我想为Firebase创建多个云功能，并从一个项目同时部署它们。我还想将每个函数分离到一个单独的文件中。目前，我可以创建多个函数，如果我把它们都放在index.js，如:
exports.foo = functions.database.ref('/foo').onWrite(event => {
...
});
exports.bar = functions.database.ref('/bar').onWrite(event => {
...
});
然而，我想把foo和酒吧在单独的文件。我试了一下:
/functions
|--index.js (blank)
|--foo.js
|--bar.js
|--package.json
foo.js在哪里
exports.foo = functions.database.ref('/foo').onWrite(event => {
...
});
bar.js是
exports.bar = functions.database.ref('/bar').onWrite(event => {
...
});
有没有一种方法可以在不把所有函数都放在index.js中的情况下实现这一点?
这种格式允许您的入口点查找其他函数文件，并自动导出每个文件中的每个函数。
主要入口脚本
找到functions文件夹中的所有.js文件，并导出从每个文件中导出的每个函数。
const fs = require('fs');
const path = require('path');
// Folder where all your individual Cloud Functions files are located.
const FUNCTIONS_FOLDER = './scFunctions';
fs.readdirSync(path.resolve(__dirname, FUNCTIONS_FOLDER)).forEach(file => { // list files in the folder.
if(file.endsWith('.js')) {
const fileBaseName = file.slice(0, -3); // Remove the '.js' extension
const thisFunction = require(`${FUNCTIONS_FOLDER}/${fileBaseName}`);
for(var i in thisFunction) {
exports[i] = thisFunction[i];
}
}
});
从一个文件导出多个函数
Const functions = require('firebase-functions');
Const query = functions.https。onRequest((req, res) => {
Let query = req.query.q;
res.send ({
“You searching For”:查询
})；
})；
const searchTest = functions.https。onRequest((req, res) => {
res.send ({
"searchTest": "你好!"
})；
})；
模块。出口= {
查询
searchTest
｝
HTTP可访问端点有适当的命名
✔功能:查询:http://localhost:5001/PROJECT-NAME/us-central1/query
function: helloWorlds: http://localhost:5001/PROJECT-NAME/us-central1/helloWorlds
✔功能:searchTest: http://localhost:5001/PROJECT-NAME/us-central1/searchTest
一个文件
如果你只有几个额外的文件(例如只有一个)，你可以使用:
Const your_functions = require('./path_to_your_functions');
For (var I in your_functions) {
export [i] = your_functions[i];
｝
为了保持简单(但能完成工作)，我个人是这样构造我的代码的。
布局
├── /src/
│ ├── index.ts
│ ├── foo.ts
│ ├── bar.ts
| ├── db.ts
└── package.json
foo.ts
import * as functions from 'firebase-functions';
export const fooFunction = functions.database()......... {
//do your function.
}
export const someOtherFunction = functions.database().......... {
// do the thing.
}
bar.ts
import * as functions from 'firebase-functions';
export const barFunction = functions.database()......... {
//do your function.
}
export const anotherFunction = functions.database().......... {
// do the thing.
}
db.ts
import * as admin from 'firebase-admin';
import * as functions from 'firebase-functions';
export const firestore = admin.firestore();
export const realtimeDb = admin.database();
index.ts
import * as admin from 'firebase-admin';
import * as functions from 'firebase-functions';
admin.initializeApp(functions.config().firebase);
// above codes only needed if you use firebase admin
export * from './foo';
export * from './bar';
适用于任何嵌套级别的目录。也只需遵循目录中的模式即可。
这要归功于@zaidfazil的答案
啊，Firebase负载节点模块的云函数通常，所以这是有效的
结构:
/functions
|--index.js
|--foo.js
|--bar.js
|--package.json
index.js:
const functions = require('firebase-functions');
const fooModule = require('./foo');
const barModule = require('./bar');
exports.foo = functions.database.ref('/foo').onWrite(fooModule.handler);
exports.bar = functions.database.ref('/bar').onWrite(barModule.handler);
foo.js:
exports.handler = (event) => {
...
};
bar.js:
exports.handler = (event) => {
...
};
为了保持简单(但能完成工作)，我个人是这样构造我的代码的。
布局
├── /src/
│ ├── index.ts
│ ├── foo.ts
│ ├── bar.ts
└── package.json
foo.ts
export const fooFunction = functions.database()......... {
//do your function.
}
export const someOtherFunction = functions.database().......... {
// do the thing.
}
bar.ts
export const barFunction = functions.database()......... {
//do your function.
}
export const anotherFunction = functions.database().......... {
// do the thing.
}
index.ts
import * as fooFunctions from './foo';
import * as barFunctions from './bar';
module.exports = {
...fooFunctions,
...barFunctions,
};
适用于任何嵌套级别的目录。也只需遵循目录中的模式即可。
Firebase文档现在已经更新了一个多文件代码组织的好指南:
文档>云功能>写功能>组织功能
总结:
foo.js
const functions = require('firebase-functions');
exports.foo = functions.https.onRequest((request, response) => {
// ...
});
bar.js
const functions = require('firebase-functions');
exports.bar = functions.https.onRequest((request, response) => {
// ...
});
index.js
const foo = require('./foo');
const bar = require('./bar');
exports.foo = foo.foo;
exports.bar = bar.bar;
