如何通过代码而不是程序来截取手机屏幕的选定区域的截图?
当前回答
如果你想捕捉一个视图或布局,比如RelativeLayout或LinearLayout等。
只需使用代码:
LinearLayout llMain = (LinearLayout) findViewById(R.id.linearlayoutMain);
Bitmap bm = loadBitmapFromView(llMain);
现在你可以保存这个位图在设备存储:
FileOutputStream outStream = null;
File f=new File(Environment.getExternalStorageDirectory()+"/Screen Shots/");
f.mkdir();
String extStorageDirectory = f.toString();
File file = new File(extStorageDirectory, "my new screen shot");
pathOfImage = file.getAbsolutePath();
try {
outStream = new FileOutputStream(file);
bm.compress(Bitmap.CompressFormat.PNG, 100, outStream);
Toast.makeText(getApplicationContext(), "Saved at "+f.getAbsolutePath(), Toast.LENGTH_LONG).show();
addImageGallery(file);
//mail.setEnabled(true);
flag=true;
} catch (FileNotFoundException e) {e.printStackTrace();}
try {
outStream.flush();
outStream.close();
} catch (IOException e) {e.printStackTrace();}
其他回答
科特林
private fun screenShot() {
try {
val mPath: String = this.getExternalFilesDir(null).getAbsolutePath()
.toString() + "/temp" + ".png"
// create bitmap screenshot
val v1: View = getWindow().getDecorView().getRootView()
v1.isDrawingCacheEnabled = true
val bitmap = Bitmap.createBitmap(v1.drawingCache)
v1.isDrawingCacheEnabled = false
val imageFile = File(mPath)
val outputStream = FileOutputStream(imageFile)
val quality = 100
bitmap.compress(Bitmap.CompressFormat.PNG, quality, outputStream)
outputStream.flush()
outputStream.close()
//or you can share to test the method fast
val uriPath =
FileProvider.getUriForFile(this, getPackageName() + ".sharing.provider", imageFile)
val intent = Intent(Intent.ACTION_SEND)
intent.type = "image/*"
intent.clipData = ClipData.newRawUri("", uriPath)
intent.addFlags(Intent.FLAG_GRANT_READ_URI_PERMISSION or Intent.FLAG_GRANT_WRITE_URI_PERMISSION)
intent.putExtra(Intent.EXTRA_STREAM, uriPath)
startActivity(Intent.createChooser(intent, "Sharing to..."))
} catch (e: Throwable) {
e.printStackTrace()
}
}
Java
private void screenShot() {
try {
String mPath = this.getExternalFilesDir(null).getAbsolutePath().toString() + "/temp" + ".png";
// create bitmap screenshot
View v1 = getWindow().getDecorView().getRootView();
v1.setDrawingCacheEnabled(true);
Bitmap bitmap = Bitmap.createBitmap(v1.getDrawingCache());
v1.setDrawingCacheEnabled(false);
File imageFile = new File(mPath);
FileOutputStream outputStream = new FileOutputStream(imageFile);
int quality = 100;
bitmap.compress(Bitmap.CompressFormat.PNG, quality, outputStream);
outputStream.flush();
outputStream.close();
//or you can share to test the method fast
Uri uriPath = FileProvider.getUriForFile(this, getPackageName() + ".sharing.provider", imageFile);
Intent intent = new Intent(Intent.ACTION_SEND);
intent.setType("image/*");
intent.setClipData(ClipData.newRawUri("", uriPath));
intent.addFlags(Intent.FLAG_GRANT_READ_URI_PERMISSION | Intent.FLAG_GRANT_WRITE_URI_PERMISSION);
intent.putExtra(Intent.EXTRA_STREAM, uriPath);
startActivity(Intent.createChooser(intent, "Sharing to..."));
} catch (Throwable e) {
e.printStackTrace();
}
}
您可以尝试以下库: http://code.google.com/p/android-screenshot-library/ Android截图库(ASL)允许以编程方式从Android设备捕获屏幕截图,而不需要具有root访问权限。相反,ASL利用了在后台运行的本地服务,每次设备启动时通过Android调试桥(ADB)启动。
我已经创建了一个简单的库,从一个视图截图,要么给你一个位图对象,要么直接保存到任何你想要的路径
https://github.com/abdallahalaraby/Blink
你可以尝试这样做,
从布局或视图中获取位图缓存 首先你需要setDrawingCacheEnabled到一个布局(线性布局或相对布局,或视图)
然后
Bitmap bm = layout.getDrawingCache()
然后对位图做任何你想做的事情。要么将其转换为图像文件,要么将位图的uri发送到其他地方。
我的解决方案是:
public static Bitmap loadBitmapFromView(Context context, View v) {
DisplayMetrics dm = context.getResources().getDisplayMetrics();
v.measure(MeasureSpec.makeMeasureSpec(dm.widthPixels, MeasureSpec.EXACTLY),
MeasureSpec.makeMeasureSpec(dm.heightPixels, MeasureSpec.EXACTLY));
v.layout(0, 0, v.getMeasuredWidth(), v.getMeasuredHeight());
Bitmap returnedBitmap = Bitmap.createBitmap(v.getMeasuredWidth(),
v.getMeasuredHeight(), Bitmap.Config.ARGB_8888);
Canvas c = new Canvas(returnedBitmap);
v.draw(c);
return returnedBitmap;
}
and
public void takeScreen() {
Bitmap bitmap = ImageUtils.loadBitmapFromView(this, view); //get Bitmap from the view
String mPath = Environment.getExternalStorageDirectory() + File.separator + "screen_" + System.currentTimeMillis() + ".jpeg";
File imageFile = new File(mPath);
OutputStream fout = null;
try {
fout = new FileOutputStream(imageFile);
bitmap.compress(Bitmap.CompressFormat.JPEG, 90, fout);
fout.flush();
} catch (FileNotFoundException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
} finally {
fout.close();
}
}
图像保存在外部存储文件夹中。
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