这是我的一点JS代码,这是需要的:

var secDiff = Math.abs(Math.round((utc_date-this.premiere_date)/1000));
this.years = this.calculateUnit(secDiff,(86400*365));
this.days = this.calculateUnit(secDiff-(this.years*(86400*365)),86400);
this.hours = this.calculateUnit((secDiff-(this.years*(86400*365))-(this.days*86400)),3600);
this.minutes = this.calculateUnit((secDiff-(this.years*(86400*365))-(this.days*86400)-(this.hours*3600)),60);
this.seconds = this.calculateUnit((secDiff-(this.years*(86400*365))-(this.days*86400)-(this.hours*3600)-(this.minutes*60)),1);

我想在“前”得到日期时间,但如果DST正在使用,那么日期是1小时。我不知道如何检查夏令时是否有效。

我怎样才能知道夏令时何时开始和结束?


当前回答

你很接近了,但是有点差。你永远不需要计算你自己的时间,因为它是你自己的时钟的结果。它可以检测您是否在您的位置使用日光节约时间,但不能检测由偏移量产生的远程位置:

newDateWithOffset = new Date(utc + (3600000*(offset)));

This will still be wrong and off an hour if they are in DST. You need for a remote time account if they are currently inside their DST or not and adjust accordingly. try calculating this and change your clock to - lets say 2/1/2015 and reset the clock back an hour as if outside DST. Then calculate for an offset for a place that should still be 2 hours behind. It will show an hour ahead of the two hour window. You would still need to account for the hour and adjust. I did it for NY and Denver and always go the incorrect (hour ahead) in Denver.

其他回答

这段代码使用了这样一个事实,即getTimezoneOffset在标准时间与日光节约时间(DST)期间返回更大的值。因此,它确定标准时间内的预期输出,并比较给定日期的输出是否相同(标准)或更少(DST)。

注意,getTimezoneOffset对于UTC以西的区域返回正数分钟,通常表示为负小时(因为它们“落后”UTC)。例如,洛杉矶是UTC-8h标准,UTC-7h夏令时。getTimezoneOffset在12月(冬季,标准时间)返回480(正480分钟),而不是-480。它返回东半球的负数(例如冬季悉尼的-600,尽管这是“超前”(UTC+10h)。

Date.prototype.stdTimezoneOffset = function () {
    var jan = new Date(this.getFullYear(), 0, 1);
    var jul = new Date(this.getFullYear(), 6, 1);
    return Math.max(jan.getTimezoneOffset(), jul.getTimezoneOffset());
}

Date.prototype.isDstObserved = function () {
    return this.getTimezoneOffset() < this.stdTimezoneOffset();
}

var today = new Date();
if (today.isDstObserved()) { 
    alert ("Daylight saving time!");
}

js库在它的time对象上提供了一个. isdst()方法。

moment#isDST检查当前时刻是否属于夏时制。

moment([2011, 2, 12]).isDST(); // false, March 12 2011 is not DST
moment([2011, 2, 14]).isDST(); // true, March 14 2011 is DST

你很接近了,但是有点差。你永远不需要计算你自己的时间,因为它是你自己的时钟的结果。它可以检测您是否在您的位置使用日光节约时间,但不能检测由偏移量产生的远程位置:

newDateWithOffset = new Date(utc + (3600000*(offset)));

This will still be wrong and off an hour if they are in DST. You need for a remote time account if they are currently inside their DST or not and adjust accordingly. try calculating this and change your clock to - lets say 2/1/2015 and reset the clock back an hour as if outside DST. Then calculate for an offset for a place that should still be 2 hours behind. It will show an hour ahead of the two hour window. You would still need to account for the hour and adjust. I did it for NY and Denver and always go the incorrect (hour ahead) in Denver.

使用Moment.js (https://momentjs.com/)

.isDST时刻()();如果日光节约被观察,将会给你。

还有辅助功能,为您计算相对时间。你不需要手动计算 例如moment("20200105", "YYYYMMDD").fromNow();

我发现使用Moment.js库和这里描述的一些概念(比较Jan和June)效果非常好。

这个简单的函数将返回用户所在的时区是否遵守日光节约时间:

function HasDST() {
    return moment([2017, 1, 1]).isDST() != moment([2017, 6, 1]).isDST();
}

检查它是否有效的一个简单方法(在Windows上)是将您的时区更改为非夏令时区域,例如亚利桑那州将返回false,而EST或PST将返回true。