当通过lambda表达式传入时，是否有更好的方法来获得属性名?
这是我目前拥有的。
eg.
GetSortingInfo<User>(u => u.UserId);
它只在属性为字符串时才将其转换为成员表达式。因为不是所有的属性都是字符串，我必须使用object，但它会为那些返回一个unaryexpression。
public static RouteValueDictionary GetInfo<T>(this HtmlHelper html,
Expression<Func<T, object>> action) where T : class
{
var expression = GetMemberInfo(action);
string name = expression.Member.Name;
return GetInfo(html, name);
}
private static MemberExpression GetMemberInfo(Expression method)
{
LambdaExpression lambda = method as LambdaExpression;
if (lambda == null)
throw new ArgumentNullException("method");
MemberExpression memberExpr = null;
if (lambda.Body.NodeType == ExpressionType.Convert)
{
memberExpr =
((UnaryExpression)lambda.Body).Operand as MemberExpression;
}
else if (lambda.Body.NodeType == ExpressionType.MemberAccess)
{
memberExpr = lambda.Body as MemberExpression;
}
if (memberExpr == null)
throw new ArgumentException("method");
return memberExpr;
}
我正在使用一个扩展方法的前c# 6项目和名称()的目标c# 6。
public static class MiscExtentions
{
public static string NameOf<TModel, TProperty>(this object @object, Expression<Func<TModel, TProperty>> propertyExpression)
{
var expression = propertyExpression.Body as MemberExpression;
if (expression == null)
{
throw new ArgumentException("Expression is not a property.");
}
return expression.Member.Name;
}
}
我称之为:
public class MyClass
{
public int Property1 { get; set; }
public string Property2 { get; set; }
public int[] Property3 { get; set; }
public Subclass Property4 { get; set; }
public Subclass[] Property5 { get; set; }
}
public class Subclass
{
public int PropertyA { get; set; }
public string PropertyB { get; set; }
}
// result is Property1
this.NameOf((MyClass o) => o.Property1);
// result is Property2
this.NameOf((MyClass o) => o.Property2);
// result is Property3
this.NameOf((MyClass o) => o.Property3);
// result is Property4
this.NameOf((MyClass o) => o.Property4);
// result is PropertyB
this.NameOf((MyClass o) => o.Property4.PropertyB);
// result is Property5
this.NameOf((MyClass o) => o.Property5);
它可以很好地处理字段和属性。
这是卡梅隆提出的方法的更新。第一个参数不是必需的。
public PropertyInfo GetPropertyInfo<TSource, TProperty>(
Expression<Func<TSource, TProperty>> propertyLambda)
{
Type type = typeof(TSource);
MemberExpression member = propertyLambda.Body as MemberExpression;
if (member == null)
throw new ArgumentException(string.Format(
"Expression '{0}' refers to a method, not a property.",
propertyLambda.ToString()));
PropertyInfo propInfo = member.Member as PropertyInfo;
if (propInfo == null)
throw new ArgumentException(string.Format(
"Expression '{0}' refers to a field, not a property.",
propertyLambda.ToString()));
if (type != propInfo.ReflectedType &&
!type.IsSubclassOf(propInfo.ReflectedType))
throw new ArgumentException(string.Format(
"Expresion '{0}' refers to a property that is not from type {1}.",
propertyLambda.ToString(),
type));
return propInfo;
}
您可以执行以下操作:
var propertyInfo = GetPropertyInfo<SomeType>(u => u.UserID);
var propertyInfo = GetPropertyInfo((SomeType u) => u.UserID);
扩展方法:
public static PropertyInfo GetPropertyInfo<TSource, TProperty>(this TSource source,
Expression<Func<TSource, TProperty>> propertyLambda) where TSource : class
{
return GetPropertyInfo(propertyLambda);
}
public static string NameOfProperty<TSource, TProperty>(this TSource source,
Expression<Func<TSource, TProperty>> propertyLambda) where TSource : class
{
PropertyInfo prodInfo = GetPropertyInfo(propertyLambda);
return prodInfo.Name;
}
您可以:
SomeType someInstance = null;
string propName = someInstance.NameOfProperty(i => i.Length);
PropertyInfo propInfo = someInstance.GetPropertyInfo(i => i.Length);
这是一个通用的实现，用于获取struct/class/interface/delegate/array的字段/属性/索引器/方法/扩展方法/委托的字符串名称。我已经测试了静态/实例和非泛型/泛型变体的组合。
//involves recursion
public static string GetMemberName(this LambdaExpression memberSelector)
{
Func<Expression, string> nameSelector = null; //recursive func
nameSelector = e => //or move the entire thing to a separate recursive method
{
switch (e.NodeType)
{
case ExpressionType.Parameter:
return ((ParameterExpression)e).Name;
case ExpressionType.MemberAccess:
return ((MemberExpression)e).Member.Name;
case ExpressionType.Call:
return ((MethodCallExpression)e).Method.Name;
case ExpressionType.Convert:
case ExpressionType.ConvertChecked:
return nameSelector(((UnaryExpression)e).Operand);
case ExpressionType.Invoke:
return nameSelector(((InvocationExpression)e).Expression);
case ExpressionType.ArrayLength:
return "Length";
default:
throw new Exception("not a proper member selector");
}
};
return nameSelector(memberSelector.Body);
}
这个东西也可以写在一个简单的while循环中:
//iteration based
public static string GetMemberName(this LambdaExpression memberSelector)
{
var currentExpression = memberSelector.Body;
while (true)
{
switch (currentExpression.NodeType)
{
case ExpressionType.Parameter:
return ((ParameterExpression)currentExpression).Name;
case ExpressionType.MemberAccess:
return ((MemberExpression)currentExpression).Member.Name;
case ExpressionType.Call:
return ((MethodCallExpression)currentExpression).Method.Name;
case ExpressionType.Convert:
case ExpressionType.ConvertChecked:
currentExpression = ((UnaryExpression)currentExpression).Operand;
break;
case ExpressionType.Invoke:
currentExpression = ((InvocationExpression)currentExpression).Expression;
break;
case ExpressionType.ArrayLength:
return "Length";
default:
throw new Exception("not a proper member selector");
}
}
}
我喜欢递归方法，尽管第二种方法可能更容易阅读。我们可以这样称呼它:
someExpr = x => x.Property.ExtensionMethod()[0]; //or
someExpr = x => Static.Method().Field; //or
someExpr = x => VoidMethod(); //or
someExpr = () => localVariable; //or
someExpr = x => x; //or
someExpr = x => (Type)x; //or
someExpr = () => Array[0].Delegate(null); //etc
string name = someExpr.GetMemberName();
打印最后一个成员。
注意:
对于像a.b.c.这样的链式表达式，将返回“C”。
这并不适用于const，数组索引器或枚举(不可能涵盖所有情况)。
当涉及到Array.Length时，有一个边缘情况。虽然'Length'被公开为属性，但您不能在任何前面提出的解决方案中使用它。
using Contract = System.Diagnostics.Contracts.Contract;
using Exprs = System.Linq.Expressions;
static string PropertyNameFromMemberExpr(Exprs.MemberExpression expr)
{
return expr.Member.Name;
}
static string PropertyNameFromUnaryExpr(Exprs.UnaryExpression expr)
{
if (expr.NodeType == Exprs.ExpressionType.ArrayLength)
return "Length";
var mem_expr = expr.Operand as Exprs.MemberExpression;
return PropertyNameFromMemberExpr(mem_expr);
}
static string PropertyNameFromLambdaExpr(Exprs.LambdaExpression expr)
{
if (expr.Body is Exprs.MemberExpression) return PropertyNameFromMemberExpr(expr.Body as Exprs.MemberExpression);
else if (expr.Body is Exprs.UnaryExpression) return PropertyNameFromUnaryExpr(expr.Body as Exprs.UnaryExpression);
throw new NotSupportedException();
}
public static string PropertyNameFromExpr<TProp>(Exprs.Expression<Func<TProp>> expr)
{
Contract.Requires<ArgumentNullException>(expr != null);
Contract.Requires<ArgumentException>(expr.Body is Exprs.MemberExpression || expr.Body is Exprs.UnaryExpression);
return PropertyNameFromLambdaExpr(expr);
}
public static string PropertyNameFromExpr<T, TProp>(Exprs.Expression<Func<T, TProp>> expr)
{
Contract.Requires<ArgumentNullException>(expr != null);
Contract.Requires<ArgumentException>(expr.Body is Exprs.MemberExpression || expr.Body is Exprs.UnaryExpression);
return PropertyNameFromLambdaExpr(expr);
}
现在看用法示例:
int[] someArray = new int[1];
Console.WriteLine(PropertyNameFromExpr( () => someArray.Length ));
如果PropertyNameFromUnaryExpr没有检查ArrayLength， "someArray"将被打印到控制台(编译器似乎生成了对支持Length字段的直接访问，作为优化，甚至在调试中，因此是特殊情况)。
