enum PostType: Decodable {
init(from decoder: Decoder) throws {
// What do i put here?
}
case Image
enum CodingKeys: String, CodingKey {
case image
}
}
我要怎么做才能完成这个?
此外,让我们说我把情况改为这样:
case image(value: Int)
我如何使这符合解码?
这是我的完整代码(不工作)
let jsonData = """
{
"count": 4
}
""".data(using: .utf8)!
do {
let decoder = JSONDecoder()
let response = try decoder.decode(PostType.self, from: jsonData)
print(response)
} catch {
print(error)
}
}
}
enum PostType: Int, Codable {
case count = 4
}
此外,它将如何处理这样的枚举?
enum PostType: Decodable {
case count(number: Int)
}
这很简单,只需使用String或Int原始值,这些值是隐式分配的。
enum PostType: Int, Codable {
case image, blob
}
图像编码为0,blob编码为1
Or
enum PostType: String, Codable {
case image, blob
}
图像被编码为Image而blob被编码为blob
这是一个简单的例子如何使用它:
enum PostType : Int, Codable {
case count = 4
}
struct Post : Codable {
var type : PostType
}
let jsonString = "{\"type\": 4}"
let jsonData = Data(jsonString.utf8)
do {
let decoded = try JSONDecoder().decode(Post.self, from: jsonData)
print("decoded:", decoded.type)
} catch {
print(error)
}
更新
在iOS 13.3+和macOS 15.1+中,允许对片段(未包装在集合类型中的单个JSON值)进行解码
let jsonString = "4"
let jsonData = Data(jsonString.utf8)
do {
let decoded = try JSONDecoder().decode(PostType.self, from: jsonData)
print("decoded:", decoded) // -> decoded: count
} catch {
print(error)
}
在Swift 5.5+中,甚至可以在不需要任何额外代码的情况下对枚举进行关联值的en /decode。这些值被映射到一个字典,并且必须为每个关联值指定一个参数标签
enum Rotation: Codable {
case zAxis(angle: Double, speed: Int)
}
let jsonString = #"{"zAxis":{"angle":90,"speed":5}}"#
let jsonData = Data(jsonString.utf8)
do {
let decoded = try JSONDecoder().decode(Rotation.self, from: jsonData)
print("decoded:", decoded)
} catch {
print(error)
}
@proxpero响应的一个更简洁的变体是将解码器表述为:
public init(from decoder: Decoder) throws {
let values = try decoder.container(keyedBy: CodingKeys.self)
guard let key = values.allKeys.first else { throw err("No valid keys in: \(values)") }
func dec<T: Decodable>() throws -> T { return try values.decode(T.self, forKey: key) }
switch key {
case .count: self = try .count(dec())
case .title: self = try .title(dec())
}
}
func encode(to encoder: Encoder) throws {
var container = encoder.container(keyedBy: CodingKeys.self)
switch self {
case .count(let x): try container.encode(x, forKey: .count)
case .title(let x): try container.encode(x, forKey: .title)
}
}
这允许编译器详尽地验证这些情况,并且在编码值与键的期望值不匹配的情况下也不会抑制错误消息。
如果遇到未知的enum值,Swift会抛出一个. datacorurt错误。如果你的数据来自服务器,它可以在任何时候给你一个未知的枚举值(错误服务器端,在API版本中添加的新类型,你希望你的应用程序的前版本能优雅地处理这种情况,等等),你最好做好准备,并编码“防御性风格”来安全地解码你的枚举。
这里有一个关于如何使用或不使用相关值的示例
enum MediaType: Decodable {
case audio
case multipleChoice
case other
// case other(String) -> we could also parametrise the enum like that
init(from decoder: Decoder) throws {
let label = try decoder.singleValueContainer().decode(String.self)
switch label {
case "AUDIO": self = .audio
case "MULTIPLE_CHOICES": self = .multipleChoice
default: self = .other
// default: self = .other(label)
}
}
}
以及如何在封闭结构中使用它:
struct Question {
[...]
let type: MediaType
enum CodingKeys: String, CodingKey {
[...]
case type = "type"
}
extension Question: Decodable {
init(from decoder: Decoder) throws {
let container = try decoder.container(keyedBy: CodingKeys.self)
[...]
type = try container.decode(MediaType.self, forKey: .type)
}
}
实际上,上面的答案真的很好,但它们遗漏了许多人在持续开发客户端/服务器项目中需要的一些细节。我们开发一个应用程序,而我们的后端随着时间不断发展,这意味着一些枚举情况将改变这种发展。因此,我们需要一个枚举解码策略,能够解码包含未知情况的枚举数组。否则,解码包含数组的对象就会失败。
我所做的很简单:
enum Direction: String, Decodable {
case north, south, east, west
}
struct DirectionList {
let directions: [Direction]
}
extension DirectionList: Decodable {
public init(from decoder: Decoder) throws {
var container = try decoder.unkeyedContainer()
var directions: [Direction] = []
while !container.isAtEnd {
// Here we just decode the string from the JSON which always works as long as the array element is a string
let rawValue = try container.decode(String.self)
guard let direction = Direction(rawValue: rawValue) else {
// Unknown enum value found - ignore, print error to console or log error to analytics service so you'll always know that there are apps out which cannot decode enum cases!
continue
}
// Add all known enum cases to the list of directions
directions.append(direction)
}
self.directions = directions
}
}
奖励:隐藏实现>使其成为一个集合
隐藏实现细节总是一个好主意。为此,您只需要再编写一点代码。诀窍是使DirectionsList符合Collection,并使你的内部列表数组私有:
struct DirectionList {
typealias ArrayType = [Direction]
private let directions: ArrayType
}
extension DirectionList: Collection {
typealias Index = ArrayType.Index
typealias Element = ArrayType.Element
// The upper and lower bounds of the collection, used in iterations
var startIndex: Index { return directions.startIndex }
var endIndex: Index { return directions.endIndex }
// Required subscript, based on a dictionary index
subscript(index: Index) -> Element {
get { return directions[index] }
}
// Method that returns the next index when iterating
func index(after i: Index) -> Index {
return directions.index(after: i)
}
}
您可以在John Sundell的这篇博客文章中阅读更多关于遵循自定义集合的内容:https://medium.com/@johnsundell/ creating-customization - colls-in swift-a344e25d0bb0
这里有很多很好的方法,但我还没有看到一个讨论枚举有一个以上的值,尽管它可以从例子中推导出来——也许有人可以找到这个方法的用途:
import Foundation
enum Tup {
case frist(String, next: Int)
case second(Int, former: String)
enum TupType: String, Codable {
case first
case second
}
enum CodingKeys: String, CodingKey {
case type
case first
case firstNext
case second
case secondFormer
}
}
extension Tup: Codable {
init(from decoder: Decoder) throws {
let values = try decoder.container(keyedBy: CodingKeys.self)
let type = try values.decode(TupType.self, forKey: .type)
switch type {
case .first:
let str = try values.decode(String.self, forKey: .first)
let next = try values.decode(Int.self, forKey: .firstNext)
self = .frist(str, next: next)
case .second:
let int = try values.decode(Int.self, forKey: .second)
let former = try values.decode(String.self, forKey: .secondFormer)
self = .second(int, former: former)
}
}
func encode(to encoder: Encoder) throws {
var container = encoder.container(keyedBy: CodingKeys.self)
switch self {
case .frist(let str, next: let next):
try container.encode(TupType.first, forKey: .type)
try container.encode(str, forKey: .first)
try container.encode(next, forKey: .firstNext)
case .second(let int, former: let former):
try container.encode(TupType.second, forKey: .type)
try container.encode(int, forKey: .second)
try container.encode(former, forKey: .secondFormer)
}
}
}
let example1 = Tup.frist("123", next: 90)
do {
let encoded = try JSONEncoder().encode(example1)
print(encoded)
let decoded = try JSONDecoder().decode(Tup.self, from: encoded)
print("decoded 1 = \(decoded)")
}
catch {
print("errpr = \(error.localizedDescription)")
}
let example2 = Tup.second(10, former: "dantheman")
do {
let encoded = try JSONEncoder().encode(example2)
print(encoded)
let decoded = try JSONDecoder().decode(Tup.self, from: encoded)
print("decoded 2 = \(decoded)")
}
catch {
print("errpr = \(error.localizedDescription)")
}