05:247 CST] done
下面是我在PowerShell中整理的flatten的递归解决方案:
#---helper function for ConvertTo-JhcUtilJsonTable
#
function getNodes {
param (
[Parameter(Mandatory)]
[System.Object]
$job,
[Parameter(Mandatory)]
[System.String]
$path
)
$t = $job.GetType()
$ct = 0
$h = @{}
if ($t.Name -eq 'PSCustomObject') {
foreach ($m in Get-Member -InputObject $job -MemberType NoteProperty) {
getNodes -job $job.($m.Name) -path ($path + '.' + $m.Name)
}
}
elseif ($t.Name -eq 'Object[]') {
foreach ($o in $job) {
getNodes -job $o -path ($path + "[$ct]")
$ct++
}
}
else {
$h[$path] = $job
$h
}
}
#---flattens a JSON document object into a key value table where keys are proper JSON paths corresponding to their value
#
function ConvertTo-JhcUtilJsonTable {
param (
[Parameter(Mandatory = $true, ValueFromPipeline = $true)]
[System.Object[]]
$jsonObj
)
begin {
$rootNode = 'root'
}
process {
foreach ($o in $jsonObj) {
$table = getNodes -job $o -path $rootNode
# $h = @{}
$a = @()
$pat = '^' + $rootNode
foreach ($i in $table) {
foreach ($k in $i.keys) {
# $h[$k -replace $pat, ''] = $i[$k]
$a += New-Object -TypeName psobject -Property @{'Key' = $($k -replace $pat, ''); 'Value' = $i[$k]}
# $h[$k -replace $pat, ''] = $i[$k]
}
}
# $h
$a
}
}
end{}
}
例子:
'{"name": "John","Address": {"house": "1234", "Street": "Boogie Ave"}, "pets": [{"Type": "Dog", "Age": 4, "Toys": ["rubberBall", "rope"]},{"Type": "Cat", "Age": 7, "Toys": ["catNip"]}]}' | ConvertFrom-Json | ConvertTo-JhcUtilJsonTable
Key Value
--- -----
.Address.house 1234
.Address.Street Boogie Ave
.name John
.pets[0].Age 4
.pets[0].Toys[0] rubberBall
.pets[0].Toys[1] rope
.pets[0].Type Dog
.pets[1].Age 7
.pets[1].Toys[0] catNip
.pets[1].Type Cat
这是我的。它在谷歌应用程序脚本中在一个相当大的对象上运行<2ms。它使用破折号而不是点作为分隔符，并且它不像提问者的问题中那样专门处理数组，但这是我想要的。
function flatten (obj) {
var newObj = {};
for (var key in obj) {
if (typeof obj[key] === 'object' && obj[key] !== null) {
var temp = flatten(obj[key])
for (var key2 in temp) {
newObj[key+"-"+key2] = temp[key2];
}
} else {
newObj[key] = obj[key];
}
}
return newObj;
}
例子:
var test = {
a: 1,
b: 2,
c: {
c1: 3.1,
c2: 3.2
},
d: 4,
e: {
e1: 5.1,
e2: 5.2,
e3: {
e3a: 5.31,
e3b: 5.32
},
e4: 5.4
},
f: 6
}
Logger.log("start");
Logger.log(JSON.stringify(flatten(test),null,2));
Logger.log("done");
示例输出:
[17-02-08 13:21:05:245 CST] start
[17-02-08 13:21:05:246 CST] {
"a": 1,
"b": 2,
"c-c1": 3.1,
"c-c2": 3.2,
"d": 4,
"e-e1": 5.1,
"e-e2": 5.2,
"e-e3-e3a": 5.31,
"e-e3-e3b": 5.32,
"e-e4": 5.4,
"f": 6
}
[17-02-08 13:21:05:247 CST] done
这段代码递归地展开JSON对象。
我在代码中包含了我的计时机制，它给了我1毫秒，但我不确定这是否是最准确的。
var new_json = [{
"name": "fatima",
"age": 25,
"neighbour": {
"name": "taqi",
"location": "end of the street",
"property": {
"built in": 1990,
"owned": false,
"years on market": [1990, 1998, 2002, 2013],
"year short listed": [], //means never
}
},
"town": "Mountain View",
"state": "CA"
},
{
"name": "qianru",
"age": 20,
"neighbour": {
"name": "joe",
"location": "opposite to the park",
"property": {
"built in": 2011,
"owned": true,
"years on market": [1996, 2011],
"year short listed": [], //means never
}
},
"town": "Pittsburgh",
"state": "PA"
}]
function flatten(json, flattened, str_key) {
for (var key in json) {
if (json.hasOwnProperty(key)) {
if (json[key] instanceof Object && json[key] != "") {
flatten(json[key], flattened, str_key + "." + key);
} else {
flattened[str_key + "." + key] = json[key];
}
}
}
}
var flattened = {};
console.time('flatten');
flatten(new_json, flattened, "");
console.timeEnd('flatten');
for (var key in flattened){
console.log(key + ": " + flattened[key]);
}
输出:
flatten: 1ms
.0.name: fatima
.0.age: 25
.0.neighbour.name: taqi
.0.neighbour.location: end of the street
.0.neighbour.property.built in: 1990
.0.neighbour.property.owned: false
.0.neighbour.property.years on market.0: 1990
.0.neighbour.property.years on market.1: 1998
.0.neighbour.property.years on market.2: 2002
.0.neighbour.property.years on market.3: 2013
.0.neighbour.property.year short listed:
.0.town: Mountain View
.0.state: CA
.1.name: qianru
.1.age: 20
.1.neighbour.name: joe
.1.neighbour.location: opposite to the park
.1.neighbour.property.built in: 2011
.1.neighbour.property.owned: true
.1.neighbour.property.years on market.0: 1996
.1.neighbour.property.years on market.1: 2011
.1.neighbour.property.year short listed:
.1.town: Pittsburgh
.1.state: PA
