如何通过代码而不是程序来截取手机屏幕的选定区域的截图?
当前回答
参数视图是根布局对象。
public static Bitmap screenShot(View view) {
Bitmap bitmap = null;
if (view.getWidth() > 0 && view.getHeight() > 0) {
bitmap = Bitmap.createBitmap(view.getWidth(),
view.getHeight(), Bitmap.Config.ARGB_8888);
Canvas canvas = new Canvas(bitmap);
view.draw(canvas);
}
return bitmap;
}
其他回答
如果你想捕捉一个视图的截图,使用View::drawToBitmap扩展函数:
val bitmap = myTargetView.drawToBitmap(/*Optional:*/ Bitmap.Config.ARGB_8888)
只需要确保使用-ktx版本的AndroidX核心库:
implementation("androidx.core:core-ktx:1.6.0")
我已经回答过一个类似的问题。
对于那些想要捕获GLSurfaceView的人,getDrawingCache或绘制到画布方法将不起作用。
在帧呈现之后,您必须读取OpenGL帧缓冲区的内容。这里有一个很好的答案
您可以尝试以下库: http://code.google.com/p/android-screenshot-library/ Android截图库(ASL)允许以编程方式从Android设备捕获屏幕截图,而不需要具有root访问权限。相反,ASL利用了在后台运行的本地服务,每次设备启动时通过Android调试桥(ADB)启动。
科特林
private fun screenShot() {
try {
val mPath: String = this.getExternalFilesDir(null).getAbsolutePath()
.toString() + "/temp" + ".png"
// create bitmap screenshot
val v1: View = getWindow().getDecorView().getRootView()
v1.isDrawingCacheEnabled = true
val bitmap = Bitmap.createBitmap(v1.drawingCache)
v1.isDrawingCacheEnabled = false
val imageFile = File(mPath)
val outputStream = FileOutputStream(imageFile)
val quality = 100
bitmap.compress(Bitmap.CompressFormat.PNG, quality, outputStream)
outputStream.flush()
outputStream.close()
//or you can share to test the method fast
val uriPath =
FileProvider.getUriForFile(this, getPackageName() + ".sharing.provider", imageFile)
val intent = Intent(Intent.ACTION_SEND)
intent.type = "image/*"
intent.clipData = ClipData.newRawUri("", uriPath)
intent.addFlags(Intent.FLAG_GRANT_READ_URI_PERMISSION or Intent.FLAG_GRANT_WRITE_URI_PERMISSION)
intent.putExtra(Intent.EXTRA_STREAM, uriPath)
startActivity(Intent.createChooser(intent, "Sharing to..."))
} catch (e: Throwable) {
e.printStackTrace()
}
}
Java
private void screenShot() {
try {
String mPath = this.getExternalFilesDir(null).getAbsolutePath().toString() + "/temp" + ".png";
// create bitmap screenshot
View v1 = getWindow().getDecorView().getRootView();
v1.setDrawingCacheEnabled(true);
Bitmap bitmap = Bitmap.createBitmap(v1.getDrawingCache());
v1.setDrawingCacheEnabled(false);
File imageFile = new File(mPath);
FileOutputStream outputStream = new FileOutputStream(imageFile);
int quality = 100;
bitmap.compress(Bitmap.CompressFormat.PNG, quality, outputStream);
outputStream.flush();
outputStream.close();
//or you can share to test the method fast
Uri uriPath = FileProvider.getUriForFile(this, getPackageName() + ".sharing.provider", imageFile);
Intent intent = new Intent(Intent.ACTION_SEND);
intent.setType("image/*");
intent.setClipData(ClipData.newRawUri("", uriPath));
intent.addFlags(Intent.FLAG_GRANT_READ_URI_PERMISSION | Intent.FLAG_GRANT_WRITE_URI_PERMISSION);
intent.putExtra(Intent.EXTRA_STREAM, uriPath);
startActivity(Intent.createChooser(intent, "Sharing to..."));
} catch (Throwable e) {
e.printStackTrace();
}
}
我的解决方案是:
public static Bitmap loadBitmapFromView(Context context, View v) {
DisplayMetrics dm = context.getResources().getDisplayMetrics();
v.measure(MeasureSpec.makeMeasureSpec(dm.widthPixels, MeasureSpec.EXACTLY),
MeasureSpec.makeMeasureSpec(dm.heightPixels, MeasureSpec.EXACTLY));
v.layout(0, 0, v.getMeasuredWidth(), v.getMeasuredHeight());
Bitmap returnedBitmap = Bitmap.createBitmap(v.getMeasuredWidth(),
v.getMeasuredHeight(), Bitmap.Config.ARGB_8888);
Canvas c = new Canvas(returnedBitmap);
v.draw(c);
return returnedBitmap;
}
and
public void takeScreen() {
Bitmap bitmap = ImageUtils.loadBitmapFromView(this, view); //get Bitmap from the view
String mPath = Environment.getExternalStorageDirectory() + File.separator + "screen_" + System.currentTimeMillis() + ".jpeg";
File imageFile = new File(mPath);
OutputStream fout = null;
try {
fout = new FileOutputStream(imageFile);
bitmap.compress(Bitmap.CompressFormat.JPEG, 90, fout);
fout.flush();
} catch (FileNotFoundException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
} finally {
fout.close();
}
}
图像保存在外部存储文件夹中。
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