我有一些HTML菜单,当用户单击这些菜单的头部时,我会完全显示这些菜单。当用户在菜单区域外单击时,我希望隐藏这些元素。

jQuery是否可以实现这样的功能?

$("#menuscontainer").clickOutsideThisElement(function() {
    // Hide the menus
});

当前回答

$(document).on('click.menu.hide', function(e){
  if ( !$(e.target).closest('#my_menu').length ) {
    $('#my_menu').find('ul').toggleClass('active', false);
  }
});

$(document).on('click.menu.show', '#my_menu li', function(e){
  $(this).find('ul').toggleClass('active');
});
div {
  float: left;
}

ul {
  padding: 0;
  position: relative;
}
ul li {
  padding: 5px 25px 5px 10px;
  border: 1px solid silver;
  cursor: pointer;
  list-style: none;
  margin-top: -1px;
  white-space: nowrap;
}
ul li ul:before {
  margin-right: -20px;
  position: absolute;
  top: -17px;
  right: 0;
  content: "\25BC";
}
ul li ul li {
  visibility: hidden;
  height: 0;
  padding-top: 0;
  padding-bottom: 0;
  border-width: 0 0 1px 0;
}
ul li ul li:last-child {
  border: none;
}
ul li ul.active:before {
  content: "\25B2";
}
ul li ul.active li {
  display: list-item;
  visibility: visible;
  height: inherit;
  padding: 5px 25px 5px 10px;
}
<script src="https://code.jquery.com/jquery-2.1.4.js"></script>
<div>
  <ul id="my_menu">
    <li>Menu 1
      <ul>
        <li>subMenu 1</li>
        <li>subMenu 2</li>
        <li>subMenu 3</li>
        <li>subMenu 4</li>
      </ul>
    </li>
    <li>Menu 2
      <ul>
        <li>subMenu 1</li>
        <li>subMenu 2</li>
        <li>subMenu 3</li>
        <li>subMenu 4</li>
      </ul>
    </li>
    <li>Menu 3</li>
    <li>Menu 4</li>
    <li>Menu 5</li>
    <li>Menu 6</li>
  </ul>
</div>

这里是jsbin版本http://jsbin.com/xopacadeni/edit?html,css,js,输出

其他回答

$("html").click(function(){
    if($('#info').css("opacity")>0.9) {
        $('#info').fadeOut('fast');
    }
});
    $('#menucontainer').click(function(e){
        e.stopPropagation();
     });

    $(document).on('click',  function(e){
        // code
    });

对于那些希望将一个简短的解决方案集成到JS代码中的人来说——一个没有JQuery的小型库:

用法:

// demo code
var htmlElem = document.getElementById('my-element')
function doSomething(){ console.log('outside click') }

// use the lib
var removeListener = new elemOutsideClickListener(htmlElem, doSomething);

// deregister on your wished event
$scope.$on('$destroy', removeListener);

下面是库:


function elemOutsideClickListener (element, outsideClickFunc, insideClickFunc) {
   function onClickOutside (e) {
      var targetEl = e.target; // clicked element
      do {
         // click inside
         if (targetEl === element) {
            if (insideClickFunc) insideClickFunc();
            return;

         // Go up the DOM
         } else {
            targetEl = targetEl.parentNode;
         }
      } while (targetEl);

      // click outside
      if (!targetEl && outsideClickFunc) outsideClickFunc();
   }

   window.addEventListener('click', onClickOutside);

   return function () {
      window.removeEventListener('click', onClickOutside);
   };
}

我从这里获取代码并将其放在函数中:https://www.w3docs.com/snippets/javascript/how-to-detect-a-click-outside-an-element.html

所有这些答案都解决了这个问题,但我想提供一个完全符合需要的moders es6解决方案。我只是希望让大家对这个可运行的演示感到满意。

window.clickOutSide=(元素,单击外部,单击内部)=>{document.addEventListener('click',(event)=>{if(!element.contains(event.target)){if(单击类型内部==“函数”){单击外侧();}}其他{if(单击类型内部==“函数”){单击内侧();}}});};window.clickOutSide(document.querySelector('.block'),()=>警报('clicked outside');.块{宽度:400px;高度:400px;背景色:红色;}<div class=“block”></div>

$('html').click(function(){//隐藏菜单(如果可见)});$('#menucontainer').click(函数(事件){event.stopPropagation();});<script src=“https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js“></script><html><button id=“#menucontainer”>确定</button></html>