当我在chrome中运行我的页面时,我得到这个错误“uncaught syntaxerror unexpected token U”。在firefox中,我得到JSON。解析:意想不到的字符”。我从一个php文件返回json数据,返回的json字符串是有效的。我在http://jsonlint.com/上查过。任何帮助都将不胜感激。谢谢。

这是返回的JSON字符串

[
    ["1","Pan Africa Market","\"1521 1st Ave, Seattle, WA\"","47.608941","-122.340145","restaurant"],
    ["2","The Melting Pot","14 Mercer St, Seattle, WA","47.624562","-122.356442","restaurant"],
    ["3","Ipanema Grill","1225 1st Ave, Seattle, WA","47.606366","-122.337656","restaurant"],
    ["4","Sake House","230 1st Ave, Seattle, WA","47.612825","-122.34567","bar"],
    ["5","Crab Pot","1301 Alaskan Way, Seattle, WA","47.605961","-122.34036","restaurant"],
    ["6","Mexican Kitchen","2234 2nd Ave, Seattle,WA","47.613975","-122.345467","bar"],
    ["7","Wingdome","1416 E Olive Way, Seattle, WA","47.617215","-122.326584","bar"],
    ["8","Piroshky Piroshky","1908 Pike pl, Seattle, WA","47.610127","-122.342838","restaurant"]
]

当前回答

好吧,对于那些实际上在你的代码中任何地方都找不到错误的人,既不是“在本地存储中未定义也不是null”。简单地只是注释掉你的代码,并编写另一个实际删除本地存储项。在那之后,你可以注释或删除当前的代码,并通过简单地取消注释来重新设置之前的代码(如果你不删除t…如果你写过,你可以再写一遍:)

LocalStorage.setItem('Previous' , "removeprevious");  


LocalStorage.removeItem('Previous');   
 Console.log(LocalStorage.getItem('Previous'));

控制台将显示null,并且它..如果t不起作用,请重新设置代码!你有错误。

对不起我的英语!

其他回答

我得到这个错误,当我使用相同的变量json字符串和parsed json:

var json = '{"1":{"url":"somesite1","poster":"1.png","title":"site title"},"2":{"url":"somesite2","poster":"2.jpg","title":"site 2 title"}}'

function usingjson(){
    var json = JSON.parse(json);
}

我把函数改为:

function usingjson(){
    var j = JSON.parse(json);
}

现在这个错误消失了。

这种错误发生的最常见的情况是使用正在生成控件的模板,然后通过“覆盖”默认模板来更改id和/或name的生成方式

@Html.TextBoxFor(m => m, new {Name = ViewData["Name"], id = ViewData["UniqueId"]} )

然后忘记将ValidationMessageFor更改为

@Html.ValidationMessageFor(m => m, null, new { data_valmsg_for = ViewData["Name"] })    

希望这能为您节省一些时间。

该错误通常在将值赋给JSON时出现。Parse实际上是未定义的。 所以,我会检查试图解析这个的代码——很可能你不是在解析这里显示的实际字符串。

以防你不明白

例如,让我们说我有一个JSON字符串..还不是json对象或数组。

所以如果在javascript你解析字符串为

var body={
  "id": 1,
  "deleted_at": null,
  "open_order": {
    "id": 16,
    "status": "open"}

var jsonBody = JSON.parse(body.open_order); //HERE THE ERROR NOW APPEARS BECAUSE THE STRING IS NOT A JSON OBJECT YET!!!! 
//TODO SO
var jsonBody=JSON.parse(body)//PASS THE BODY FIRST THEN LATER USE THE jsonBody to get the open_order

var OpenOrder=jsonBody.open_order;

上面的回答很棒

JSON的参数。parse可能什么也不返回(即JSON的值)。解析未定义)!

它发生在我从xyz解析已编译的固体代码时。索尔文件。

import web3 from './web3';
import xyz from './build/xyz.json';

const i = new web3.eth.Contract(
  JSON.parse(xyz.interface),
  '0x99Fd6eFd4257645a34093E657f69150FEFf7CdF5'
);

export default i;

拼错了

JSON.parse(xyz.intereface)

什么也没回!