如果你需要复杂的结果(嵌入)，创建你自己的结构:

class templateRequest
{
    public String[] registration_ids;
    public Data data;
    public class Data
    {
        public String message;
        public String tickerText;
        public String contentTitle;
        public Data(String message, String tickerText, string contentTitle)
        {
            this.message = message;
            this.tickerText = tickerText;
            this.contentTitle = contentTitle;
        }                
    };
}

然后通过调用获取JSON字符串

List<String> ids = new List<string>() { "id1", "id2" };
templateRequest request = new templeteRequest();
request.registration_ids = ids.ToArray();
request.data = new templateRequest.Data("Your message", "Your ticker", "Your content");

string json = new JavaScriptSerializer().Serialize(request);

结果是这样的:

json = "{\"registration_ids\":[\"id1\",\"id2\"],\"data\":{\"message\":\"Your message\",\"tickerText\":\"Your ticket\",\"contentTitle\":\"Your content\"}}"

希望能有所帮助!

如果你想避免创建一个类和创建JSON，那么创建一个动态对象和序列化对象。

            dynamic data = new ExpandoObject();
            data.name = "kushal";
            data.isActive = true;

            // convert to JSON
            string json = Newtonsoft.Json.JsonConvert.SerializeObject(data);

读取JSON并像这样反序列化:

            // convert back to Object
            dynamic output = Newtonsoft.Json.JsonConvert.DeserializeObject(json);

            // read a particular value:
            output.name.Value

ExpandoObject来自System。动态名称空间。

我发现您根本不需要序列化器。如果将对象作为List返回。 让我举个例子。

在asmx中，我们使用传递的变量获取数据

// return data
[WebMethod(CacheDuration = 180)]
public List<latlon> GetData(int id) 
{
    var data = from p in db.property 
               where p.id == id 
               select new latlon
               {
                   lat = p.lat,
                   lon = p.lon

               };
    return data.ToList();
}

public class latlon
{
    public string lat { get; set; }
    public string lon { get; set; }
}

然后使用jquery访问服务，传递该变量。

// get latlon
function getlatlon(propertyid) {
var mydata;

$.ajax({
    url: "getData.asmx/GetLatLon",
    type: "POST",
    data: "{'id': '" + propertyid + "'}",
    async: false,
    contentType: "application/json;",
    dataType: "json",
    success: function (data, textStatus, jqXHR) { //
        mydata = data;
    },
    error: function (xmlHttpRequest, textStatus, errorThrown) {
        console.log(xmlHttpRequest.responseText);
        console.log(textStatus);
        console.log(errorThrown);
    }
});
return mydata;
}

// call the function with your data
latlondata = getlatlon(id);

我们得到了答案。

{"d":[{"__type":"MapData+latlon","lat":"40.7031420","lon":"-80.6047970}]}

如果您试图创建一个web服务，通过JSON向web页面提供数据，请考虑使用ASP。. NET Ajax工具包:

http://www.asp.net/learn/ajax/tutorial-05-cs.aspx

它会自动将你通过webservice服务的对象转换为json，并创建你可以用来连接到它的代理类。

如果你需要复杂的结果(嵌入)，创建你自己的结构:

class templateRequest
{
    public String[] registration_ids;
    public Data data;
    public class Data
    {
        public String message;
        public String tickerText;
        public String contentTitle;
        public Data(String message, String tickerText, string contentTitle)
        {
            this.message = message;
            this.tickerText = tickerText;
            this.contentTitle = contentTitle;
        }                
    };
}

然后通过调用获取JSON字符串

List<String> ids = new List<string>() { "id1", "id2" };
templateRequest request = new templeteRequest();
request.registration_ids = ids.ToArray();
request.data = new templateRequest.Data("Your message", "Your ticker", "Your content");

string json = new JavaScriptSerializer().Serialize(request);

结果是这样的:

json = "{\"registration_ids\":[\"id1\",\"id2\"],\"data\":{\"message\":\"Your message\",\"tickerText\":\"Your ticket\",\"contentTitle\":\"Your content\"}}"

希望能有所帮助!

包括:

使用System.Text.Json;

然后像这样序列化你的object_to_serialize: JsonSerializer.Serialize (object_to_serialize)