我正在开发一个应用程序在Android操作系统。我不知道如何检查位置服务是否启用。
我需要一个方法,如果它们被启用,返回“true”,如果没有“false”(所以在最后一种情况下,我可以显示一个对话框来启用它们)。
我正在开发一个应用程序在Android操作系统。我不知道如何检查位置服务是否启用。
我需要一个方法,如果它们被启用,返回“true”,如果没有“false”(所以在最后一种情况下,我可以显示一个对话框来启用它们)。
当前回答
到2020年
最近,最好和最短的方法是
@SuppressWarnings("deprecation")
public static Boolean isLocationEnabled(Context context) {
if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.P) {
// This is a new method provided in API 28
LocationManager lm = (LocationManager) context.getSystemService(Context.LOCATION_SERVICE);
return lm.isLocationEnabled();
} else {
// This was deprecated in API 28
int mode = Settings.Secure.getInt(context.getContentResolver(), Settings.Secure.LOCATION_MODE,
Settings.Secure.LOCATION_MODE_OFF);
return (mode != Settings.Secure.LOCATION_MODE_OFF);
}
}
其他回答
You can also use extension function.
------------------------------------
fun Context.isLocationEnabled(): Boolean{
val locationManager = getSystemService(Context.LOCATION_SERVICE) as LocationManager
return LocationManagerCompat.isLocationEnabled(locationManager)}
我使用第一个代码开始创建方法isLocationEnabled
private LocationManager locationManager ;
protected boolean isLocationEnabled(){
String le = Context.LOCATION_SERVICE;
locationManager = (LocationManager) getSystemService(le);
if(!locationManager.isProviderEnabled(LocationManager.NETWORK_PROVIDER)){
return false;
} else {
return true;
}
}
和我检查条件,如果true打开地图和false给意图ACTION_LOCATION_SOURCE_SETTINGS
if (isLocationEnabled()) {
SupportMapFragment mapFragment = (SupportMapFragment) getSupportFragmentManager()
.findFragmentById(R.id.map);
mapFragment.getMapAsync(this);
locationClient = getFusedLocationProviderClient(this);
locationClient.getLastLocation()
.addOnSuccessListener(new OnSuccessListener<Location>() {
@Override
public void onSuccess(Location location) {
// GPS location can be null if GPS is switched off
if (location != null) {
onLocationChanged(location);
Log.e("location", String.valueOf(location.getLongitude()));
}
}
})
.addOnFailureListener(new OnFailureListener() {
@Override
public void onFailure(@NonNull Exception e) {
Log.e("MapDemoActivity", e.toString());
e.printStackTrace();
}
});
startLocationUpdates();
}
else {
new AlertDialog.Builder(this)
.setTitle("Please activate location")
.setMessage("Click ok to goto settings else exit.")
.setPositiveButton(android.R.string.yes, new DialogInterface.OnClickListener() {
public void onClick(DialogInterface dialog, int which) {
Intent intent = new Intent(Settings.ACTION_LOCATION_SOURCE_SETTINGS);
startActivity(intent);
}
})
.setNegativeButton(android.R.string.no, new DialogInterface.OnClickListener() {
public void onClick(DialogInterface dialog, int which) {
System.exit(0);
}
})
.show();
}
是的,你可以检查以下是代码:
public boolean isGPSEnabled(Context mContext)
{
LocationManager lm = (LocationManager)
mContext.getSystemService(Context.LOCATION_SERVICE);
return lm.isProviderEnabled(LocationManager.GPS_PROVIDER);
}
在manifest文件中的权限下:
<uses-permission android:name="android.permission.ACCESS_FINE_LOCATION" />
private boolean isGpsEnabled()
{
LocationManager service = (LocationManager) getSystemService(LOCATION_SERVICE);
return service.isProviderEnabled(LocationManager.GPS_PROVIDER)&&service.isProviderEnabled(LocationManager.NETWORK_PROVIDER);
}
我使用这样的方式NETWORK_PROVIDER,但你可以添加和GPS。
LocationManager locationManager;
在onCreate中
isLocationEnabled();
if(!isLocationEnabled()) {
AlertDialog.Builder builder = new AlertDialog.Builder(MainActivity.this);
builder.setTitle(R.string.network_not_enabled)
.setMessage(R.string.open_location_settings)
.setPositiveButton(R.string.yes,
new DialogInterface.OnClickListener() {
public void onClick(DialogInterface dialog, int id) {
startActivity(new Intent(Settings.ACTION_LOCATION_SOURCE_SETTINGS));
}
})
.setNegativeButton(R.string.cancel,
new DialogInterface.OnClickListener() {
public void onClick(DialogInterface dialog, int id) {
dialog.cancel();
}
});
AlertDialog alert = builder.create();
alert.show();
}
检查方法
protected boolean isLocationEnabled(){
String le = Context.LOCATION_SERVICE;
locationManager = (LocationManager) getSystemService(le);
if(!locationManager.isProviderEnabled(LocationManager.NETWORK_PROVIDER)){
return false;
} else {
return true;
}
}