使用过滤器

var json = { homes: [{ "home_id": "1", "price": "925", "sqft": "1100", "num_of_beds": "2", "num_of_baths": "2.0", }, { "home_id": "2", "price": "1425", "sqft": "1900", "num_of_beds": "4", "num_of_baths": "2.5", }, ] } let filter = json.homes.filter(d => d.price >= 1000 & d.sqft >= 500 & d.num_of_beds >=2 & d.num_of_baths >= 2.5 ) console.log(filter)

const y = 'search text';
const a = [{key: "x", "val: "y"},  {key: "d", "val: "z"}]
const data = a.filter(res => {
        return(JSON.stringify(res).toLocaleLowerCase()).match(y.toLocaleLowerCase());
});

**

The simplest way to search a specific value in an Array of Object
--------------------------------------------------------------------

filter() -> uses a callback function the return value of which decides what will be returned in the filtered array. If the return value is true, the item is included in the resultant array.

includes() -> searches for something in an array of items using == equality
**

       const words = [{id:1,name:"tim"},{id:2,name:"morgon"}]
        
          function searchHandler(enteredString){
          const formatedString = enteredString.toLowerCase();
          const result = words.filter(data=> data?.name?.includes(formatedString));
          console.log(result);
    }

这里是工作提琴，在IE8使用jquery MAP函数工作良好

http://jsfiddle.net/533135/Cj4j7/

json.HOMES = $.map(json.HOMES, function(val, key) {
    if (Number(val.price) <= 1000
            && Number(val.sqft) >= 500
            && Number(val.num_of_beds) >=2
            && Number(val.num_of_baths ) >= 2.5)
        return val;
});

你应该看看OGX。List，它内置了过滤方法，并扩展了标准javascript数组(以及分组、排序和查找)。下面是它为过滤器支持的操作符列表:

'eq' //Equal to
'eqjson' //For deep objects, JSON comparison, equal to
'neq' //Not equal to
'in' //Contains
'nin' //Doesn't contain
'lt' //Lesser than
'lte' //Lesser or equal to
'gt' //Greater than
'gte' //Greater or equal to
'btw' //Between, expects value to be array [_from_, _to_]
'substr' //Substring mode, equal to, expects value to be array [_from_, _to_, _niddle_]
'regex' //Regex match

你可以这样使用它

  let list = new OGX.List(your_array);
  list.addFilter('price', 'btw', 100, 500);
  list.addFilter('sqft', 'gte', 500);
  let filtered_list = list.filter();

或者这样

  let list = new OGX.List(your_array);
  let filtered_list = list.get({price:{btw:[100,500]}, sqft:{gte:500}});

或者作为一行

   let filtered_list = new OGX.List(your_array).get({price:{btw:[100,500]}, sqft:{gte:500}});

我更喜欢下划线框架。它提出了许多有用的对象操作。 你的任务:

var newArray = homes.filter(
    price <= 1000 & 
    sqft >= 500 &
    num_of_beds >=2 & 
    num_of_baths >= 2.5);

可以像这样覆盖:

var newArray = _.filter (homes, function(home) {
    return home.price<=1000 && sqft>=500 && num_of_beds>=2 && num_of_baths>=2.5;
});

希望对大家有用!