是否有一个命令来检索给定相对路径的绝对路径?
例如,我想要$line包含dir ./etc/中每个文件的绝对路径
find ./ -type f | while read line; do
echo $line
done
是否有一个命令来检索给定相对路径的绝对路径?
例如,我想要$line包含dir ./etc/中每个文件的绝对路径
find ./ -type f | while read line; do
echo $line
done
当前回答
更新之前的答案使用python 3
to_abs_path() {
python -c "import os; print (os.path.abspath('$1'))"
}
允许
to_abs_path "./../some_file.txt"
其他回答
这是来自所有其他解决方案的链式解决方案,例如,当realpath失败时,要么是因为没有安装它,要么是因为它带着错误代码退出,那么,将尝试下一个解决方案,直到它获得正确的路径。
#!/bin/bash
function getabsolutepath() {
local target;
local changedir;
local basedir;
local firstattempt;
target="${1}";
if [ "$target" == "." ];
then
printf "%s" "$(pwd)";
elif [ "$target" == ".." ];
then
printf "%s" "$(dirname "$(pwd)")";
else
changedir="$(dirname "${target}")" && basedir="$(basename "${target}")" && firstattempt="$(cd "${changedir}" && pwd)" && printf "%s/%s" "${firstattempt}" "${basedir}" && return 0;
firstattempt="$(readlink -f "${target}")" && printf "%s" "${firstattempt}" && return 0;
firstattempt="$(realpath "${target}")" && printf "%s" "${firstattempt}" && return 0;
# If everything fails... TRHOW PYTHON ON IT!!!
local fullpath;
local pythoninterpreter;
local pythonexecutables;
local pythonlocations;
pythoninterpreter="python";
declare -a pythonlocations=("/usr/bin" "/bin");
declare -a pythonexecutables=("python" "python2" "python3");
for path in "${pythonlocations[@]}";
do
for executable in "${pythonexecutables[@]}";
do
fullpath="${path}/${executable}";
if [[ -f "${fullpath}" ]];
then
# printf "Found ${fullpath}\\n";
pythoninterpreter="${fullpath}";
break;
fi;
done;
if [[ "${pythoninterpreter}" != "python" ]];
then
# printf "Breaking... ${pythoninterpreter}\\n"
break;
fi;
done;
firstattempt="$(${pythoninterpreter} -c "import os, sys; print( os.path.abspath( sys.argv[1] ) );" "${target}")" && printf "%s" "${firstattempt}" && return 0;
# printf "Error: Could not determine the absolute path!\\n";
return 1;
fi
}
printf "\\nResults:\\n%s\\nExit: %s\\n" "$(getabsolutepath "./asdfasdf/ asdfasdf")" "${?}"
你可以使用bash字符串替换任何相对路径$line:
line=$(echo ${line/#..\//`cd ..; pwd`\/})
line=$(echo ${line/#.\//`pwd`\/})
echo $line
基本的字符串前端替换遵循以下公式 ${/ #子字符串替换字符串} 在这里讨论得很好:https://www.tldp.org/LDP/abs/html/string-manipulation.html
当我们希望/是我们找到/替换的字符串的一部分时,\字符对/求反。
基于@EugenKonkov的回答和@HashChange的回答,我的回答结合了前者的简洁和对。和. .关于后者。我相信下面所有的选项仅仅依赖于基本的Shell命令语言POSIX标准。
使用dirname和basename,一个选项是:
absPathDirname()
{
[ -d "${1}" ] && set -- "${1}" || set -- "`dirname "${1}"`" "/`basename "${1}"`"
echo "`cd "${1}"; pwd`${2}";
}
不使用dirname或basename,另一个简单的选项是:
absPathMinusD()
{
[ -d "${1}" ] && set -- "${1}" || set -- "${1%${1##*/}}" "/${1##*/}"
echo "`cd "${1:-.}"; pwd`${2}";
}
我会推荐上面两个选择中的一个,其他的只是为了好玩…
Grep版本:
absPathGrep()
{
echo "`[ "${1##/*}" ] && echo "$1" | grep -Eo '^(.*/)?\.\.($|/)' | { read d && cd "$d"; echo "${PWD}/${1#$d}"; } || echo "$1"`"
}
作为一个有趣的“可以用shell有限的RegEx做什么”的例子:
absPathShellReplace()
{
E="${1##*/}"; D="${E#$E${E#.}}"; DD="${D#$D${D#..}}"
DIR="${1%$E}${E#$DD}"; FILE="${1#$DIR}"; SEP=${FILE:+/}
echo "`cd "${DIR:-.}"; pwd`${SEP#$DIR}$FILE"
}
如果你在Mac OS X上使用bash,它既没有realpath也没有readlink可以打印绝对路径,你可以选择编写自己的版本来打印它。 这是我的实现:
(纯bash)
abspath(){
local thePath
if [[ ! "$1" =~ ^/ ]];then
thePath="$PWD/$1"
else
thePath="$1"
fi
echo "$thePath"|(
IFS=/
read -a parr
declare -a outp
for i in "${parr[@]}";do
case "$i" in
''|.) continue ;;
..)
len=${#outp[@]}
if ((len==0));then
continue
else
unset outp[$((len-1))]
fi
;;
*)
len=${#outp[@]}
outp[$len]="$i"
;;
esac
done
echo /"${outp[*]}"
)
}
(用呆呆的)
abspath_gawk() {
if [[ -n "$1" ]];then
echo $1|gawk '{
if(substr($0,1,1) != "/"){
path = ENVIRON["PWD"]"/"$0
} else path = $0
split(path, a, "/")
n = asorti(a, b,"@ind_num_asc")
for(i in a){
if(a[i]=="" || a[i]=="."){
delete a[i]
}
}
n = asorti(a, b, "@ind_num_asc")
m = 0
while(m!=n){
m = n
for(i=1;i<=n;i++){
if(a[b[i]]==".."){
if(b[i-1] in a){
delete a[b[i-1]]
delete a[b[i]]
n = asorti(a, b, "@ind_num_asc")
break
} else exit 1
}
}
}
n = asorti(a, b, "@ind_num_asc")
if(n==0){
printf "/"
} else {
for(i=1;i<=n;i++){
printf "/"a[b[i]]
}
}
}'
fi
}
(纯BSD AWK)
#!/usr/bin/env awk -f
function abspath(path, i,j,n,a,b,back,out){
if(substr(path,1,1) != "/"){
path = ENVIRON["PWD"]"/"path
}
split(path, a, "/")
n = length(a)
for(i=1;i<=n;i++){
if(a[i]==""||a[i]=="."){
continue
}
a[++j]=a[i]
}
for(i=j+1;i<=n;i++){
delete a[i]
}
j=0
for(i=length(a);i>=1;i--){
if(back==0){
if(a[i]==".."){
back++
continue
} else {
b[++j]=a[i]
}
} else {
if(a[i]==".."){
back++
continue
} else {
back--
continue
}
}
}
if(length(b)==0){
return "/"
} else {
for(i=length(b);i>=1;i--){
out=out"/"b[i]
}
return out
}
}
BEGIN{
if(ARGC>1){
for(k=1;k<ARGC;k++){
print abspath(ARGV[k])
}
exit
}
}
{
print abspath($0)
}
例子:
$ abspath I/am/.//..//the/./god/../of///.././war
/Users/leon/I/the/war
realpath试试。
~ $ sudo apt-get install realpath # may already be installed
~ $ realpath .bashrc
/home/username/.bashrc
要避免扩展符号链接,请使用realpath -s。
答案来自“bash/fish命令打印文件的绝对路径”。