你可以使用Array.prototype.filter方法:

var newArray = homes.filter(function (el) {
  return el.price <= 1000 &&
         el.sqft >= 500 &&
         el.num_of_beds >=2 &&
         el.num_of_baths >= 2.5;
});

生活例子:

var obj = { 'homes': [{ "home_id": "1", "price": "925", "sqft": "1100", "num_of_beds": "2", "num_of_baths": "2.0", }, { "home_id": "2", "price": "1425", "sqft": "1900", "num_of_beds": "4", "num_of_baths": "2.5", }, // ... (more homes) ... ] }; // (Note that because `price` and such are given as strings in your object, // the below relies on the fact that <= and >= with a string and number // will coerce the string to a number before comparing.) var newArray = obj.homes.filter(function (el) { return el.price <= 1000 && el.sqft >= 500 && el.num_of_beds >= 2 && el.num_of_baths >= 1.5; // Changed this so a home would match }); console.log(newArray);

该方法是新的ECMAScript第5版标准的一部分，可以在几乎所有现代浏览器中找到。

对于IE，为了兼容性，你可以包含以下方法:

if (!Array.prototype.filter) {
  Array.prototype.filter = function(fun /*, thisp*/) {
    var len = this.length >>> 0;
    if (typeof fun != "function")
      throw new TypeError();

    var res = [];
    var thisp = arguments[1];
    for (var i = 0; i < len; i++) {
      if (i in this) {
        var val = this[i];
        if (fun.call(thisp, val, i, this))
          res.push(val);
      }
    }
    return res;
  };
}

const state.contactList = [{
    name: 'jane',
    email: 'jane@gmail.com'
  },{},{},...]

const fileredArray = state.contactsList.filter((contactItem) => {
  const regex = new RegExp(`${action.payload}`, 'gi');
  return contactItem.nameProperty.match(regex) || 
    contactItem.emailProperty.match(regex);
});


// contactList: all the contacts stored in state
// action.payload: whatever typed in search field

你可以很容易地做到这一点-可能有很多实现可供你选择，但这是我的基本想法(可能有一些格式，你可以用jQuery迭代一个对象，我只是现在想不起来):

function filter(collection, predicate)
{
    var result = new Array();
    var length = collection.length;

    for(var j = 0; j < length; j++)
    {
        if(predicate(collection[j]) == true)
        {
             result.push(collection[j]);
        }
    }

    return result;
}

然后你可以像这样调用这个函数:

filter(json, function(element)
{
    if(element.price <= 1000 && element.sqft >= 500 && element.num_of_beds > 2 && element.num_of_baths > 2.5)
        return true;

    return false;
});

这样，您可以根据定义的任何谓词调用筛选器，甚至可以使用更小的筛选器进行多次筛选。

用于搜索数组中对象的所有属性的高级代码

b=[]; 
yourArray.forEach(x => {
      Object.keys(x).forEach(i => {if (x[i].match('5') && !b.filter(y => y === x).length) { b.push(x) }})
    });
console.log(b)

你应该看看OGX。List，它内置了过滤方法，并扩展了标准javascript数组(以及分组、排序和查找)。下面是它为过滤器支持的操作符列表:

'eq' //Equal to
'eqjson' //For deep objects, JSON comparison, equal to
'neq' //Not equal to
'in' //Contains
'nin' //Doesn't contain
'lt' //Lesser than
'lte' //Lesser or equal to
'gt' //Greater than
'gte' //Greater or equal to
'btw' //Between, expects value to be array [_from_, _to_]
'substr' //Substring mode, equal to, expects value to be array [_from_, _to_, _niddle_]
'regex' //Regex match

你可以这样使用它

  let list = new OGX.List(your_array);
  list.addFilter('price', 'btw', 100, 500);
  list.addFilter('sqft', 'gte', 500);
  let filtered_list = list.filter();

或者这样

  let list = new OGX.List(your_array);
  let filtered_list = list.get({price:{btw:[100,500]}, sqft:{gte:500}});

或者作为一行

   let filtered_list = new OGX.List(your_array).get({price:{btw:[100,500]}, sqft:{gte:500}});

我更喜欢下划线框架。它提出了许多有用的对象操作。 你的任务:

var newArray = homes.filter(
    price <= 1000 & 
    sqft >= 500 &
    num_of_beds >=2 & 
    num_of_baths >= 2.5);

可以像这样覆盖:

var newArray = _.filter (homes, function(home) {
    return home.price<=1000 && sqft>=500 && num_of_beds>=2 && num_of_baths>=2.5;
});

希望对大家有用!