根据这个:http://developer.android.com/preview/features/runtime-permissions.html#coding一个应用程序可以检查运行时权限和请求权限,如果它还没有被授予。弹出如下对话框:
如果用户拒绝一个重要的权限,在我看来,应用程序应该显示一个解释为什么需要权限和什么影响拒绝。该对话框有两个选项:
重试(再次请求许可)
拒绝(应用程序将工作没有该许可)。
但是,如果用户选中“Never ask again”,则不应该显示带有解释的第二个对话框,特别是如果用户之前已经拒绝了一次。
现在的问题是:我的应用程序如何知道用户是否选中了Never ask again?IMO onRequestPermissionsResult(int requestCode, String[] permissions, int[] grantResults)没有给我这个信息。
第二个问题是:谷歌是否计划在权限对话框中包含一个自定义消息,以解释为什么应用程序需要权限?这样就不会出现第二个对话框,这肯定会带来更好的用户体验。
OnRequestPermissionResult-free和shouldshowrequestpermissionrationalfree方法:
public static void requestDangerousPermission(AppCompatActivity activity, String permission) {
if (hasPermission(activity, permission)) return;
requestPermission();
new Handler().postDelayed(() -> {
if (activity.getLifecycle().getCurrentState() == Lifecycle.State.RESUMED) {
Intent intent = new Intent(Settings.ACTION_APPLICATION_DETAILS_SETTINGS);
intent.setData(Uri.parse("package:" + context.getPackageName()));
context.startActivity(intent);
}
}, 250);
}
如果没有权限弹出,250ms后打开设备设置(如果选择了“Never ask again”,就是这种情况)。
相反,你会收到回调onRequestPermissionsResult()作为PERMISSION_DENIED当你再次请求权限时,而落在shouldShowRequestPermissionRationale()的错误条件下
来自Android文档:
When the system asks the user to grant a permission, the user has the option of telling the system not to ask for that permission again. In that case, any time an app uses requestPermissions() to ask for that permission again, the system immediately denies the request. The system calls your onRequestPermissionsResult() callback method and passes PERMISSION_DENIED, the same way it would if the user had explicitly rejected your request again. This means that when you call requestPermissions(), you cannot assume that any direct interaction with the user has taken place.
您可以通过检查权限原理是否显示在onRequestPermissionsResult()回调方法中来确定它。如果您发现任何权限集永远不会再次请求,您可以请求用户从设置中授予权限。
我的完整实现如下所示。它适用于单个或多个权限请求。使用以下或直接使用我的库。
@Override
public void onRequestPermissionsResult(int requestCode, @NonNull String[] permissions, @NonNull int[] grantResults) {
if(permissions.length == 0){
return;
}
boolean allPermissionsGranted = true;
if(grantResults.length>0){
for(int grantResult: grantResults){
if(grantResult != PackageManager.PERMISSION_GRANTED){
allPermissionsGranted = false;
break;
}
}
}
if(!allPermissionsGranted){
boolean somePermissionsForeverDenied = false;
for(String permission: permissions){
if(ActivityCompat.shouldShowRequestPermissionRationale(this, permission)){
//denied
Log.e("denied", permission);
}else{
if(ActivityCompat.checkSelfPermission(this, permission) == PackageManager.PERMISSION_GRANTED){
//allowed
Log.e("allowed", permission);
} else{
//set to never ask again
Log.e("set to never ask again", permission);
somePermissionsForeverDenied = true;
}
}
}
if(somePermissionsForeverDenied){
final AlertDialog.Builder alertDialogBuilder = new AlertDialog.Builder(this);
alertDialogBuilder.setTitle("Permissions Required")
.setMessage("You have forcefully denied some of the required permissions " +
"for this action. Please open settings, go to permissions and allow them.")
.setPositiveButton("Settings", new DialogInterface.OnClickListener() {
@Override
public void onClick(DialogInterface dialog, int which) {
Intent intent = new Intent(Settings.ACTION_APPLICATION_DETAILS_SETTINGS,
Uri.fromParts("package", getPackageName(), null));
intent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
startActivity(intent);
}
})
.setNegativeButton("Cancel", new DialogInterface.OnClickListener() {
@Override
public void onClick(DialogInterface dialog, int which) {
}
})
.setCancelable(false)
.create()
.show();
}
} else {
switch (requestCode) {
//act according to the request code used while requesting the permission(s).
}
}
}
请不要为这个解决办法向我扔石头。
这是可行的,但有点“俗气”。
当调用requestPermissions时,注册当前时间。
mAskedPermissionTime = System.currentTimeMillis();
然后在onRequestPermissionsResult中
如果结果不允许,请再次检查时间。
if (System.currentTimeMillis() - mAskedPermissionTime < 100)
由于用户不可能那么快地点击拒绝按钮,我们知道他选择了“永不再问”,因为回调是即时的。
使用风险自负。